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Suppose that 14children, who were learning to ride two-wheel bikes, were surveyed to determine how long they had

to use training wheels. It was revealed that they used them an average of six months with a sample standard deviation of

three months. Assume that the underlying population distribution is normal.

a.i.x̄=__________ii.sx=__________iii.n=__________iv.n1=__________

b. Define the random variable Xin words.

c. Define the random variable Xin words.

d. Which distribution should you use for this problem? Explain your choice.

e. Construct a 99%confidence interval for the population mean length of time using training wheels.

i. State the confidence interval.

ii. Sketch the graph.

iii. Calculate the error bound.

f. Why would the error bound change if the confidence level were lowered to 90%?

Short Answer

Expert verified

(a) The results are:

1. x=6

2. sx=3

3. n = 14

4. n-1=13.

(b) The total amount of time that 1youngster requires training wheels is X.

(c) From a sample of14youngsters, the average amount of time spent on training wheels is X.

(d) With the parameters tn-1, the distribution is thet.

t14-1=t13.

(e) The final results are:

1. CI=(3.5848,8.4152)

2. we show it through graph :

3.EBM=1.72

(f) The error bound will become smaller as the confidence level decreases, because the area under the curve to derive the real population mean decreases as the confidence level decreases.

Step by step solution

01

Explanation (a)

i. The sample mean time spent utilising training wheels is 6minutes.

Overline x=6is the mean time.

ii. The sample length of time's standard deviation, sx=3.

iv. There were 14children asked about how long they had been wearing training wheels, n=14.

iv. If n=14is the total number of patients used in the study, then n-1=13.

02

Explanation (b)

The total amount of time that 1 youngster requires training wheels is X.

03

Explanation (c)

From a sample of 14youngsters, the average amount of time spent on training wheels is X.

04

Explanation (d)

With the parameters tn-1, the distribution is the t.

t14-1=t13.

05

Explanation (e) 

i. Using the TI-83calculator, calculate the confidence interval. The confidence interval's output,

CI=(3.5848,8.4152)

ii. The graph is as follows:

iii. The formula is used to compute the error bound,

EBM=tn-1α2sn

EBM=t14-10.052314

EBM=1.72.

06

Explanation (f)

The error bound will become smaller as the confidence level decreases, because the area under the curve to derive the real population mean decreases as the confidence level decreases.

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