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Consider a regression analysis with three independent variables \(x_{1}, x_{2}\), and \(x_{3}\). Give the equation for the following regression models: a. The model that includes as predictors all independent variables but no quadratic or interaction terms b. The model that includes as predictors all independent variables and all quadratic terms c. All models that include as predictors all independent variables, no quadratic terms, and exactly one interaction term d. The model that includes as predictors all independent variables, all quadratic terms, and all interaction terms (the full quadratic model)

Short Answer

Expert verified
a) \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3}\) \nb) \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{4}x_{1}^{2} + \beta_{5}x_{2}^{2} + \beta_{6}x_{3}^{2}\) \nc) Three alternatives: \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{4}x_{1}x_{2}\), \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{5}x_{1}x_{3}\), \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{6}x_{2}x_{3}\) \nd) \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{4}x_{1}^{2} + \beta_{5}x_{2}^{2} + \beta_{6}x_{3}^{2} + \beta_{7}x_{1}x_{2} + \beta_{8}x_{1}x_{3} + \beta_{9}x_{2}x_{3}\)

Step by step solution

01

Part (a): No quadratic or Interaction terms

Since no quadratic or interaction terms are needed, the equation would just include the predictors. The model would be: \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3}\)
02

Part (b): Quadratic terms

Now quadratic terms need to be included. A quadratic term is a variable squared. This gives the model: \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{4}x_{1}^{2} + \beta_{5}x_{2}^{2} + \beta_{6}x_{3}^{2}\)
03

Part (c): One Interaction term

Interaction terms are terms where variables multiply each other. Since only one interaction term should be included, three models need to be created for each possible pair. The models are: \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{4}x_{1}x_{2}\), \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{5}x_{1}x_{3}\), \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{6}x_{2}x_{3}\)
04

Part (d): Full Quadratic Model

A full quadratic model includes all interaction and quadratic terms. This yields the model: \(y = \beta_{0} + \beta_{1}x_{1} + \beta_{2}x_{2} + \beta_{3}x_{3} + \beta_{4}x_{1}^{2} + \beta_{5}x_{2}^{2} + \beta_{6}x_{3}^{2} + \beta_{7}x_{1}x_{2} + \beta_{8}x_{1}x_{3} + \beta_{9}x_{2}x_{3}\)

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Most popular questions from this chapter

The article "Pulp Brightness Reversion: Influence of Residual Lignin on the Brightness Reversion of Bleached Sulfite and Kraft Pulps" (TAPPI \([1964]: 653-662)\) proposed a quadratic regression model to describe the relationship between \(x=\) degree of delignification during the processing of wood pulp for paper and \(y=\) total chlorine content. Suppose that the actual model is $$ y=220+75 x-4 x^{2}+e $$ a. Graph the regression function \(220+75 x-4 x^{2}\) over \(x\) values between 2 and \(12 .\) (Substitute \(x=2,4,6,8,10\), and 12 to find points on the graph, and connect them with a smooth curve.) b. Would mean chlorine content be higher for a degree of delignification value of 8 or \(10 ?\) c. What is the change in mean chlorine content when the degree of delignification increases from 8 to \(9 ?\) From 9 to \(10 ?\)

A manufacturer of wood stoves collected data on \(y=\) particulate matter concentration and \(x_{1}=\) flue temperature for three different air intake settings (low, medium, and high). a. Write a model equation that includes dummy variables to incorporate intake setting, and interpret all the \(\beta \mathrm{co}\) efficients. b. What additional predictors would be needed to incorporate interaction between temperature and intake setting?

The article "Readability of Liquid Crystal Displays: A Response Surface" (Human Factors \([1983]: 185-190\) ) used a multiple regression model with four independent variables, where \(y=\) error percentage for subjects reading a four-digit liquid crystal display $$ \begin{aligned} &\left.x_{1}=\text { level of backlight (from } 0 \text { to } 122 \mathrm{~cd} / \mathrm{m}\right) \\ &x_{2}=\text { character subtense }\left(\text { from } .025^{\circ} \text { to } 1.34^{\circ}\right) \end{aligned} $$ \(x_{3}=\) viewing angle \(\left(\right.\) from \(0^{\circ}\) to \(60^{\circ}\) ) \(x_{4}=\) level of ambient light (from 20 to \(1500 \mathrm{~lx}\) ) The model equation suggested in the article is $$ y=1.52+.02 x_{1}-1.40 x_{2}+.02 x_{3}-.0006 x_{4}+e $$ a. Assume that this is the correct equation. What is the mean value of \(y\) when \(x_{1}=10, x_{2}=.5, x_{3}=50\), and \(x_{4}=100 ?\) b. What mean error percentage is associated with a backlight level of 20 , character subtense of \(.5\), viewing angle of 10, and ambient light level of 30 ? c. Interpret the values of \(\beta_{2}\) and \(\beta_{3}\)

The article "Readability of Liquid Crystal Displays: A Response Surface" (Human Factors [1983]: \(185-190\) ) used the estimated regression equation to describe the relationship between \(y=\) error percentage for subjects reading a four-digit liquid crystal display and the independent variables \(x_{1}=\) level of backlight, \(x_{2}=\) character subtense, \(x_{3}=\) viewing angle, and \(x_{4}=\) level of ambient light. From a table given in the article, SSRegr \(=19.2\), SSResid = \(20.0\), and \(n=30\). a. Does the estimated regression equation specify a useful relationship between \(y\) and the independent variables? Use the model utility test with a \(.05\) significance level. b. Calculate \(R^{2}\) and \(s_{e}\) for this model. Interpret these values. c. Do you think that the estimated regression equation would provide reasonably accurate predictions of error rate? Explain.

Obtain as much information as you can about the \(P\) -value for an upper-tailed \(F\) test in each of the following situations: a. \(\mathrm{df}_{1}=3, \mathrm{df}_{2}=15\), calculated \(F=4.23\) b. \(\mathrm{df}_{1}=4, \mathrm{df}_{2}=18\), calculated \(F=1.95\) c. \(\mathrm{df}_{1}=5, \mathrm{df}_{2}=20\), calculated \(F=4.10\) d. \(\mathrm{df}_{1}=4, \mathrm{df}_{2}=35\), calculated \(F=4.58\)

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