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The formula used to compute a large-sample confidence interval for \(\pi\) is $$ p \pm(z \text { critical value }) \sqrt{\frac{p(1-p)}{n}} $$ What is the appropriate \(z\) critical value for each of the following confidence levels? a. \(95 \%\) d. \(80 \%\) b. \(90 \%\) e. \(85 \%\) c. \(99 \%\)

Short Answer

Expert verified
The z critical values for the confidence levels 95%, 90%, 99%, 80%, and 85% are 1.96, 1.645, 2.575, 1.28, and 1.44 respectively.

Step by step solution

01

Understanding the Confidence Interval

The confidence interval is expressed as \( p \pm z \sqrt{\frac{p(1-p)}{n}} \) where \( p \) is the population proportion, \( n \) is the sample size, and \( z \) is the critical value corresponding to the confidence level. The critical value \( z \) is determined by the desired confidence level and can be looked up in a standard normal distribution table.
02

Calculating the z critical value for a 95% confidence level

The z critical value for a 95% confidence level is 1.96.
03

Calculating the z critical value for a 90% confidence level

The z critical value for a 90% confidence level is 1.645.
04

Calculating the z critical value for a 99% confidence level

The z critical value for a 99% confidence level is 2.575.
05

Calculating the z critical value for an 80% confidence level

The z critical value for an 80% confidence level is 1.28.
06

Calculating the z critical value for an 85% confidence level

The z critical value for an 85% confidence level is 1.44.

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Most popular questions from this chapter

An Associated Press article on potential violent behavior reported the results of a survey of 750 workers who were employed full time (San Luis Obispo Tribune, September 7,1999 ). Of those surveyed, 125 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker (but didn't). Assuming that it is reasonable to regard this sample of 750 as a random sample from the population of full-time workers, use this information to construct and interpret a \(90 \%\) confidence interval estimate of \(\pi\), the true proportion of fulltime workers so angered in the last year that they wanted to hit a colleague.

The article "Doctors Cite Burnout in Mistakes" (San Luis Obispo Tribune, March 5,2002 ) reported that many doctors who are completing their residency have financial struggles that could interfere with training. In a sample of 115 residents, 38 reported that they worked moonlighting jobs and 22 reported a credit card debt of more than \(\$ 3000\). Suppose that it is reasonable to consider this sample of 115 as a random sample of all medical residents in the United States. a. Construct and interpret a \(95 \%\) confidence interval for the proportion of U.S. medical residents who work moonlighting jobs. b. Construct and interpret a \(90 \%\) confidence interval for the proportion of U.S. medical residents who have a credit card debt of more than \(\$ 3000\). c. Give two reasons why the confidence interval in Part (a) is wider than the confidence interval in Part (b).

According to an AP-Ipsos poll (June 15,2005 ), \(42 \%\) of 1001 randomly selected adult Americans made plans in May 2005 based on a weather report that turned out to be wrong. a. Construct and interpret a \(99 \%\) confidence interval for the proportion of Americans who made plans in May 2005 based on an incorrect weather report. b. Do you think it is reasonable to generalize this estimate to other months of the year? Explain.

For each of the following choices, explain which would result in a wider large-sample confidence interval for \(\pi\) : a. \(90 \%\) confidence level or \(95 \%\) confidence level b. \(n=100\) or \(n=400\)

A manufacturer of college textbooks is interested in estimating the strength of the bindings produced by a particular binding machine. Strength can be measured by recording the force required to pull the pages from the binding. If this force is measured in pounds, how many books should be tested to estimate with \(95 \%\) confidence to within \(0.1 \mathrm{lb}\), the average force required to break the binding? Assume that \(\sigma\) is known to be \(0.8 \mathrm{lb}\).

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