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Increases in worker injuries and disability claims have prompted renewed interest in workplace design and regulation. As one particular aspect of this, employees required to do regular lifting should not have to handle unsafe loads. The article "Anthropometric, Muscle Strength, and Spinal Mobility Characteristics as Predictors of the Rating of Acceptable Loads in Parcel Sorting" (Ergonomics [1992]: 1033-1044) reported on a study involving a random sample of \(n=18\) male postal workers. The sample mean rating of acceptable load attained with a work-simulating test was found to be \(\bar{x}=9.7 \mathrm{~kg}\). and the sample standard deviation was \(s=4.3 \mathrm{~kg}\). Suppose that in the population of all male postal workers, the distribution of rating of acceptable load can be modeled approximately using a normal distribution with mean value \(\mu\). Construct and interpret a \(95 \%\) confidence interval for \(\mu\).

Short Answer

Expert verified
The 95% confidence interval for \(\mu\) is calculated using the above steps based on the given sample. The interpretation would depend on the calculated range which is a result of these computations.

Step by step solution

01

Define and Compute the Standard Error

To begin, we first need to calculate the standard error. The standard error of the mean is given by the formula \(SE = \frac{s}{\sqrt{n}}\), where \(s\) is the standard deviation and \(n\) is the number of observations in the sample. Here, our standard deviation, \(s\), is 4.3 kg, and the number of samples, \(n\), is 18, so our standard error is \(SE = \frac{4.3}{\sqrt{18}}\).
02

Find the z-value

For a 95% confidence interval, we look for the z-value that leaves 5% of the probability distribution in the tails, split evenly at 2.5% in each tail. This z-value can be looked up in standard statistical tables, or be found using appropriate functions in statistical software. The z-value corresponding to a 95% confidence interval is about 1.96.
03

Calculate the Confidence Interval

The confidence interval is calculated using the formula \(CI = \bar{x} \pm z * SE\), where \(\bar{x}\) is mean of the sample, \(z\) is our z-value for the chosen level of confidence, and \(SE\) is the standard error. Here, our sample mean, \(\bar{x}\), is 9.7 kg, and our standard error has been computed in the first step, and z-value has been obtained in the second step. Substituting these values into the formula will yield the confidence interval for \(\mu\).
04

Interpret the Confidence Interval

The resulting confidence interval can be interpreted as follows: We are 95% confident that the true mean value for the acceptable load for all male postal workers is within the calculated range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The standard error (SE) is a statistical measure that quantifies the amount of variation or dispersion of a sample mean relative to the true population mean. It's a crucial concept in statistics as it helps researchers understand how far off a sample's mean is likely to be from the actual mean of the entire population.

To compute the standard error, you need the sample standard deviation, denoted as 's', and the sample size, denoted as 'n'. The formula is given by:
\[\begin{equation} SE = \frac{s}{\sqrt{n}} \end{equation}\]
In a real-world scenario, such as assessing the acceptable load ratings by postal workers, the standard error helps determine the reliability of the sample mean. A smaller standard error suggests a more reliable and precise sample mean, indicating that the sample is a good representation of the population.
Sample Mean
The sample mean, often represented by \(\bar{x}\), is the average value of a set of observations. It is calculated by adding up all the values and then dividing by the number of observations. When we have a sample mean, it’s important to remember we are looking at a representation of the broader population from which the sample was drawn.

To mathematically express the sample mean, you use the formula: \[\begin{equation} \bar{x} = \frac{1}{n}\sum_{i=1}^{n}x_i \end{equation}\]
where \(x_i\) represents each value in the sample and \(n\) is the total number of observations. This average can give us insights into the central tendency of the data.

In practical terms, like the study of postal workers and acceptable load weights, the sample mean gives us an estimate of what postal workers consider to be an acceptable load on average. Knowing the sample mean allows us to then apply it to conclusions about the general population of postal workers, including constructing confidence intervals to understand the variability of this estimate.
Normal Distribution
The normal distribution, also known as the Gaussian distribution, is a symmetric, bell-shaped curve that represents the distribution of many types of data. Most values remain around the mean and the probabilities for values further away from the mean taper off equally in both directions.

Mathematically described by the equation of a bell curve, the main properties of a normal distribution include its mean \(\mu\), standard deviation \(\sigma\), and the total area under the curve representing the probability which is always 1. The standard normal distribution has a mean of 0 and a standard deviation of 1.

For practical applications like the one involving postal workers, assuming a normal distribution can simplify the process of making inferences about the population mean—since we can then use well-established statistical tools such as z-scores for constructing confidence intervals. With this approach, it is assumed that sample means will tend to form a normal distribution around the true population mean as the sample size increases, due to the Central Limit Theorem.

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Most popular questions from this chapter

"Heinz Plays Catch-up After Under-Filling Ketchup Containers" is the headline of an article that appeared on CNN.com (November 30,2000 ). The article stated that Heinz had agreed to put an extra \(1 \%\) of ketchup into each ketchup container sold in California for a 1 -year period. Suppose that you want to make sure that Heinz is in fact fulfilling its end of the agreement. You plan to take a sample of 20 -oz bottles shipped to California, measure the amount of ketchup in each bottle, and then use the resulting data to estimate the mean amount of ketchup in each bottle. A small pilot study showed that the amount of ketchup in 20 -oz bottles varied from \(19.9\) to \(20.3\) oz. How many bottles should be included in the sample if you want to estimate the true mean amount of ketchup to within \(0.1\) oz with \(95 \%\) confidence?

Why is an unbiased statistic generally preferred over a biased statistic for estimating a population characteristic? Does unbiasedness alone guarantee that the estimate will be close to the true value? Explain. Under what circumstances might you choose a biased statistic over an unbiased statistic if two statistics are available for estimating a population characteristic?

One thousand randomly selected adult Americans participated in a survey conducted by the Associated Press (June, 2006). When asked "Do you think it is sometimes justified to lie or do you think lying is never justified?" \(52 \%\) responded that lying was never justified. When asked about lying to avoid hurting someone's feelings, 650 responded that this was often or sometimes OK. a. Construct a \(90 \%\) confidence interval for the proportion of adult Americans who think lying is never justified. b. Construct a \(90 \%\) confidence interval for the proportion of adult American who think that it is often or sometimes OK to lie to avoid hurting someone's feelings. c. Based on the confidence intervals from Parts (a) and (b), comment on the apparent inconsistency in the responses given by the individuals in this sample.

The report "2005 Electronic Monitoring \& Surveillance Survey: Many Companies Monitoring, Recording, Videotaping-and Firing-Employees" (American Management Association, 2005 ) summarized the results of a survey of 526 U.S. businesses. The report stated that 137 of the 526 businesses had fired workers for misuse of the Internet and 131 had fired workers for email misuse. For purposes of this exercise, assume that it is reasonable to regard this sample as representative of businesses in the United States. a. Construct and interpret a \(95 \%\) confidence interval for the proportion of U.S. businesses that have fired workers for misuse of the Internet. b. What are two reasons why a \(90 \%\) confidence interval for the proportion of U.S. businesses that have fired workers for misuse of email would be narrower than the \(95 \%\) confidence interval computed in Part (a).

Samples of two different types of automobiles were selected, and the actual speed for each car was determined when the speedometer registered \(50 \mathrm{mph}\). The resulting \(95 \%\) confidence intervals for true average actual speed were \((51.3,52.7)\) and \((49.4,50.6)\). Assuming that the two sample standard deviations are identical, which confidence interval is based on the larger sample size? Explain your reasoning.

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