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The US Department of Energy reported that 51.7% of homes were heated by natural gas. A random sample of 221 homes in Kentucky found that 115 were heated by natural gas. Does the evidence support the claim for Kentucky at the α = 0.05 level in Kentucky? Are the results applicable across the country? Why?

Short Answer

Expert verified

We would need to expand our sample base to include these possibilities if we wanted to generalize this claim to the entire nation.

Step by step solution

01

State the null and alternate hypothesis. we have to conduct hypothesis test if homes of Kentucky take 51.7% of the natural gas according to US Department of Energy or not, on average. 

H0:p=0.517;Ha:p0.517

02

Calculate the p-value using the normal distribution for proportions: 

p-value=0.9203

In one to two complete sentences, explain what the p-value means for this problem. If the null hypothesis is true (the proportion is 0.517), then there is a 0.9203 probability that the sample (estimated) proportion is 0.520 or more.

03

Compare α and the p-value:Indicate the correct decision (“reject” or “do not reject” the null hypothesis), the reason for it, and write an appropriate conclusion, using complete sentences.

alphadecisionreason for decision
0.05Do not reject the null hypothesis.
p-value>0.05

Conclusion: At the 5% significance level, there is not enough evidence to conclude that the proportion of homes in Kentucky that are heated by natural gas is 0.517.

04

Are the results applicable across the country

However, we cannot generalize this result to the entire nation. First, the sample’s population is only the state of Kentucky. Second, it is reasonable to assume that homes in the extreme north and south will have extreme high usage and low usage, respectively. We would need to expand our sample base to include these possibilities if we wanted to generalize this claim to the entire nation.

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Most popular questions from this chapter

"Macaroni and Cheese, please!!" by Nedda Misherghi and Rachelle Hall

As a poor starving student I don't have much money to spend for even the bare necessities. So my favorite and main staple food is macaroni and cheese. It's high in taste and low in cost and nutritional value.

One day, as I sat down to determine the meaning of life, I got a serious craving for this, oh, so important, food of my life. So I went down the street to Greatway to get a box of macaroni and cheese, but it was SO expensive! \(2.02!!!Can you believe it? It made me stop and think. The world is changing fast. I had thought that the mean cost of a box (the normal size, not some super-gigantic-family-value-pack) was at most \)1, but now I wasn't so sure. However, I was determined to find out. I went to 53of the closest grocery stores and surveyed the prices of macaroni and cheese. Here are the data I wrote in my notebook:

Price per box of Mac and Cheese:

5stores @\(2.02

15stores @\)0.25

3stores @\(1.29

6stores @\)0.35

4stores @\(2.27

7stores @\)1.50

5stores @\(1.89

8stores @0.75.

I could see that the cost varied but I had to sit down to figure out whether or not I was right. If it does turn out that this mouth-watering dish is at most\)1,then I'll throw a big cheesy party in our next statistics lab, with enough macaroni and cheese for just me. (After all, as a poor starving student I can't be expected to feed our class of animals!)

You are testing that the mean speed of your cable Internet connection is more than three Megabits per second. State the null and alternative hypotheses.

It is believed that a stock price for a particular company will grow at a rate of 5per week with a standard deviation of1. An investor believes the stock won’t grow as quickly. The changes in stock price are recorded for ten weeks and are as follows: 4,3,2, 3, 1,7, 2,1,1, 2. Perform a hypothesis test using a 5%level of significance. State the null and alternative hypotheses, find the p-value, state your conclusion, and identify the Type Iand Type IIerrors.

Toastmasters International cites a report by Gallop Poll that 40% of Americans fear public speaking. A student believes that less than 40% of students at her school fear public speaking. She randomly surveys 361 schoolmates and finds that 135 report they fear public speaking. Conduct a hypothesis test to determine if the percent at her school is less than 40%.

A report by the Gallup Poll found that a woman visits her doctor, on average, at most5.8times each year. A random sample of 20women results in these yearly visit totals

3;2;1;3;7;2;9;4;6;6;8;0;5;6;4;2;1;3;4;1

At the α = 0.05 level can it be concluded that the sample mean is higher than 5.8visits per year?

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