Open In App

Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Introductory Statistics

Barbara Illowsky, Susan Dean

$Math Studyset Vaia Explanations$ Math

OER 2018 Edition · 902 pages

ISBN: 9781938168208

Chapter 8: Q.66 (page 481)

Which distribution should you use for this problem ?

Short Answer

Expert verified

The distribution for this problem is $N (0.6; 0.035)$ .

Step by step solution

Given Information

They randomly surveyed $200$ households and found that in $120$ of them.

Explanation

The distribution for this problem is

$p = 0.6$

$\sqrt{\frac{p (1 - p)}{n}} = \sqrt{\frac{0.6 (1 - 0.6)}{200}} = 0.035$

$N (0.6; 0.035)$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The mean age for all Foothill College students for a recent Fall term was $33.2$ . The population standard deviation has been pretty consistent at $15$ . Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was $30.4$ . We are interested in the true mean age for Winter Foothill College students. Let $X =$ the age of a Winter Foothill College student.

Construct a $95 %$ Confidence Interval for the true mean age of Winter Foothill College students.

How much area is in each tail? $\frac{α}{2} =______$ ?

Using the same mean, standard deviation, and sample size, how would the error bound change if the confidence level were reduced to 90%? Why?

In words, define the random variable $\bar{X}$ .

A poll of 1,200 voters asked what the most significant issue was in the upcoming election. Sixty-five percent answered the economy. We are interested in the population proportion of voters who feel the economy is the most important.

Define the random variable X in words

Table $8.2$ shows a different random sampling of $20$ cell phone models. Use this data to calculate a $93$ % confidence interval for the true mean SAR for cellphones certified for use in the United States. As previously, assume that the population standard deviation is σ= $0.337$ .

Phone Model	SAR	Phone Model	SAR
Blackberry pearl $8120$	$1.48$	Nokia E71x	$1.53$
HTC Evo Design 4G	$0.8$	Nokia N $75$	$0.68$
HTC Freestyle	$1.15$	Nokia N $79$	$1.4$
LG Ally	$1.36$	Sagem Puma	$1.24$
LG Fathom	$0.77$	Samsung Fascinate	$0.57$
LG Optimus Vu	$0.462$	Samsung Infuse 4G	$0.2$
Motorola Cliq XT	$1.36$	Samsung Nexus S	$0.51$
Motorola Droid pro	$1.39$	Samsung Replenish	$0.3$
Motorola Droid Razr M	$1.3$	Sony W5 $18$ a walkman	$0.73$
Nokia $7705$ Twist	$0.7$	ZTE C $79$	$0.869$

See all solutions

Recommended explanations on Math Textbooks

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free

Which distribution should you use for this problem ?

Short Answer

Step by step solution

Given Information

Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Applied Mathematics

Calculus

Pure Maths

Logic and Functions

Geometry

Study anywhere. Anytime. Across all devices.

Company

Product

Help