Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A television manufacturer claims that (at least) \(90 \%\) of its TV sets will need no service during the first 3 years of operation. A consumer agency wishes to check this claim, so it obtains a random sample of \(n=100\) purchasers and asks each whether the set purchased needed repair during the first 3 years after purchase. Let \(p\) be the sample proportion of responses indicating no repair (so that no repair is identified with a success). Let \(\pi\) denote the true proportion of successes for all sets made by this manufacturer. The agency does not want to claim false advertising unless sample evidence strongly suggests that \(\pi<.9 .\) The appropriate hypotheses are then \(H_{0}: \pi=.9\) versus \(H_{a}: \pi<.9\). a. In the context of this problem, describe Type \(I\) and Type II errors, and discuss the possible consequences of each. b. Would you recommend a test procedure that uses \(\alpha=.10\) or one that uses \(\alpha=.01 ?\) Explain.

Short Answer

Expert verified
Type I error would lead to wrongly accusing the manufacturer of false advertising. Its consequences could be legal or reputational harm to the manufacturer. Type II error would result in failure to identify false advertising leading to poor consumer choices and potential damage to the agency's credibility. The choice between using \(\alpha = .10\) or \(\alpha = .01\) depends on the balance between the risks of Type I and Type II errors one is willing to take. If the cost associated with Type I error is high, one might use a lower \(\alpha = .01\).

Step by step solution

01

Define Type I and Type II Errors

In the context of this problem, a Type I error occurs when the consumer agency incorrectly rejects the null hypothesis \(H_{0}: \pi=.9\) when in fact it is true, i.e., they mistakenly accuse the manufacturer of false advertising when their claims are accurate. On the other hand, a Type II error is made when the agency fails to reject the null hypothesis when it is false i.e., they fail to detect the manufacturer's false advertising.
02

Discuss the Consequences of Each Error

The consequences of a Type I error in this scenario could lead to potential legal issues or harm to the manufacturer’s reputation, as they would be wrongly accused of false advertising. A Type II error, on the other hand, involves the failure to identify false advertising. This could lead to consumers purchasing lower-quality TV sets under false premises, resulting in financial losses and potential damage to the agency's credibility.
03

Recommending a test procedure

Whether one should use a test procedure that uses \(\alpha=.10\) or \( \alpha=.01\) depends heavily on how much risk of committing Type I and Type II errors one is willing to accept. The smaller the value of alpha, the smaller the chance of committing a Type I error but the greater the chance of committing a Type II error. If the potential costs or consequences of a Type I error (falsely accusing the TV manufacturer) are considered to be quite high, then a smaller alpha, such as \(\alpha = 0.01\), would be advisable. However, this comes at the expense of a higher risk for a Type II error.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The article "Americans Seek Spiritual Guidance on Web" (San Luis Obispo Tribune, October 12,2002 ) reported that \(68 \%\) of the general population belong to a religious community. In a survey on Internet use, \(84 \%\) of "religion surfers" (defined as those who seek spiritual help online or who have used the web to search for prayer and devotional resources) belong to a religious community. Suppose that this result was based on a sample of 512 religion surfers. Is there convincing evidence that the proportion of religion surfers who belong to a religious community is different from \(.68\), the proportion for the general population? Use \(\alpha=.05\).

A certain university has decided to introduce the use of plus and minus with letter grades, as long as there is evidence that more than \(60 \%\) of the faculty favor the change. A random sample of faculty will be selected, and the resulting data will be used to test the relevant hypothe ses. If \(\pi\) represents the true proportion of all faculty that favor a change to plus- minus grading, which of the following pair of hypotheses should the administration test: $$ H_{0}: \pi=.6 \text { versus } H_{a}: \pi<.6 $$ or $$ H_{0}: \pi=.6 \text { versus } H_{a}: \pi>.6 $$ Explain your choice.

Let \(\pi\) denote the proportion of grocery store customers that use the store's club card. For a large sample \(z\) test of \(H_{0}: \pi=.5\) versus \(H_{a}: \pi>.5\), find the \(P\) -value associated with each of the given values of the test statistic: a. \(1.40\) d. \(2.45\) b. \(0.93\) e. \(-0.17\) c. \(1.96\)

Students at the Akademia Podlaka conducted an experiment to determine whether the Belgium-minted Euro coin was equally likely to land heads up or tails up. Coins were spun on a smooth surface, and in 250 spins, 140 landed with the heads side up (New Scientist, January 4 , 2002). Should the students interpret this result as convincing evidence that the proportion of the time the coin would land heads up is not .5? Test the relevant hypotheses using \(\alpha=.01\). Would your conclusion be different if a significance level of \(.05\) had been used? Explain.

Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharged water is at most \(150^{\circ} \mathrm{F}\), there will be no negative effects on the river ecosystem. To investigate whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above \(150^{\circ} \mathrm{F}\), a scientist will take 50 water samples at randomly selected times and will record the water temperature of each sample. She will then use a \(z\) statistic $$ z=\frac{\bar{x}-150}{\frac{\sigma}{\sqrt{n}}} $$ to decide between the hypotheses \(H_{0}: \mu=150\) and \(H_{a^{2}}\) \(\mu>150\), where \(\mu\) is the mean temperature of discharged water. Assume that \(\sigma\) is known to be 10 . a. Explain why use of the \(z\) statistic is appropriate in this setting. b. Describe Type I and Type II errors in this context. c. The rejection of \(H_{0}\) when \(z \geq 1.8\) corresponds to what value of \(\alpha ?\) (That is, what is the area under the \(z\) curve to the right of \(1.8 ?\) ) d. Suppose that the true value for \(\mu\) is 153 and that \(H_{0}\) is to be rejected if \(z \geq 1.8 .\) Draw a sketch (similar to that of Figure \(10.5\) ) of the sampling distribution of \(\bar{x}\), and shade the region that would represent \(\beta\), the probability of making a Type II error. e. For the hypotheses and test procedure described, compute the value of \(\beta\) when \(\mu=153\). f. For the hypotheses and test procedure described, what is the value of \(\beta\) if \(\mu=160 ?\) g. If \(H_{0}\) is rejected when \(z \geq 1.8\) and \(\bar{x}=152.8\), what is the appropriate conclusion? What type of error might have been made in reaching this conclusion?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free