Suppose that a six-sided die is "loaded" so that any particular even-numbered
face is twice as likely to be observed as any particular odd-numbered face.
a. What are the probabilities of the six simple events? (Hint: Denote these
events by \(O_{1}, \ldots, O_{6}\). Then \(P\left(O_{1}\right)=p\),
\(P\left(O_{2}\right)=2 p, P\left(O_{3}\right)=p, \ldots, P\left(O_{6}\right)=2
p .\) Now use a condi-
tion on the sum of these probabilities to determine \(p .\) )
b. What is the probability that the number showing is an odd number? at most
\(3 ?\)
c. Now suppose that the die is loaded so that the probability of any
particular simple event is proportional to the number showing on the
corresponding upturned face; that is, \(P\left(O_{1}\right)=c,
P\left(O_{2}\right)=2 c, \ldots, P\left(O_{6}\right)=6 c .\) What are the
probabilities of the six simple events? Calculate the probabilities of Part
(b) for this die.