Question

For a given line of best fit, you computed that $r=0.6501$using $n=12$data points and the critical value is $0.576$. Can the line be used for prediction? Why or why not?

Short answer

Yes. the line can be used for the prediction because$r>criticalvalue$

Step-by-step solution

Given information

For a given line of best fit, we computed that $r=0.6501$using $n=12$data points and the critical value is $0.576$.

Explanation

Suppose you computed $r=0.6501$using $n=12$data points.

$df=n-2=12-2=10.$

The critical values associated with $df=12$are $-0.576$and $+0.576$. If $r<$negative critical value or $r>$positive critical value, then $r$is significant.

Since $r=0.6501$and $0.6501>0.576$, $r$is significant and the line may be used for prediction.