Question

Jeremiah has basketball practice two days a week. Ninety percent of the time, he attends both practices. Eight percent of the time, he attends one practice. Two percent of the time, he does not attend either practice. What is X and what values does it take on?

Short answer

X is equal to the number of basketball practices Jeremiah attends during two days a week.

X takes on the values$0,1and2$

Step-by-step solution

Content Introduction

A discrete probability distribution counts events with finite or countable outcomes. Discrete distributions, on the other hand, depict data with a countable number of outcomes, i.e., the alternative outcomes may be listed. It's possible that the list will be finite or limitless. A discrete distribution has two characteristics:

1. Each probability is between zero and one.
2. The sum of the probability is one.

Content Explanation

In the given problem, we know that Jerimiah attend both practices $90\%$of the time,

attends one practice $8\%$of the time,

not attend either practices $2\%$of the time.

Therefore, the random variable X denotes here the number of basketball practices, Jeremiah attends during two days a week and the possible values it takes are$X=0,1and2$