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Tongue Piercing May Speed Tooth Loss, }}\( Researchers Say" is the headline of an article that appeared in the San Luis Obispo Tribune (June 5,2002 ). The article describes a study of 52 young adults with pierced tongues. The researchers found receding gums, which can lead to tooth loss, in 18 of the participants. Construct a \)95 \%\( confidence interval for the proportion of young adults with pierced tongues who have receding gums. What assumptions must be made for use of the \)z$ confidence interval to be appropriate?

Short Answer

Expert verified
The 95% confidence interval fluctuates based on the calculated values. The assumptions that must be made for the z interval to be appropriate are that observations are independent and come from a random sample. Additionally, the Central Limit Theorem states if the sample size is large (n > 30), the distribution is approximately normal.

Step by step solution

01

Interpret the problem and data

From the exercise, we have a study of 52 young adults with pierced tongues, and among them, 18 have receding gums.
02

Calculate the sample proportion

The sample proportion (p) is calculated by dividing the number of young adults with receding gums by the total number of young adults in the study. In this case, the sample proportion is \(p = 18/52\).
03

Calculate the standard error

The standard error (SE) is calculated using the formula \(SE = \sqrt{(p(1-p)/n)}\), where p is the sample proportion, and n is the sample size. Plugging the values will allow us to get the standard error.
04

Find the critical value

Using the Z-table, the critical value for a 95% confidence interval is approximately 1.96.
05

Calculate the 95% confidence interval

The 95% confidence interval is calculated using the formula: \(p \pm Z*SE\), where p is the sample proportion, Z is the critical value, and SE is the standard error. Calculate this to get the confidence interval.
06

State the assumptions

The assumptions for this interval are that the samples are independent and are randomly sampled. Also, the Central Limit Theorem states that the distribution tends to be normal if the sample size is large (n > 30), which is the case here. A point to note is that these results are dependant on the validity of the study's methodology.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics
In the world of data and decision-making, statistics serves as a crucial tool for understanding and interpreting the information gathered from the world around us. It's the science of collecting, analyzing, interpreting, presenting, and organizing data to find patterns, trends, and probabilities. When a study, such as the investigation into receding gums among young adults with pierced tongues, seeks to understand a phenomenon in a larger population, statistics provides the methodology to make informed conclusions based on a sample.

Understanding the results from such studies involves familiarizing oneself with several statistical concepts, including proportion, standard error, and confidence intervals. These allow researchers to infer characteristics of a larger population without having to survey every individual, an often impractical or impossible task.
Sample Proportion
The sample proportion is a snapshot of what you're studying — in this case, the fraction of young adults with pierced tongues who are experiencing receding gums. It's represented by the symbol \(p\) and is calculated by dividing the number of 'successes' by the total number of observations in the sample. If you have 18 young adults with receding gums out of 52 surveyed, then the sample proportion \(p\) is \(18/52\).

Understanding sample proportions is essential to making predictions about the broader population. As you work with this kind of data, remember that sample proportions can vary from sample to sample; hence, statisticians use them alongside other statistical measures, such as the standard error and confidence intervals, to create a more complete, reliable picture.
Standard Error
The standard error (SE) measures how much the sample proportion (\(p\)) might differ from the true population proportion due to random sampling variability. It's the standard deviation of the sampling distribution of the sample proportion and is calculated using the formula \(SE = \sqrt{(p(1-p)/n)}\), where \(n\) is the sample size. In our example, with the sample proportion of receding gums calculated at \(18/52\), and with a sample size of 52, you can insert these values into the formula to determine the standard error.

This metric is vital because it allows researchers to create a range (known as a confidence interval) around the sample proportion to estimate where the true population proportion is likely to fall. The lower the standard error, the more precise the estimation is.
Central Limit Theorem
The Central Limit Theorem is a cornerstone in the field of statistics. This theorem states that, given a sufficiently large sample size, the sampling distribution of the sample mean will be normally distributed, regardless of the original distribution of the population. This principle is what underlies the approach to calculate confidence intervals using Z-scores or T-scores.

In the context of the pierced tongue study, considering the sample size of 52 is greater than the common threshold of 30, the central limit theorem assures us that the sampling distribution of our sample proportion will tend to be normal. This normality allows us to apply the Z-score to our calculations to determine our confidence interval. When we assume a normal distribution, we can assert with some degree of 'confidence' that the true population proportion lies within this interval, giving us a practical and statistically valid estimation.

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Most popular questions from this chapter

The article "First Year Academic Success: A Prediction Combining Cognitive and Psychosocial Variables for Caucasian and African American Students" (Journal of College Student Development \([1999]: 599-610\) ) reported that the sample mean and standard deviation for high school grade point average (GPA) for students enrolled at a large research university were \(3.73\) and \(0.45\), respectively. Suppose that the mean and standard deviation were based on a random sample of 900 students at the university. a. Construct a \(95 \%\) confidence interval for the mean high school GPA for students at this university. b. Suppose that you wanted to make a statement about the range of GPAs for students at this university. Is it reasonable to say that \(95 \%\) of the students at the university have GPAs in the interval you computed in Part (a)? Explain.

The formula used to compute a confidence interval for the mean of a normal population when \(n\) is small is $$ \bar{x} \pm(t \text { critical value }) \frac{s}{\sqrt{n}} $$ What is the appropriate \(t\) critical value for each of the following confidence levels and sample sizes? a. \(95 \%\) confidence, \(n=17\) b. \(90 \%\) confidence, \(n=12\) c. \(99 \%\) confidence, \(n=24\) d. \(90 \%\) confidence, \(n=25\) e. \(90 \%\) confidence, \(n=13\) f. \(95 \%\) confidence, \(n=10\)

An Associated Press article on potential violent behavior reported the results of a survey of 750 workers who were employed full time (San Luis Obispo Tribune, September 7,1999 ). Of those surveyed, 125 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker (but didn't). Assuming that it is reasonable to regard this sample of 750 as a random sample from the population of full-time workers, use this information to construct and interpret a \(90 \%\) confidence interval estimate of \(\pi\), the true proportion of fulltime workers so angered in the last year that they wanted to hit a colleague.

In the article "Fluoridation Brushed Off by Utah" (Associated Press, August 24,1998 ), it was reported that a small but vocal minority in Utah has been successful in keeping fluoride out of Utah water supplies despite evidence that fluoridation reduces tooth decay and despite the fact that a clear majority of Utah residents favor fluoridation. To support this statement, the article included the result of a survey of Utah residents that found \(65 \%\) to be in favor of fluoridation. Suppose that this result was based on a random sample of 150 Utah residents. Construct and interpret a \(90 \%\) confidence interval for \(\pi\), the true proportion of Utah residents who favor fluoridation. Is this interval consistent with the statement that fluoridation is favored by a clear majority of residents?

Five hundred randomly selected working adults living in Calgary, Canada were asked how long, in minutes, their typical daily commute was (Calgary Herald Traffic Study, Ipsos, September 17,2005 ). The resulting sample mean and standard deviation of commute time were \(28.5\) minutes and \(24.2\) minutes, respectively. Construct and interpret a \(90 \%\) confidence interval for the mean commute time of working adult Calgary residents.

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