Question

In a population of fish, approximately$42\%$ are female. A test is conducted to see if, in fact, the proportion is less. State the null and alternative hypotheses.

Short answer

The required value are

$$\begin{gathered} H_0:p=0.42 \\ {H}_a:p<0.42 \end{gathered}$$

Step-by-step solution

Given information

Females account for around 42% of a fish population. A test is to see if the proportion is indeed lower.

The null and alternative hypotheses are stated.

The null hypothesis $\left(H_6\right)$ can be stated as shown below:

$H_0:p\ge 0.42$

That mean, the proportion of female fish is more than $42\%$.

And, the alternative hypothesis $\left(H_a\right)$ can be stated as shown below:

$H_a:p<0.42$

That mean, the proportion of female fish is no more than $42\%$.