Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The article "The Caseload Controversy and the Study of Criminal Courts" (Journal of Criminal Law and Criminology [1979]: 89-101) used a multiple regression analysis to help assess the impact of judicial caseload on the processing of criminal court cases. Data were collected in the Chicago criminal courts on the following variables: $$ \begin{aligned} y &=\text { number of indictments } \\ x_{1} &=\text { number of cases on the docket } \end{aligned} $$ \(x_{2}=\) number of cases pending in criminal court trial system The estimated regression equation (based on \(n=367\) observations) was $$ \hat{y}=28-.05 x_{1}-.003 x_{2}+.00002 x_{3} $$ where \(x_{3}=x_{1} x_{2}\) a. The reported value of \(R^{2}\) was . 16. Conduct the model utility test. Use a \(.05\) significance level. b. Given the results of the test in Part (a), does it surprise you that the \(R^{2}\) value is so low? Can you think of a possible explanation for this? c. How does adjusted \(R^{2}\) compare to \(R^{2}\) ?

Short Answer

Expert verified
The model utility test verifies whether the regression model is useful based on its F statistic and comparing with the F-critical value. The low \(R^{2}\) value could suggest that the predictors are weakly related to the dependent variable or missing important predictors. The comparison of \(R^{2}\) and adjusted \(R^{2}\) examines the contribution of predictors. While the former always increases when more predictors are included, the latter will decrease if new predictors don't significantly improve the model.

Step by step solution

01

model utility test

In order to conduct the model utility test, we must check if the Regression Model would be useful to predict the response. In multiple regression, the null hypothesis \(H_{0}\): All regression coefficients are equal to zero. And the alternative hypothesis \(H_{a}\): At least one regression coefficient is not zero. Since we are given an \(R^{2}\) of 0.16 and a significance level of 0.05, we can calculate the F statistic using the formula \(F = R^{2}/(1-R^{2}) * (n-p-1)/p\), where n is the number of observations and p is the number of predictors. Then, we must check if the calculated F-value is greater than the F-critical value from the F-distribution table for the given significance level. If it's greater then we reject the null hypothesis suggesting our model is useful.
02

Interpret the result from Step 1

Based on the result of the F-test in Step 1, interpret the outcome. If you reject the null hypothesis, it means that at least one predictor variable's coefficient is not zero, which suggests that the model has some predictive power. If we fail to reject the null hypothesis, it indicates that the model has no predictive power.
03

Discuss the \(R^{2}\) value

After the model utility test, discuss why the \(R^{2}\) value, which represents the proportion of the variance for a dependent variable that's explained by an independent variable(s), could be low. This could be due to a weak relationship between predictors and the dependent variable, or that important predictors are missing.
04

Compare \(R^{2}\) and adjusted \(R^{2}\)

Adjusted \(R^{2}\) takes into account the number of predictors in the model, adjusting for the increase of \(R^{2}\) when additional predictors are included. While \(R^{2}\) always increases as more predictors are added, adjusted \(R^{2}\) could decrease if the addition of the predictor doesn't significantly improve the model. When comparing these two, if both values are close it means the predictors all contribute to the model. Conversely, if the adjusted \(R^{2}\) is much lower than \(R^{2}\), some predictors may not be contributing to the model.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Model Utility Test
The model utility test in multiple regression analysis is critical for understanding the overall significance of the model. It is, essentially, a hypothesis test that checks whether there is a statistically significant relationship between the response variable and the set of predictors.

The null hypothesis (\(H_{0}\)) typically states that none of the predictor variables is significantly related to the output variable—implying that all regression coefficients are equal to zero. On the other hand, the alternative hypothesis (\(H_{a}\)) asserts that at least one of the coefficients is not zero. To perform this test, statisticians usually use the F-statistic, a value derived from an F-distribution that compares the explained variance of the model against the unexplained variance.

If the calculated F-statistic is greater than the critical value from the F-distribution table at a certain significance level (commonly, 0.05), it justifies rejecting the null hypothesis. This means our regression model does provide a better fit to the data than a model with no predictors at all. Correspondingly, if the F-statistic is lower than the critical value, there's no statistical evidence to claim that our model is useful.
R-squared (\rR^2)
The R-squared (\(R^2\)) value is a popular statistic used to gauge the effectiveness of a regression model. It represents the proportion of variance in the dependent variable that can be explained by the independent variables in the model. In other words, it measures the strength of the relationship between the model and the dependent variable on a scale from 0 to 1, where a higher value typically suggests a better model fit.

However, one must be cautious; a higher R-squared does not necessarily indicate that the model is the best. It simply tells us how much of the variability in the dependent variable our model can explain. Still, a low R-squared—as in the exercise where it was reported to be 0.16—could imply a weak relationship between the variables or that key predictors might be missing from the model, leading to questions about the model's predictive power.
Adjusted R-squared
While the R-squared value can give us a quick indication of a model's explanatory power, it has a significant limitation: it can increase simply by adding more predictors, regardless of whether they are meaningful to the model. This is where Adjusted R-squared comes into play.

The Adjusted R-squared adjusts the R-squared value for the number of predictors in the model, penalizing for adding predictors that do not improve the model. This statistic is particularly useful when comparing models with a different number of predictors. If we have a model where the adjusted R-squared is substantially lower than the R-squared, it might indicate that some predictors are not contributing to the model and could be removed.

Comparing R-squared and Adjusted R-squared helps to ensure that our model is not just fitting the data better because we've added more variables, but because the variables we've added truly carry explanatory power.
F-statistic
The F-statistic plays a central role in conducting the model utility test discussed earlier. It is calculated from an ANOVA (analysis of variance) and is used to compare model fits—essentially, whether any of the independent variables, when taken together, are related to the dependent variable.

The formula to calculate it is relatively straightforward: \[ F = \frac{R^{2} / p}{(1-R^{2}) / (n - p - 1)} \] where 'p' is the number of predictors and 'n' is the total sample size. Once the F-statistic is determined, it is compared with a critical value from an F-distribution table. A high F-statistic, which indicates a significant amount of variance explained by the model relative to the amount of unexplained variance, leads to the rejection of the null hypothesis—acknowledging that the regression model provides a better fit than the intercept-only model.

Understanding the F-statistic helps in validating the effectiveness of the model and ensuring that the results of the regression analysis are reliable and not due to random chance.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A number of investigations have focused on the problem of assessing loads that can be manually handled in a safe manner. The article "Anthropometric, Muscle Strength, and Spinal Mobility Characteristics as Predictors in the Rating of Acceptable Loads in Parcel Sorting" (Ergonomics [1992]: \(1033-1044\) ) proposed using a regression model to relate the dependent variable \(y=\) individual's rating of acceptable load \((\mathrm{kg})\) to \(k=3\) independent (predictor) variables: \(x_{1}=\) extent of left lateral bending \((\mathrm{cm})\) $$ \begin{aligned} &x_{2}=\text { dynamic hand grip endurance (sec) } \\ &x_{3}=\text { trunk extension ratio }(\mathrm{N} / \mathrm{kg}) \end{aligned} $$ Suppose that the model equation is $$ y=30+.90 x_{1}+.08 x_{2}-4.50 x_{3}+e $$ and that \(\sigma=5\). a. What is the population regression function? b. What are the values of the population regression \(\underline{\mathrm{co}}\) efficients? c. Interpret the value of \(\beta_{1}\). d. Interpret the value of \(\beta_{3}\). e. What is the mean value of rating of acceptable load when extent of left lateral bending is \(25 \mathrm{~cm}\), dynamic hand grip endurance is \(200 \mathrm{sec}\), and trunk extension ratio is \(10 \mathrm{~N} / \mathrm{kg}\) ? f. If repeated observations on rating are made on different individuals, all of whom have the values of \(x_{1}, x_{2}\), and \(x_{3}\) specified in Part (e), in the long run approximately what percentage of ratings will be between \(13.5 \mathrm{~kg}\) and \(33.5 \mathrm{~kg} ?\)

Explain the difference between a deterministic and a probabilistic model. Give an example of a dependent variable \(y\) and two or more independent variables that might be related to \(y\) deterministically. Give an example of a dependent variable \(y\) and two or more independent variables that might be related to \(y\) in a probabilistic fashion.

Suppose that the variables \(y, x_{1}\), and \(x_{2}\) are related by the regression model $$ y=1.8+.1 x_{1}+.8 x_{2}+e $$ a. Construct a graph (similar to that of Figure \(14.5)\) showing the relationship between mean \(y\) and \(x_{2}\) for fixed values 10,20 , and 30 of \(x_{1}\). b. Construct a graph depicting the relationship between mean \(y\) and \(x_{1}\) for fixed values 50,55, and 60 of \(x_{2}\). c. What aspect of the graphs in Parts (a) and (b) can be attributed to the lack of an interaction between \(x_{1}\) and \(x_{2}\) ? d. Suppose the interaction term \(.03 x_{3}\) where \(x_{3}=x_{1} x_{2}\) is added to the regression model equation. Using this new model, construct the graphs described in Parts (a) and (b). How do they differ from those obtained in Parts (a) and (b)?

When coastal power stations take in large quantities of cooling water, it is inevitable that a number of fish are drawn in with the water. Various methods have been designed to screen out the fish. The article "Multiple \(\mathrm{Re}-\) gression Analysis for Forecasting Critical Fish Influxes at Power Station Intakes" (Journal of Applied Ecology [1983]: 33-42) examined intake fish catch at an English power plant and several other variables thought to affect fish intake: $$ \begin{aligned} y &=\text { fish intake (number of fish) } \\ x_{1} &=\text { water temperature }\left({ }^{\circ} \mathrm{C}\right) \\ x_{2} &=\text { number of pumps running } \\ x_{3} &=\text { sea state }(\text { values } 0,1,2, \text { or } 3) \\ x_{4} &=\text { speed }(\text { knots }) \end{aligned} $$ Part of the data given in the article were used to obtain the estimated regression equation $$ \hat{y}=92-2.18 x_{1}-19.20 x_{2}-9.38 x_{3}+2.32 x_{4} $$ (based on \(n=26\) ). SSRegr \(=1486.9\) and SSResid = \(2230.2\) were also calculated. a. Interpret the values of \(b_{1}\) and \(b_{4}\). b. What proportion of observed variation in fish intake can be explained by the model relationship? c. Estimate the value of \(\sigma\). d. Calculate adjusted \(R^{2}\). How does it compare to \(R^{2}\) itself?

This exercise requires the use of a computer package. The cotton aphid poses a threat to cotton crops in Iraq. The accompanying data on \(y=\) infestation rate (aphids/100 leaves) \(x_{1}=\) mean temperature \(\left({ }^{\circ} \mathrm{C}\right)\) \(x_{2}=\) mean relative humidity appeared in the article "Estimation of the Economic Threshold of Infestation for Cotton Aphid" (Mesopotamia Journal of Agriculture [1982]: 71-75). Use the data to find the estimated regression equation and assess the utility of the multiple regression model $$ y=\alpha+\beta_{1} x_{1}+\beta_{2} x_{2}+e $$ $$ \begin{array}{rrrrrr} \boldsymbol{y} & \boldsymbol{x}_{1} & \boldsymbol{x}_{2} & \boldsymbol{y} & \boldsymbol{x}_{1} & \boldsymbol{x}_{2} \\ \hline 61 & 21.0 & 57.0 & 77 & 24.8 & 48.0 \\ 87 & 28.3 & 41.5 & 93 & 26.0 & 56.0 \\ 98 & 27.5 & 58.0 & 100 & 27.1 & 31.0 \\ 104 & 26.8 & 36.5 & 118 & 29.0 & 41.0 \\ 102 & 28.3 & 40.0 & 74 & 34.0 & 25.0 \\ 63 & 30.5 & 34.0 & 43 & 28.3 & 13.0 \\ 27 & 30.8 & 37.0 & 19 & 31.0 & 19.0\\\ 14 & 33.6 & 20.0 & 23 & 31.8 & 17.0 \\ 30 & 31.3 & 21.0 & 25 & 33.5 & 18.5 \\ 67 & 33.0 & 24.5 & 40 & 34.5 & 16.0 \\ 6 & 34.3 & 6.0 & 21 & 34.3 & 26.0 \\ 18 & 33.0 & 21.0 & 23 & 26.5 & 26.0 \\ 42 & 32.0 & 28.0 & 56 & 27.3 & 24.5 \\ 60 & 27.8 & 39.0 & 59 & 25.8 & 29.0 \\ 82 & 25.0 & 41.0 & 89 & 18.5 & 53.5 \\ 77 & 26.0 & 51.0 & 102 & 19.0 & 48.0 \\ 108 & 18.0 & 70.0 & 97 & 16.3 & 79.5 \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free