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Suppose that a random sample of 50 bottles of a par. ticular brand of cough medicine is selected and the alcohol content of each bottle is determined. Let \(\mu\) denote the average alcohol content for the population of all bottles of the brand under study. Suppose that the sample of 50 results in a \(95 \%\) confidence interval for \(\mu\) of \((7.8,9.4)\). a. Would a \(90 \%\) confidence interval have been narrower or wider than the given interval? Explain your answer. b. Consider the following statement: There is a \(95 \%\) chance that \(\mu\) is between \(7.8\) and \(9.4\). Is this statement correct? Why or why not? c. Consider the following statement: If the process of selecting a sample of size 50 and then computing the corresponding \(95 \%\) confidence interval is repeated 100 times, 95 of the resulting intervals will include \(\mu\). Is this statement correct? Why or why not?

Short Answer

Expert verified
a. A \(90 \%\) would have been narrower than the \(95 \%\) interval. b. It is incorrect to say there's a \(95 \%\) chance the average alcohol content is between \(7.8\) and \(9.4\); the correct interpretation is that we're \(95 \%\) confident the actual average falls within our interval. c. It’s incorrect to say that \(95\) out of \(100\) confidence intervals will contain the average; the correct interpretation is that, in the long run, \(95 \%\) of the intervals resulting from this process would contain the average.

Step by step solution

01

Understanding and comparing confidence intervals

Part (a) asks whether a \(90 \%\) confidence interval would be wider or narrower than a \(95 \%\). Because a higher confidence level corresponds to a wider interval - given that a higher confidence level means more certainty about the parameter falling within the interval - a \(90 \%\) confidence interval would be narrower than the \(95 \%\).
02

Interpreting the confidence interval

Part (b) asks whether it is correct to say there's a \(95 \%\) chance that the average alcohol content is between \(7.8\) and \(9.4\). The correct interpretation of a \(95 \%\) confidence interval is that we're \(95 \%\) confident that the actual average falls within our interval. The average alcohol content isn't a random variable - it's a fixed value - we're just not exactly sure what it is. So, it's incorrect to say there's a 'chance' it falls within the interval.
03

Understanding the concept of 'confidence' in confidence intervals

Part (c) asks whether it is correct to say if sampling and confidence interval calculation is repeated \(100\) times, \(95\) intervals will include the actual average. It’s important to note that 'confidence' in confidence intervals doesn’t mean that \(95 \%\) of the samples will always contain the population parameter but that, in the long run, \(95 \%\) of such computed intervals would contain the population parameter. The emphasis is on the method rather than the individual intervals which are outcomes of the method.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Inference
Statistical inference is a cornerstone of data analysis, allowing us to draw conclusions about a population based on sample data. It involves using probability theory to estimate population characteristics from samples. When we infer the average alcohol content of cough medicine bottles from a sample of 50, we're applying statistical inference.

Understanding confidence intervals, as in the provided exercise, is fundamental to statistical inference. Given a 95% confidence interval of (7.8, 9.4), we infer there's a high level of certainty that the true population mean, \( \mu \), lies within this range. However, it's crucial to grasp that the 'confidence' is not about the probability of \( \mu \) being in the interval but about the reliability of our estimation process if repeated over time.
Population Parameter Estimation
Population parameter estimation involves deducing the value of a particular characteristic (parameter) for an entire population. In our exercise, this parameter is the mean alcohol content \( \mu \). Estimation is performed through samples because studying the entire population is often not feasible.

This estimation process arises from the collected sample's data, leading us to calculate a range where we believe the true population parameter will lie. A narrower confidence interval, such as a hypothetical 90% interval compared to a 95% interval, indicates more precision but less confidence. It's like saying, 'We're taking a calculated gamble and are less sure, but we think the true mean is closer to this specific number.'
Sample Data Analysis
Sample data analysis is the process by which we examine and interpret the data collected from a subset of the population (our sample) to make inferences about the whole. This method assumes that the sample is representative of the population and applies statistical techniques to derive meaningful patterns and measures, such as confidence intervals.

In part (c) of our exercise, the interpretation of the sample analysis process is crucial. The statement isn't asserting that exactly 95 of the 100 intervals will include \( \mu \); rather, it expresses confidence in the long-term performance of the method. In other words, if we kept taking samples and calculating intervals, we'd expect that 95% of those intervals would capture the true mean—demonstrating the powerful insights we can gain from well-conducted sample data analysis.

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Most popular questions from this chapter

The Gallup Organization conducts an annual survey on crime. It was reported that \(25 \%\) of all households experienced some sort of crime during the past year. This estimate was based on a sample of 1002 randomly selected adults. The report states, "One can say with \(95 \%\) confidence that the margin of sampling error is \(\pm 3\) percentage points." Explain how this statement can be justified.

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked how many months had passed since their last visit to a dentist. Their responses were as follows: \(\begin{array}{lllll}6 & 17 & 11 & 22 & 29\end{array}\) Assuming that these five students can be considered a random sample of all students participating in the free checkup program, construct a \(95 \%\) confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program.

Consumption of fast food is a topic of interest to researchers in the field of nutrition. The article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among Children" (Pediatrics [2004]: \(112-118\) ) reported that 1720 of those in a random sample of 6212 U.S. children indicated that on a typical day they ate fast food. Estimate \(\pi\), the proportion of children in the U.S. who eat fast food on a typical day.

An Associated Press article on potential violent behavior reported the results of a survey of 750 workers who were employed full time (San Luis Obispo Tribune, September 7,1999 ). Of those surveyed, 125 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker (but didn't). Assuming that it is reasonable to regard this sample of 750 as a random sample from the population of full-time workers, use this information to construct and interpret a \(90 \%\) confidence interval estimate of \(\pi\), the true proportion of fulltime workers so angered in the last year that they wanted to hit a colleague.

In a study of 1710 schoolchildren in Australia (Herald Sun, October 27,1994 ), 1060 children indicated that they normally watch TV before school in the morning. (Interestingly, only \(35 \%\) of the parents said their children watched TV before school!) Construct a \(95 \%\) confidence interval for the true proportion of Australian children who say they watch TV before school. What assumption about the sample must be true for the method used to construct the interval to be valid?

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