Question

For a given line of best fit, you compute that $r=0.5204$using $n=9$data points, and the critical value is $0.666$. Can the line be used for prediction? Why or why not?

Short answer

Yes. The line can not be used for prediction because $r<criticalvalue$.

Step-by-step solution

Introduction

A critical value is the worth of the test measurement which characterizes the upper and lower limits of a certainty span, or which characterizes the edge of factual importance in a factual test.

Explanation

For a given line of best fit, you compute that $r=0.5204$using $n=10$data points, and the critical value is $0.666$.

Suppose you computed $r=0.5204$using $n=10$data points.

$df=n-2=9-2=7.$

The critical values associated with $df=7are-0.666and+0.666.$

If $r<$negative critical value or $r>$positive critical value, then $r$is significant.

Since $r=0.5204$ and $0.5204<0.666$, r is not significant and the line may not be used for prediction.