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The accompanying data resulted from a flammability study in which specimens of five different fabrics were tested to determine burn times. $$\begin{array}{lllllll} & \mathbf{1} & 17.8 & 16.2 & 15.9 & 15.5 & \\ & \mathbf{2} & 13.2 & 10.4 & 11.3 & & \\ \text { Fabric } & \mathbf{3} & 11.8 & 11.0 & 9.2 & 10.0 & \\ & \mathbf{4} & 16.5 & 15.3 & 14.1 & 15.0 & 13.9 \\ & \mathbf{5} & 13.9 & 10.8 & 12.8 & 11.7 & \end{array}$$ \(\begin{aligned} \mathrm{MSTr} &=23.67 \\ \mathrm{MSE} &=1.39 \\ F &=17.08 \\ P \text { -value } &=.000 \end{aligned}\) The accompanying output gives the T-K intervals as calculated by MINITAB. Identify significant differences and give the underscoring pattern. $$\begin{array}{lrrr} & 1 & 2 & 3 & 4 \\ 2 & 1.938 & & & \\ & 7.495 & & & \\ 3 & 3.278 & -1.645 & & \\ & 8.422 & 3.912 & & \\ 4 & 3.830 & -0.670 & -2.020 & \\ & 1.478 & -3.445 & -4.372 & 0.220 \\ 5 & 6.622 & 2.112 & 0.772 & 5.100 \end{array}$$

Short Answer

Expert verified
There are significant differences among the five fabrics' burn times according to the ANOVA results. Fabrics 1 and 5 are significantly different from the others according to the Tukey-Kramer intervals. The underscoring pattern can be represented as: Fabric 1: __, Fabric 2: _, Fabric 3: _, Fabric 4: __, Fabric 5: ____.

Step by step solution

01

Understand Provided ANOVA Results

The first step is to understand the provided ANOVA results. The mean sum of squares due to treatment (\(MSTr\)) is 23.67, while the mean sum of squares due to error (\(MSE\)) is 1.39. The F statistic is 17.08 and the P value is 0. This indicates that there are significant differences among the group means because the P value is less than 0.05.
02

Interpretation of T-K Intervals

The second step is to interpret the provided Tukey-Kramer (T-K) intervals. A fabric is significantly different from another if their interval does not contain zero. For example, the interval for fabric 1 and 2 (1.938 to 7.495) does not contain zero, which means fabric 1 and 2 are significantly different. But the interval for fabric 2 and 4 (-0.670 to -2.020) does contain zero, so there's no significant difference between fabric 2 and 4.
03

Identify UnderScoring Pattern

Finally, the underscoring pattern represents the significant differences among the groups. Fabrics that have significant differences receive different underscores. Based on the T-K intervals interpreted in the previous step, the underscoring pattern would be: Fabric 1: __, Fabric 2: _, Fabric 3: _, Fabric 4: __, Fabric 5: ____.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Sum of Squares
The 'mean sum of squares’ (often abbreviated as MSS) is a critical component in the ANOVA flammability study that helps us understand the variability within a set of data points. To envision this, imagine how different fabrics may resist flames differently, so when subjected to burning, each type will take various times to burn. The MSS can be calculated for both the treatments (MSTr) and the error (MSE).

Specifically, the MSTr reflects the variance between the group means (comparing the burn times across different fabrics), while the MSE reflects the variance within the groups (the burn times within a single fabric type). A large MSTr relative to MSE, as we see in the study with an F statistic of 17.08, suggests that not all fabrics behave the same when lit – some are more flammable than others. Therefore, the MSS is a foundational marker in discerning significant differences between fabric types in this study.
Tukey-Kramer Intervals
One method of comparing means from multiple treatments is through the use of 'Tukey-Kramer (T-K) intervals'. These intervals help us to determine if the differences observed in mean burn times between any two fabrics are statistically significant or just due to random chance.

In simple terms, a T-K interval that does not cross zero indicates that the two fabrics have significantly different mean burn times; these are fabrics we would not group together when considering flammability. On the other hand, intervals spanning zero show no significant difference, indicating similar flammability characteristics. Through careful inspection of these intervals, we can separate fabrics into categories based on their similarity in burn time and evaluate which fabrics might be more suitable for certain applications where fire resistance is a concern.
F Statistic
The 'F statistic' is a number obtained during an ANOVA test and is used to compare variances. It's calculated by dividing MSTr by MSE, and it tells us whether the treatment factor (in this case, different fabric types) has a significant effect. A high F statistic, as obtained in this study (F=17.08), is a beacon that alerts us – the chance that all fabric types have identical average burn times is so low that we should reject this assumption.

Essentially, the F statistic serves as a way to judge whether observed differences in an experiment are due to the treatment effects or merely by chance. Its value acts as a guide, steering the analysis towards investigating specific differences between group means with confidence.
P-value Analysis
Lastly, the 'P-value' offers a threshold to decide if our findings from the experiment can be deemed significant. Traditionally, a P-value of less than 0.05 is considered the tipping point. In our flammability study, the P-value is .000, which falls far below the conventional line. This whispers to us a message loud and clear – coincidence is not at play here; rather, the fabric types do, in fact, have significantly different burn times.

The P-value, in essence, tells us the probability of observing our results (or something more extreme) if, in the realm of theoretical mathematics, the fabrics would have identical resistance to fire. The closer this value is to zero, the stronger the evidence against this world of sameness, prompting us to confidently assert the reality of variation among fabric types.

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Most popular questions from this chapter

An investigation carried out to study purchasers of luxury automobiles reported data on a number of different attributes that might affect purchase decisions, including comfort, safety, styling, durability, and reliability ("Measuring Values Can Sharpen Segmentation in the Luxury Car Market," Journal of Advertising Research \([1995]: 9-\) 22). Here is summary information on the level of importance of speed, rated on a seven-point scale: $$ \begin{array}{lccc} \text { Type of Car } & \text { American } & \text { German } & \text { Japanese } \\ \hline \text { Sample size } & 58 & 38 & 59 \\ \text { Sample mean rating } & 3.05 & 2.87 & 2.67 \end{array} $$ In addition, \(\mathrm{SSE}=459.04\). Carry out a hypothesis test to determine if there is sufficient evidence to conclude that the mean importance rating of speed is not the same for owners of these three types of cars.

Give as much information as you can about the \(P\) -value of the single-factor ANOVA \(F\) test in each of the following situations. a. \(k=5, n_{1}=n_{2} \equiv n_{3}=n_{4}=n_{5}=4, F=5.37\) b. \(k=5, n_{1}=n_{2}=n_{3}=5, n_{4}=n_{5}=4, F=2.83\) c. \(k=3, n_{1}=4, n_{2}=5, n_{3}=6, F=5.02\) d. \(k=3, n_{1}=n_{2}=4, n_{3}=6, F=15.90\) e. \(k=4, n_{1}=n_{2}=15, n_{3}=12, n_{4}=10, F=1.75\)

The article "Growth Response in Radish to Sequential and Simultaneous Exposures of \(\mathrm{NO}_{2}\) and \(\mathrm{SO}_{2} "(\) Environmental Pollution \([1984]: 303-325\) ) compared a control group (no exposure), a sequential exposure group (plants exposed to one pollutant followed by exposure to the second four weeks later), and a simultaneous-exposure group (plants exposed to both pollutants at the same time). The article states, "Sequential exposure to the two pollutants had no effect on growth compared to the control. Simultaneous exposure to the gases significantly reduced plant growth." Let \(\bar{x}_{1}, \bar{x}_{2}\), and \(\bar{x}_{3}\) represent the sample means for the control, sequential, and simultaneous groups, respectively. Suppose that \(\bar{x}_{1}>\bar{x}_{2}>\bar{x}_{3}\). Use the given information to construct a table where the sample means are listed in increasing order, with those that are judged not to be significantly different underscored. \(15.30\) The nutritional quality of shrubs commonly used for feed by rabbits was the focus of a study summarized in the article "Estimation of Browse by Size Classes for Snowshoe Hare" (Journal of Wildlife Management [1980]: \(34-40\) ). The energy content \((\mathrm{cal} / \mathrm{g})\) of three sizes \((4 \mathrm{~mm}\) or less, \(5-7 \mathrm{~mm}\), and \(8-10 \mathrm{~mm}\) ) of serviceberries was studied. Let \(\mu_{1}, \mu_{2}\), and \(\mu_{3}\) denote the true energy content for the three size classes. Suppose that \(95 \%\) simultaneous confidence intervals for \(\mu_{1}-\mu_{2}, \mu_{1}-\mu_{3}\), and \(\mu_{2}-\mu_{3}\) are \((-10,290),(150,450)\), and \((10,310)\), respectively. How would you interpret these intervals?

Consider the accompanying data on plant growth after the application of different types of growth hormone. $$\begin{array}{llrlrl} & \mathbf{1} & 13 & 17 & 7 & 14 \\ & \mathbf{2} & 21 & 13 & 20 & 17 \\ \text { Hormone } & \mathbf{3} & 18 & 14 & 17 & 21 \\ & \mathbf{4} & 7 & 11 & 18 & 10 \\ & \mathbf{5} & 6 & 11 & 15 & 8 \end{array}$$ a. Carry out the \(F\) test at level \(\alpha=.05\). b. What happens when the T-K procedure is applied? (Note: This "contradiction" can occur when is "barely" rejected. It happens because the test and the multiple comparison method are based on different distributions. Consult your friendly neighborhood statistician for more information.)

Do lizards play a role in spreading plant seeds? Some research carried out in South Africa would suggest so ("Dispersal of Namaqua Fig (Ficus cordata cordata) Seeds by the Augrabies Flat Lizard (Platysaurus broadleyi)," Journal of Herpetology [1999]: \(328-330\) ). The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5 , and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. $$\begin{array}{lccc} \text { Treatment } & \boldsymbol{n} & \overline{\boldsymbol{x}} & \boldsymbol{s} \\ \hline \text { Uneaten figs } & 20 & 2.40 & .30 \\ \text { Lizard dung } & 20 & 2.35 & .33 \\ \text { Bird dung } & 20 & 1.70 & .34 \\ \text { Hyrax dung } & 20 & 1.45 & .28 \end{array}$$ a. Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between mean number of seeds germinating for the four treatments. b. Is there evidence that seeds eaten and then excreted by lizards germinate at a higher rate than those eaten and then excreted by birds? Give statistical evidence to sup- port your answer.

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