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The article "Americans Seek Spiritual Guidance on Web" (San Luis Obispo Tribune, October 12,2002 ) reported that \(68 \%\) of the general population belong to a religious community. In a survey on Internet use, \(84 \%\) of "religion surfers" (defined as those who seek spiritual help online or who have used the web to search for prayer and devotional resources) belong to a religious community. Suppose that this result was based on a sample of 512 religion surfers. Is there convincing evidence that the proportion of religion surfers who belong to a religious community is different from \(.68\), the proportion for the general population? Use \(\alpha=.05\).

Short Answer

Expert verified
To provide a short answer, the actual computation of the z score and P-value are necessary. After that, based on the comparison of the P-value to \(\alpha = 0.05\), we would know whether to reject or fail to reject the null hypothesis, and hence could conclude if there is convincing evidence that the proportion of religion surfers who belong to a religious community is different from \(0.68\), as that the proportion for the general population.

Step by step solution

01

State the Hypotheses

We start by stating the null and alternative hypotheses. The null hypothesis assumes no difference between the two proportions, while the alternative hypothesis states otherwise. Let \( p \) denote the proportion of 'religion surfers' who belong to a religious community.\n\nNull hypothesis \( H_0 \): \( p = 0.68 \)\nAlternative hypothesis \( H_a \): \( p ≠ 0.68 \)
02

Calculate the Test Statistic

We'll use the formula for the two-proportion z-test to find the z score:\n\n\[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \]\n\nwhere:\n\(\hat{p}\) is the sample proportion (0.84),\n\(p_0\) is the stated population proportion (0.68), and\n\(n\) is the sample size (512).\n\nCarrying out the calculation yields: \n\n\[ z = \frac{0.84 - 0.68}{\sqrt{\frac{0.68(1 - 0.68)}{512}}} \]
03

Find the P-value

Once we find the z score, we can determine the P-value, which is the probability under the null hypothesis of obtaining a z score as extreme as the one calculated. The P-value is found using a z-table or statistical software.
04

Draw Conclusion

We compare the P-value to the significance level, \(\alpha = 0.05\). \n\nIf the P-value is less than \(\alpha\), we reject the null hypothesis and conclude that the proportion of religion surfers belonging to a religious community is significantly different from that of the general population.\n\nOtherwise, if the P-value is greater than \(\alpha\), we fail to reject the null hypothesis, implying that the proportion for religion surfers may be equal to 0.68.

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Most popular questions from this chapter

Duck hunting in populated areas faces opposition on the basis of safety and environmental issues. The San Luis Obispo Telegram-Tribune (June 18,1991 ) reported the results of a survey to assess public opinion regarding duck hunting on Morro Bay (located along the central coast of California). A random sample of 750 local residents included 560 who strongly opposed hunting on the bay. Does this sample provide sufficient evidence to conclude that the majority of local residents oppose hunting on Morro Bay? Test the relevant hypotheses using \(\alpha=.01\).

Explain why the statement \(\bar{x}=50\) is not a legitimate hypothesis.

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