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Consider the following population: \(\\{1,2,3,4\\}\). Note that the population mean is $$\mu=\frac{1+2+3+4}{4}=2.5$$ a. Suppose that a random sample of size 2 is to be selected without replacement from this population. There are 12 possible samples (provided that the order in which observations are selected is taken into account): \(\begin{array}{cccccc}1,2 & 1,3 & 1,4 & 2,1 & 2,3 & 2,4 \\ 3,1 & 3,2 & 3,4 & 4,1 & 4,2 & 4,3\end{array}\) Compute the sample mean for each of the 12 possible samples. Use this information to construct the sampling distribution of \(\bar{x}\). (Display the sampling distribution as a density histogram.) b. Suppose that a random sample of size 2 is to be selected, but this time sampling will be done with replacement. Using a method similar to that of Part (a), construct the sampling distribution of \(\bar{x}\). (Hint: There are 16 different possible samples in this case.) c. In what ways are the two sampling distributions of Parts (a) and (b) similar? In what ways are they different?

Short Answer

Expert verified
The resulting histograms or frequency distribution tables from step 2 and 4 represent the sampling distribution of the sample mean for both instances of sampling with and without replacement. Comparison in step 5 could note that while some sample means might stay the same, the distribution shape, center, and the count of possible samples would differ between the two methods.

Step by step solution

01

Sample Means Without Replacement

First, compute the sample mean for each of the 12 possible samples. The sample mean can be calculated by adding the two numbers together and dividing by 2 (since we are taking samples of size 2). After calculating, list all 12 sample means.
02

Constructing Sampling Distribution Without Replacement

Use the sample means to create the sampling distribution of \(\bar{x}\). This distribution can be represented as a frequency distribution or histogram with sample means on the x-axis and count frequency on the y-axis.
03

Sample Means With Replacement

Now, do the same as in step 1 but this time consider sampling with replacement. There will be 16 samples this time. Compute and list the 16 sample means.
04

Constructing Sampling Distribution With Replacement

As in step 2, use these sample means to construct the sampling distribution of \(\bar{x}\) with replacement
05

Compare the Distributions

Compare the two sampling distributions from parts (a) and (b). Comment on similarities and differences. It's important in this step to notice how the count of possible samples changes based on sampling method and how the sample means might shift in location and shape.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Sampling
Statistical sampling is a powerful technique used to understand and make inferences about a larger group, or population, by examining a subset of that group, known as a sample. Proper sampling methods are crucial for obtaining representative samples that can accurately reflect the properties of the population. In our textbook exercise, we exemplify this concept by selecting samples of size 2 from a population of four elements. By varying the method of sampling, we can see how the choice of technique can affect the sample and our inferences about the population.

When conducting statistical sampling, it's important to define the population, decide on a sampling method like random sampling, and determine whether to sample with or without replacement. These decisions can significantly influence the sampling distribution, which is the probability distribution of a statistic (like the sample mean) obtained through repeated sampling from the population.
Population Mean
The population mean, denoted by the symbol \(\mu\), represents the average of all the values within an entire population. It is a parameter that describes the central tendency of the population data. In our example, the population mean is calculated by adding up all the numbers in the population \( \{1,2,3,4\} \) and dividing by the total number of elements (4).

In a formula, the population mean is expressed as \( \mu = \frac{\sum_{i=1}^{N} x_i}{N} \) where \( x_i \) represents each value in the population, and \( N \) is the size of the population. Knowing the population mean allows us to compare it with the sample means and assess the sampling method's accuracy.
Sample Mean
The sample mean, represented by \( \bar{x} \) is similar to the population mean, but it's derived from a sample rather than the full population. It's calculated by summing all values in the sample and dividing by the number of values in the sample. Although the sample mean is a statistic and not a parameter of the population, it is used to estimate the population mean.

In our textbook exercise, we calculate the sample mean for each possible set of samples. Since the sample size is 2, the calculation is straightforward: \( \bar{x} = \frac{x_1 + x_2}{2} \) where \( x_1 \) and \( x_2 \) are the values in the sample. It's crucial to note that the sample mean can vary from sample to sample, which leads to the concept of a sampling distribution.
Random Sampling
Random sampling is a method wherein each member of the population has an equal chance of being selected in the sample. This impartiality is essential to reducing sampling bias and ensuring the sample's representativeness. For instance, in the given problem, each 2-number combination is equally likely to be chosen as a sample.

This method underpins most statistical inference techniques because a random sample will, on average, exhibit the same properties as the population. When we talk about 'random', it implies that there is no discernible pattern in the selection process. Random sampling is central to gathering unbiased data and making sure our estimates, like the sample mean, are reliable.
Sampling with Replacement
Sampling with replacement is a method where each member of the population can be chosen more than once for the same sample. After a member is selected, it is 'replaced' before another member is picked. In our textbook example, each value from the population can appear multiple times across different samples, and the same value can even appear more than once within a single sample.

Because the population elements are replaced, the probability distribution of the sample remains constant with each draw. This approach can increase diversity in the samples in terms of combinations but not necessarily in representation of different population elements. The consequence of this method on the sampling distribution is that it may include more repeated values of sample means.
Sampling without Replacement
Contrary to sampling with replacement, sampling without replacement means that once a member of the population is selected, it cannot be chosen again for that specific sample. Consequently, each sample will consist of unique elements from the population. In our problem, this results in 12 discrete samples for a population of 4 when selecting two numbers.

This method affects the probability distribution of subsequent selections and often leads to a more varied array of sample means. Because the samples don't have repeated elements, the sampling distribution without replacement can sometimes provide a better estimate of the population mean by preventing the overrepresentation of certain population elements in the sample.
Frequency Distribution
Frequency distribution is a summary that shows the number of occurrences of each possible value of a variable. In the context of sampling, the variables are the sample means, and the frequency shows how many times each mean appears across all samples. For example, certain sample means might appear more frequently than others, indicating a trend in the sampling distribution.

Typically, a frequency distribution is visualized using a table or a chart, like a histogram. When we represent the frequency distribution as a histogram, the x-axis has the sample means, and the y-axis has the frequencies, allowing us to see the shape of the sampling distribution. A clear view of the frequency of different sample means gives insights into the variability and spread of the data.
Density Histogram
A density histogram is a type of graph that represents the distribution of a variable and is similar to a frequency histogram. Instead of simply showing frequency, it shows the proportion of the sample represented by each bin relative to the size of the sample. This allows us to compare the shapes of two distributions, even if they have a different number of observations, like in our textbook exercise where one sampling method has 12 samples and the other has 16.

The bars in a density histogram correspond to the sample mean values with their respective probabilities. Constructing such a histogram for our sampling distribution gives a visual understanding of how likely we are to obtain certain sample means from a population, considering the particular sampling method.

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Most popular questions from this chapter

The article "Unmarried Couples More Likely to Be Interracial" (San Luis Obispo Tribune, March 13, 2002) reported that \(7 \%\) of married couples in the United States are mixed racially or ethnically. Consider the population consisting of all married couples in the United States. a. A random sample of \(n=100\) couples will be selected from this population and \(p\), the proportion of couples that are mixed racially or ethnically, will be computed. What are the mean and standard deviation of the sampling distribution of \(p\) ? b. Is it reasonable to assume that the sampling distribution of \(p\) is approximately normal for random samples of size \(n=100\) ? Explain. c. Suppose that the sample size is \(n=200\) rather than \(n=100\), as in Part (b). Does the change in sample size change the mean and standard deviation of the sampling distribution of \(p ?\) If so, what are the new values for the mean and standard deviation? If not, explain why not. d. Is it reasonable to assume that the sampling distribution of \(p\) is approximately normal for random samples of size \(n=200 ?\) Explain. e. When \(n=200\), what is the probability that the proportion of couples in the sample who are racially or ethnically mixed will be greater than \(.10\) ?

Suppose that the mean value of interpupillary distance (the distance between the pupils of the left and right eyes) for adult males is \(65 \mathrm{~mm}\) and that the population standard deviation is \(5 \mathrm{~mm}\). a. If the distribution of interpupillary distance is normal and a sample of \(n=25\) adult males is to be selected, what is the probability that the sample average distance \(\bar{x}\) for these 25 will be between 64 and \(67 \mathrm{~mm}\) ? at least \(68 \mathrm{~mm}\) ? b. Suppose that a sample of 100 adult males is to be obtained. Without assuming that interpupillary distance is normally distributed, what is the approximate probability that the sample average distance will be between 64 and \(67 \mathrm{~mm}\) ? at least \(68 \mathrm{~mm}\) ?

An airplane with room for 100 passengers has a total baggage limit of 6000 lb. Suppose that the total weight of the baggage checked by an individual passenger is a random variable \(x\) with a mean value of \(50 \mathrm{lb}\) and a standard deviation of \(20 \mathrm{lb}\). If 100 passengers will board a flight, what is the approximate probability that the total weight of their baggage will exceed the limit? (Hint: With \(n=100\), the total weight exceeds the limit when the average weight \(\bar{x}\) exceeds \(6000 / 100\).)

Let \(x_{1}, x_{2}, \ldots, x_{100}\) denote the actual net weights (in pounds) of 100 randomly selected bags of fertilizer. Suppose that the weight of a randomly selected bag has a distribution with mean \(50 \mathrm{lb}\) and variance \(1 \mathrm{lb}^{2}\). Let \(\bar{x}\) be the sample mean weight \((n=100)\). a. Describe the sampling distribution of \(\bar{x}\). b. What is the probability that the sample mean is between \(49.75 \mathrm{lb}\) and \(50.25 \mathrm{lb}\) ? c. What is the probability that the sample mean is less than \(50 \mathrm{lb}\) ?

The nicotine content in a single cigarette of a particular brand has a distribution with mean \(0.8 \mathrm{mg}\) and standard deviation \(0.1 \mathrm{mg}\). If 100 of these cigarettes are analyzed, what is the probability that the resulting sample mean nicotine content will be less than \(0.79 ?\) less than \(0.77\) ?

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