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The data shown is the recorded body temperatures of 130subjects as estimated from available histograms. Traditionally we are taught that the normal human body temperature is 98.6F. This is not quite correct for everyone. Are the mean temperatures among the four groups different? Calculate 95%confidence intervals for the mean body temperature in each group and comment about the confidence intervals.

Short Answer

Expert verified

We accept the null hypothesis.

Step by step solution

01

Given Information

02

Explanation

To find these results on the calculator:

Press STAT. Press 1 EDIT. Put the data into the lists L1,L2,L3

Press STAT, and arrow over to TESTS, and arrow down to ANOVA. Press ENTER, and then enter L1,L2,L3. Press ENTER. We will see that the values in the foregoing ANOVA table are easily produced by the calculator, including the test statistic and the p-value of the test.

The calculator displays :

F=3.1363622

p=0.080746

Factor

df=2

SS=1468909.2

MS=734454.6

Error

df=12

SS=2819076

MS=234923.067

03

Explanation

We use a solution sheet to conduct the hypothesis tests, and we have:

a) The null hypothesis that three mean commuting mileages are the same is:

H0:μp=μm=μh

b) The alternate hypothesis is that at least any two of the means are different.

c) The degree of freedom in the numerator - df(num)is 2,

and the degree of freedom in the denominator - df(denom)is 12.

d) We use the F distribution for the test.

e) The value of the test statistic (F-value) is 3.14.

f) The P-value for the test is 0.08.

04

Explanation

g). The graph of the distribution is

05

Explanation

h)

i. Level of significance α is 0.05.

ii. Decision: We do not reject the null hypothesis

iii. Reason for decision: P-value is 0.08 which is greater than the 0.05 level of significance.

iv. Conclusion: There is not sufficient evidence to conclude that the mean numbers of daily visitors are different.

06

Final Answer

We accept the null hypothesis.

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