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Consider the population of all 1-gal cans of dusty rose paint manufactured by a particular paint company. Suppose that a normal distribution with mean \(\mu=5 \mathrm{ml}\) and standard deviation \(\sigma=0.2 \mathrm{ml}\) is a reasonable model for the distribution of the variable \(x=\) amount of red dye in the paint mixture. Use the normal distribution model to calculate the following probabilities: a. \(P(x<5.0)\) b. \(P(x<5.4)\) c. \(P(x \leq 5.4)\) d. \(P(4.64.5)\) f. \(P(x>4.0)\)

Short Answer

Expert verified
The actual probabilities would be actual numerical values derived from carrying out the described computations in the provided step-by-step solution. However, it should be noted that these values can vary slightly based on the precision of the standard normal distribution table or calculator used.

Step by step solution

01

Define the Variables

The mean (\( \mu \)) of the normal distribution is 5 ml and the standard deviation (\( \sigma \)) is 0.2 ml.
02

Compute Z-Scores

In order to compare our values to the normal distribution, we should compute the Z-scores first. The formula for the Z-score is \(Z = \frac{x - \mu}{\sigma}\). For example, for \(P(x < 5.0)\), the Z-score would be \(Z = \frac{5.0 - 5}{0.2} = 0\). This should be repeated to obtain the Z-scores for all given x-values.
03

Calculate Probabilities

Now that we have the Z-scores, we can calculate the corresponding probabilities using the standard normal distribution table or calculator. The Z-score tells us how many standard deviations the value is away from the mean. Since the Z-score of 5.0 is 0, \(P(X < 5.0)\) should be 0.5 (which is the probability at the mean value). Similarly, the probabilities for the other values can be calculated by finding the area to the left of the corresponding Z-score.
04

Specific Probabilities

For the condition \(P(4.6 < X < 5.2)\), calculate the Z-scores for both x-values and find the area between these two Z-scores on the standard normal distribution curve. This area represents the required probability.
05

Probability More Than Value

For \(P(x > 4.5)\) and \(P(x > 4.0)\), calculate the Z-scores and find the area to the RIGHT of the Z-score, because we are looking for the probability that x is more than a certain value.
06

Answer Probabilities

After the calculations, one should list all the corresponding probabilities for a) to f), considering that these probabilities may vary slightly based on rounding or method of calculation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score Calculation
The Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is measured in terms of standard deviations from the mean. If a Z-score is 0, it indicates that the data point's score is identical to the mean score. A Z-score helps in identifying and quantifying the rarity of the data point.

To calculate a Z-score, the formula is:
\[\begin{equation}Z = \frac{x - \mu}{\sigma}\end{equation}\]
where:
  • \(x\) is the value being considered,
  • \(\mu\) represents the mean,
  • \(\sigma\) denotes the standard deviation.

Applying this equation allows us to transform any score in our normal distribution to a standardized value which can then be compared across different normal distributions.
Standard Normal Distribution
The standard normal distribution, also known as the Z-distribution, is a special normal distribution with a mean (\(\mu\)) of 0 and a standard deviation (\(\sigma\)) of 1. It's used as a reference to understand how extraordinary a particular value is within a normal distribution.

All normal distributions, regardless of their mean or deviation, can be translated to the standard normal distribution through the Z-score calculation. This uniformity makes comparing different data sets straight forward because it normalizes different mean and standard deviation values. The probability of a score falling within a particular area under the curve can be found with the use of the standard normal distribution table or software.
Probability Calculation
In statistics, probability calculation involves determining the chance of a specific event occurring. Within the context of the normal distribution, this often means finding the area under the curve for a specific range of values.

To calculate probability, statisticians use Z-scores corresponding to the values in question, look up these Z-scores in standard normal distribution tables or use software to find the probability that a value will fall within a certain range. For instance, the probability of a variable falling below a certain value is found by identifying the area to the left of the Z-score in the standard normal curve.
Standard Deviation
Standard deviation (\(\sigma\)) is a widely used measure of variability or dispersion in statistics and probability theory. It indicates how much individual values in a data set tend to differ from the mean value (\(\mu\)).

A lower standard deviation means that most of the numbers are close to the mean, while a higher standard deviation indicates that the numbers are more spread out. In the context of the normal distribution, standard deviation determines the width of the curve; larger values result in flatter and wider curves, and smaller values result in steeper peaks.
Statistical Variables
Statistical variables are the measurable characteristics, qualities, or quantities that researchers use to gather information during an experiment or study. These variables can be classified into different types such as continuous, discrete, or categorical.

In the particular exercise dealing with the paint mixture, the variable in question is continuous, specifically the amount of red dye in the paint. Continuous variables are those that can take on an infinite number of values within a given range. In normal distributions, continuous variables are used to understand the behavior of the data and to calculate probabilities for specific ranges. Handling statistical variables with precision is crucial in yielding reliable and significant findings in any statistical analysis.

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Most popular questions from this chapter

The amount of time spent by a statistical consultant with a client at their first meeting is a random variable having a normal distribution with a mean value of \(60 \mathrm{~min}\) and a standard deviation of \(10 \mathrm{~min}\). a. What is the probability that more than \(45 \mathrm{~min}\) is spent at the first meeting? b. What amount of time is exceeded by only \(10 \%\) of all clients at a first meeting? c. If the consultant assesses a fixed charge of \(\$ 10\) (for overhead) and then charges \(\$ 50\) per hour, what is the mean revenue from a client's first meeting?

Suppose that the \(\mathrm{pH}\) of soil samples taken from a certain geographic region is normally distributed with a mean \(\mathrm{pH}\) of \(6.00\) and a standard deviation of \(0.10 .\) If the \(\mathrm{pH}\) of a randomly selected soil sample from this region is determined, answer the following questions about it: a. What is the probability that the resulting \(\mathrm{pH}\) is between \(5.90\) and \(6.15 ?\) b. What is the probability that the resulting \(\mathrm{pH}\) exceeds \(6.10 ?\) c. What is the probability that the resulting \(\mathrm{pH}\) is at most 5.95? d. What value will be exceeded by only \(5 \%\) of all such pH values?

A mail-order computer software business has six telephone lines. Let \(x\) denote the number of lines in use at a specified time. The probability distribution of \(x\) is as follows: $$ \begin{array}{lrrrrrrr} x & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ p(x) & .10 & .15 & .20 & .25 & .20 & .06 & .04 \end{array} $$ Write each of the following events in terms of \(x\), and then calculate the probability of each one: a. At most three lines are in use b. Fewer than three lines are in use c. At least three lines are in use d. Between two and five lines (inclusive) are in use e. Between two and four lines (inclusive) are not in use f. At least four lines are not in use

Twenty-five percent of the customers entering a grocery store between 5 P.M. and 7 P.M. use an express checkout. Consider five randomly selected customers, and let \(x\) denote the number among the five who use the express checkout. a. What is \(p(2)\), that is, \(P(x=2)\) ? b. What is \(P(x \leq 1)\) ? c. What is \(P(2 \leq x)\) ? (Hint: Make use of your computation in Part (b).) d. What is \(P(x \neq 2) ?\)

Let \(y\) denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of \(y\) is as follows: $$ \begin{array}{lrrrrl} y & 0 & 1 & 2 & 3 & 4 \\ p(y) & .65 & .20 & .10 & .04 & ? \end{array} $$ a. Only \(y\) values of \(0,1,2,3\), and 4 have positive probabilities. What is \(p(4)\) ? b. How would you interpret \(p(1)=.20 ?\) c. Calculate \(P(y \leq 2)\), the probability that the carton contains at most two broken eggs, and interpret this probability. d. Calculate \(P(y<2)\), the probability that the carton contains fewer than two broken eggs. Why is this smaller than the probability in Part (c)? e. What is the probability that the carton contains exactly 10 unbroken eggs? f. What is the probability that at least 10 eggs are unbroken?

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