Question

A jar of 150 jelly beans contains 22 red jelly beans, 38

yellow, 20 green, 28 purple, 26 blue, and the rest are orange.

Let B = the event of getting a blue jelly bean

Let G = the event of getting a green jelly bean.

Let O = the event of getting an orange jelly bean.

Let P = the event of getting a purple jelly bean.

Let R = the event of getting a red jelly bean.

Let Y = the event of getting a yellow jelly bean.

Find P(G).

Short answer

The value of$P\left(G\right)is0.13.$

Step-by-step solution

Given Information

A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue and the rest are orange.

Concept Used

Probability is a measure that is associated with how certain we are of outcomes of a particular experiment The formula for calculating the probability is:

$\text{Probability}=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}$

For example, if we flip a coin two times, the sample space associated with this random experiment is $\{HH,HT,TH,TT\}$where T= tails and

H= heads.

Let's suppose A= getting one tail. There are two outcomes which favors the event A

localid="1648977556231" $$\begin{gathered} \{HT,TH\}\text{, so}P\left(A\right)=\frac{2}{4} \\ =0.5\text{.} \end{gathered}$$

Calculation

Now to find the probability of getting a green jelly bean, the favorable number of cases is 20 and total cases are 150 .

Therefore, the probability of getting a green jelly bean is:

$$\begin{gathered} P\left(G\right)=\frac{20}{150} \\ =\frac{2}{15} \\ =0.13 \end{gathered}$$