Chapter 23: Problem 9
Let \(R,=(\mathrm{A}-\lambda I)^{-1}\) and \(R,=(\mathrm{A}-\mu I)^{-1}\) be the resolvents corresponding to the points \(A\) and \(\mu\). Prove that \(R_{\lambda} R_{\mu}=R_{\mu} R_{\lambda}\) and $$ R_{\mu}-R_{\lambda}=(\mu-\lambda) R_{\mu} R_{\lambda} $$ Hint. Multiply both sides of (19) by \((\mathrm{A}-\lambda I)(A-\mu L)\). Comment. It follows from (19) that if \(\mathrm{A}\), is a regular point of \(\mathrm{A}\), then the derivative of \(R\), with respect to \(A\) at the point \(\lambda_{0}\), i.e., the limit. $$ \lim _{\Delta \lambda \rightarrow 0} \frac{R_{\lambda_{0}+\Delta \lambda}-R_{\lambda_{0}}}{\Delta \lambda} $$ (in the sense of convergence with respect to the operator norm) exists and equals \(R_{\lambda_{0}^{\circ}}^{2}\)
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