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A random sample of \(n=44\) individuals with a B.S. degree in accounting who started with a Big Eight accounting firm and subsequently changed jobs resulted in a sample mean time to change of \(35.02\) months and a sample standard deviation of \(18.94\) months ("The Debate over Post-Baccalaureate Education: One University's Experience," Issues in Accounting Education [1992]: 18-36). Can it be concluded that the true average time to change exceeds 2 years? Test the appropriate hypotheses using a significance level of \(.01\).

Short Answer

Expert verified
Yes, at a .01 level of significance, the data suggests that the average time it takes for individuals with a B.S. degree in accounting to change jobs is significantly more than 2 years.

Step by step solution

01

State the Hypotheses

Null Hypothesis \(H_0\): The average time to change accounting jobs is equal or less than 2 years, i.e., \(μ ≤ 24\). \n Alternative Hypothesis \(H_1\): The average time to change accounting jobs exceeds 2 years, i.e., \(μ > 24\). \n \(H_0\) and \(H_1\) are complementary to each other.
02

Assume Standard Distribution

Since the sample size is greater than 30 (\(n = 44\)), we'll use the standard normal (z) distribution for this hypothesis test. Calculate the test statistic using the formula: \[ z = \frac{\( \bar{x} - μ_0 \)}{\(s/\sqrt{n}\)} \] where \( \bar{x} = 35.02 \), \( μ_0 = 24 \), \( s = 18.94 \), and \( n = 44 \).
03

Calculate Test Statistic

Substitute the given values into the z-formula: \[ z = \frac{35.02 - 24}{18.94/ \sqrt{44}} = 4.60 \] The test statistic \(z = 4.60\) is greater than the critical z-value for a .01 level of significance (2.33).
04

Conclusion

Reject the null hypothesis \(H_0\) if the calculated z-value is greater than the critical z-value. In this case, as the calculated value \(4.60\) exceeds the critical z-value \(2.33\), therefore we reject the null hypothesis. Hence, it can be concluded that the true average time to change jobs for individuals with a B.S. degree in accounting significantly exceeds 2 years at a .01 level of significance.

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Most popular questions from this chapter

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week (Ipsos Reid, August 9,2005 ). The mean of the 1000 resulting observations was \(12.7\) hours. a. The sample standard deviation was not reported, but suppose that it was 5 hours. Carry out a hypothesis test with a significance level of \(.05\) to decide if there is convincing evidence that the mean time spent using the Internet by Canadians is greater than \(12.5\) hours. b. Now suppose that the sample standard deviation was 2 hours. Carry out a hypothesis test with a significance level of . 05 to decide if there is convincing evidence that the mean time spent using the Internet by Canadians is greater than \(12.5\) hours.

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