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A Gallup survey of 2002 adults found that \(46 \%\) of women and \(37 \%\) of men experience pain daily (San Luis Obispo Tribune, April 6, 2000). Suppose that this information is representative of U.S. adults. If a U.S. adult is selected at random, are the events selected adult is male and selected adult experiences pain daily independent or dependent? Explain.

Short Answer

Expert verified
Therefore, the events 'selected adult is male' and 'selected adult experiences pain daily' are not independent but dependent because \(P(Man \cap Pain) \neq P(Man) \times P(Pain)\). Thus, the occurrence of one event does affect the occurrence of the other.

Step by step solution

01

Understand the Data

From the survey, \(46 \%\) of women and \(37 \%\) of men experience pain daily. It is not directly given the proportion of men and women in the population. It's most commonly accepted to assume a \(50-50\) split. As a result, the probability that a randomly selected adult experiences pain daily \(P(Pain)\) would be the average of \(46 \%\) and \(37 \%\), i.e. \(41.5 \%\). Moreover, the probability of selecting a man \(P(Man)\) will be \(50 \%\) from our assumption.
02

Calculate the Joint Probability

Based on the survey, \(37 \%\) of men experience pain daily. This can be seen as the joint probability of the two events (being male and experiencing pain) and thus, this will be our \(P(Man \cap Pain)\), which is equal to \(37 \% \).
03

Check for Independence

Two events A and B are independent if \(P(A \cap B) = P(A) \times P(B)\). In our case, we check if \(P(Man \cap Pain)= P(Man) \times P(Pain)\). If this is true, the events are independent. If not, they are dependent. Replacing the values, we need to check if \(37 \% = 50 \% \times 41.5 \%\). After performing the multiplication, we see that \(50 \% \times 41.5 \% = 20.75 \% \) which is not equal to \(37 \% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the branch of mathematics concerned with analyzing random phenomena and modeling uncertainty. It provides a framework for quantifying the likelihood of various outcomes, enabling us to make predictions about events that involve chance.

When a Gallup survey indicates that a certain percentage of a population experiences a specific outcome, such as daily pain, it applies probability theory by presenting the results in terms of percentages—a form of probability. For instance, saying that 46% of women experience pain daily is interpreted as having a probability of 0.46 when a woman is randomly selected from the U.S. adult population.

Understanding such data requires an appreciation for the fundamental rule that the total probability equals one—representing certainty—and the probabilities of all possible outcomes must add up to one. This is instrumental in evaluating survey data which, like the example given, often represents a fraction of a population's experience.
Joint Probability
Joint probability is a measure of two events happening at the same time and is denoted as the probability of the intersection of two events, symbolically represented as \( P(A \cap B) \). It assumes a value between 0 and 1, where 0 indicates that two events never occur together, and 1 implies they always occur simultaneously.

In the survey's context, the joint probability refers to the likelihood of an adult being both male and experiencing pain daily. The calculation of this joint probability is crucial for determining whether the events are independent or dependent. For example, according to the step-by-step solution provided, the joint probability \( P(Man \cap Pain) \) is given as 37%, derived directly from the survey's findings for men.
Survey Data Analysis
Survey data analysis involves processing and interpreting data collected from surveys to draw meaningful conclusions. It can be complex, requiring careful consideration of the survey design, sampling methods, and statistical techniques.

In applying survey data to probability questions, it is essential to ensure the data is representative of the population in question. As suggested in the solution steps provided, sometimes assumptions must be made, such as a 50-50 gender split when specific information is not given. However, it is these very assumptions that can impact the analysis's accuracy, and understanding their effects is crucial in drawing reliable conclusions, especially when inferring the independence or dependence of events in a population.

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Most popular questions from this chapter

According to a study released by the federal Substance Abuse and Mental Health Services Administration (Knight Ridder Tribune, September 9,1999 ), approximately \(8 \%\) of all adult full-time workers are drug users and approximately \(70 \%\) of adult drug users are employed full-time. a. Is it possible for both of the reported percentages to be correct? Explain. b. Define the events \(D\) and \(E\) as \(D=\) event that a randomly selected adult is a drug user and \(E=\) event that a randomly selected adult is employed full- time. What are the estimated values of \(P(D \mid E)\) and \(P(E \mid D) ?\) c. Is it possible to determine \(P(D)\), the probability that a randomly selected adult is a drug user, from the information given? If not, what additional information would be needed?

A company uses three different assembly lines \(-A_{1}\), \(A_{2}\), and \(A_{3}-\) to manufacture a particular component. Of those manufactured by \(A_{1}, 5 \%\) need rework to remedy a defect, whereas \(8 \%\) of \(A_{2}\) 's components and \(10 \%\) of \(A_{3}\) 's components need rework. Suppose that \(50 \%\) of all components are produced by \(A_{1}\), whereas \(30 \%\) are produced by \(A_{2}\) and \(20 \%\) come from \(A_{3} .\) a. Construct a tree diagram with first-generation branches corresponding to the three lines. Leading from each branch, draw one branch for rework (R) and another for no rework (N). Then enter appropriate probabilities on the branches. b. What is the probability that a randomly selected component came from \(A_{1}\) and needed rework? c. What is the probability that a randomly selected component needed rework?

USA Today (June 6,2000 ) gave information on seat belt usage by gender. The proportions in the following table are based on a survey of a large number of adult men and women in the United States: $$ \begin{array}{l|cc} \hline & \text { Male } & \text { Female } \\ \hline \text { Uses Seat Belts Regularly } & .10 & .175 \\ \begin{array}{l} \text { Does Not Use Seat Belts } \\ \text { Regularly } \end{array} & .40 & .325 \\ \hline \end{array} $$ Assume that these proportions are representative of adults in the United States and that a U.S. adult is selected at random. a. What is the probability that the selected adult regularly uses a seat belt? b. What is the probability that the selected adult regularly uses a seat belt given that the individual selected is male? c. What is the probability that the selected adult does not use a seat belt regularly given that the selected individual is female? d. What is the probability that the selected individual is female given that the selected individual does not use a seat belt regularly? e. Are the probabilities from Parts (c) and (d) equal? Write a couple of sentences explaining why this is so.

Suppose that, starting at a certain time, batteries coming off an assembly line are examined one by one to see whether they are defective (let \(\mathrm{D}=\) defective and \(\mathrm{N}=\) not defective). The chance experiment terminates as soon as a nondefective battery is obtained. a. Give five possible experimental outcomes. b. What can be said about the number of outcomes in the sample space? c. What outcomes are in the event \(E\), that the number of batteries examined is an even number?

The article "Checks Halt over 200,000 Gun Sales" (San Luis Obispo Tribune, June 5,2000 ) reported that required background checks blocked 204,000 gun sales in 1999\. The article also indicated that state and local police reject a higher percentage of would-be gun buyers than does the FBI, stating, "The FBI performed \(4.5\) million of the \(8.6\) million checks, compared with \(4.1\) million by state and local agencies. The rejection rate among state and local agencies was 3 percent, compared with \(1.8\) percent for the FBI" a. Use the given information to estimate \(P(F), P(S)\), \(P(R \mid F)\), and \(P(R \mid S)\), where \(F=\) event that a randomly selected gun purchase background check is performed by the FBI, \(S=\) event that a randomly selected gun purchase background check is performed by a state or local agency, and \(R=\) event that a randomly selected gun purchase background check results in a blocked sale. b. Use the probabilities from Part (a) to evaluate \(P(S \mid R)\), and write a sentence interpreting this value in the context of this problem.

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