Question

$$\begin{gathered} \text{An article in the New England Journal of Medicine, reported about a study of smokers in California and Hawaii.} \\ \text{Inone part of the report, the self-reported ethnicity and smoking levels per day were given.} \\ \text{Ofthe people smoking at most ten cigarettes per day, there were}9,886\text{African Americans,}2,745\text{Native Hawaiians,} \\ 12,831\text{Latinos,}8,378\text{Japanese Americans, and}7,650\text{Whites. Of the people smoking}11to20\text{cigarettes per day, there were} \\ 6,514\text{African Americans,}3,062\text{Native Hawaiians,}4,932\text{Latinos,}10,680\text{Japanese Americans, and}9,877\text{Whites.} \\ \text{Ofthe people smoking}21to30\text{cigarettes per day, there were}1,671\text{African Americans,}1,419\text{Native Hawaiians,} \\ 1,406\text{Latinos,}4,715\text{Japanese Americans, and}6,062\text{Whites. Of the people smoking at least}31\text{cigarettes per day, there were} \\ 759\text{African Americans,}788\text{Native Hawaiians,}800\text{Latinos,}2,305\text{Japanese Americans, and}3,970\text{WhitesAn article in the New England Journal of Medicine,} \\ \text{reported about a study of smokers in California and Hawaii. In one part of the report, the self-reported ethnicity and smoking levels per day were given.} \\ \text{Ofthe people smoking at most ten cigarettes per day, there were}9,886\text{African Americans,}2,745\text{Native Hawaiians,}12,831\text{Latinos,} \\ 8,378\text{Japanese Americans, and}7,650\text{Whites. Of the people smoking}11to20\text{cigarettes per day, there were}6,514\text{African Americans,} \\ 3,062\text{Native Hawaiians,}4,932\text{Latinos,}10,680\text{Japanese Americans, and}9,877\text{Whites. Of the people smoking}21to30\text{cigarettes per day, there were} \\ 1,671\text{African Americans,}1,419\text{Native Hawaiians,}1,406\text{Latinos,}4,715\text{Japanese Americans, and}6,062\text{Whites. Of the people smoking at least} \\ 31\text{cigarettes per day, there were}759\text{African Americans,}788\text{Native Hawaiians,}800\text{Latinos,}2,305\text{Japanese Americans, and}3,970\text{Whites} \end{gathered}$$

Suppose that one person from the study is randomly selected. Find the probability that person smoked $11to20$ cigarettes per day

Short answer

The required solution is$P\left(thatapersonsmoked11to20cigarettesperday\right)=0.35$

Step-by-step solution

Given information

$\text{An article in the New England Journal of Medicine, reported about a study of smokers in California and Hawaii. In one part of the report, the self-reported ethnicity and smoking levels per day were given. Of the people smoking at most ten cigarettes per day, there were}9,886\text{African Americans,}2,745\text{Native Hawaiians,}12,831\text{Latinos,}8,378\text{Japanese Americans, and}7,650\text{Whites. Of the people smoking}11to20\text{cigarettes per day, there were}6,514\text{African Americans,}3,062\text{Native Hawaiians,}4,932\text{Latinos,}10,680\text{Japanese Americans, and}9,877\text{Whites. Of the people smoking}21to30\text{cigarettes per day, there were}1,671\text{African Americans,}1,419\text{Native Hawaiians,}1,406\text{Latinos,}4,715\text{Japanese Americans, and}6,062\text{Whites. Of the people smoking at least}31\text{cigarettes per day, there were}759\text{African Americans,}788\text{Native Hawaiians,}800\text{Latinos,2},305\text{Japanese Americans, and}3,970\text{Whites}$

Calculation

We known the table

Since there are $35065$persons are there who smokes $11to20$cigarettes per day and there are $100450$total no. of persons. So, by using normal method of probability in which to get the probability we divide no. of favorable outcomes by total no. of events.

$$\begin{gathered} P(thatapersonsmoked11to20cigarettesperday)=\frac{\text{No.of people whosmokes}11\text{to}20\text{cigarentesperday}}{\text{Total oo.of person}} \\ P(thatapersonsmoked11to20cigarettesperday)=\frac{35065}{100450}=0.35 \end{gathered}$$

So, Probability that a person smokes 11 to 20 cigarettes per day is $35065$divided by $100450$.

Therefore the required solution is$0.35.$

Final answer

The probability is$P\left(thatapersonsmoked11to20cigarettesperday\right)=0.35$.