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Three students, Linda, Tuan, and Javier, are given five laboratory rats each for a nutritional experiment. Each rat’s weight is recorded in grams. Linda feeds her rats Formula A, Tuan feeds his rats Formula B, and Javier feeds his rats Formula C. At the end of a specified time period, each rat is weighed again and the net gain in grams is recorded.

Linda's rats
Tuan's rats
Javier's rats
43.5
47.0
51.2
39.4
40.5
40.9

41.3
38.9
37.9
46.0
46.3
45.0
38.2
44.2
48.6

Determine whether or not the variance in weight gain is statistically the same among Javier’s and Linda’s rats. Test at a significance level of 10%

Short Answer

Expert verified

There is no evidence that there is a difference between Javier's and Linda's rats.

Step by step solution

01

 Given information 

Given in the question that, Three students, Linda, Tuan, and Javier, are given five laboratory rats each for a nutritional experiment. Each rat’s weight is recorded in grams. Linda feeds her rats Formula A, Tuan feeds his rats Formula B, and Javier feeds his rats Formula C. At the end of a specified time period, each rat is weighed again and the net gain in grams is recorded.

Linda's rats
Tuan's rats
Javier's rats
43.5
47.0
51.2
39.4
40.5
40.9
41.3
38.9
37.9
46.0
46.3
45.0
38.2
44.2
48.6
02

Explanation

To find these results on the calculator:

Press STAT. Press 1 EDIT. Put the data into the listsL1,L2,L3

Press STAT, and arrow over to TESTS, and arrow down to 2Samp FTest. Select Data and press then selectl and press var then select 2in list 1and list2. Select the hypothesis as σ1σ2.

The calculator displays :

F=2.998578

p=0.312

Sx1=5.436635

Sx2=3.1396

x¯1=44.72

x¯2=41.68

n1=5

n2=5

03

Hypothesis tests 

We use a solution sheet to conduct the hypothesis tests, and we have:

a) The null hypothesis that three mean commuting mileages are the same is:

H0:σ1=σ2

b) The alternate hypothesis is that at least any two of the means are different:

H1:σ1σ2

c) The degree of freedom in the numerator - df(num) is 4, and the degree of freedom in the denominator - df(denom) is 4

d) We use the F(4,4)distribution for the test.

e) The value of the test statistic (F-value) is2.99857

f) The P-value for the test is 0.312

04

The graph of the distribution 

g) The graph of the distribution is

h) i. Level of significance αis 0.1

ii. Decision: We do not reject the null hypothesis

iii. Reason for decision: P-value is 0.312which is greater than the 0.1level of significance.

iv. Conclusion: There is no evidence that there is a difference between Javier's and Linda's rats.

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