Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Researchers at the University of Washington and Harvard University analyzed records of breast cancer screening and diagnostic evaluations ("Mammogram Cancer Scares More Frequent than Thought," USA Today, April 16,1998 ). Discussing the benefits and downsides of the screening process, the article states that, although the rate of false-positives is higher than previously thought, if radiologists were less aggressive in following up on suspicious tests, the rate of false-positives would fall but the rate of missed cancers would rise. Suppose that such a screening test is used to decide between a null hypothesis of \(H_{0}:\) no cancer is present and an alternative hypothesis of \(H_{a}:\) cancer is present. (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) a. Would a false-positive (thinking that cancer is present when in fact it is not) be a Type I error or a Type II error? b. Describe a Type I error in the context of this problem, and discuss the consequences of making a Type I error. c. Describe a Type II error in the context of this problem, and discuss the consequences of making a Type II error. d. What aspect of the relationship between the probability of Type I and Type II errors is being described by the statement in the article that if radiologists were less aggressive in following up on suspicious tests, the rate of false-positives would fall but the rate of missed cancers would rise?

Short Answer

Expert verified
a. A false positive is a Type I error. b. In this context, a Type I error is falsely diagnosing a patient with cancer, leading to possible stress, unnecessary testing, or harmful treatment. c. A Type II error would be falsely assuming a patient is cancer-free, causing delayed treatment and worse health outcomes. d. The statement in the article describes a trade-off relationship between Type I and Type II errors.

Step by step solution

01

Identify Type I and Type II Errors

A false positive, or thinking that cancer is present when in fact it is not, is a Type I error. A Type I error occurs when the null hypothesis (in this case \(H_{0}:\) no cancer is present) is rejected when it is true. A Type II error is when the null hypothesis is accepted when it is false, or believing there is no cancer when there actually is.
02

Describe Type I Error and its Consequences

In this situation, a Type I error would be diagnosing a patient with cancer when they do not have it. The consequences of making a Type I error could be unnecessary stress, anxiety, further invasive testing, and potential physical harm from unnecessary treatment for the patients.
03

Describe Type II Error and its Consequences

A Type II error, in this context, would be telling a patient that they do not have cancer when, in fact, they do. The consequences of making a Type II error would be that the patient's health would continue to deteriorate as the cancer was left untreated, reducing their chance of survival and possibility of a full recovery.
04

Analyze The Relationship Between Type I and Type II Errors

The statement in the article implies a trade-off between Type I and Type II errors in radiological diagnosis. If radiologists were less aggressive in following up on suspicious tests, they would make fewer Type I errors (false positives), but the rate of Type II errors (missed diagnoses of real cancers) would increase.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A random sample of \(n=44\) individuals with a B.S. degree in accounting who started with a Big Eight accounting firm and subsequently changed jobs resulted in a sample mean time to change of \(35.02\) months and a sample standard deviation of \(18.94\) months ("The Debate over Post-Baccalaureate Education: One University's Experience," Issues in Accounting Education [1992]: 18-36). Can it be concluded that the true average time to change exceeds 2 years? Test the appropriate hypotheses using a significance level of \(.01\).

Pizza Hut, after test-marketing a new product called the Bigfoot Pizza, concluded that introduction of the Bigfoot nationwide would increase its sales by more than \(14 \%\) (USA Today, April 2, 1993). This conclusion was based on recording sales information for a random sample of Pizza Hut restaurants selected for the marketing trial. With \(\mu\) denoting the mean percentage increase in sales for all Pizza Hut restaurants, consider using the sample data to decide between \(H_{0}: \mu=14\) and \(H_{a}: \mu>14\). a. Is Pizza Hut's conclusion consistent with a decision to reject \(H_{0}\) or to fail to reject \(H_{0}\) ? b. If Pizza Hut is incorrect in its conclusion, is the company making a Type I or a Type II error?

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week (Ipsos Reid, August 9,2005 ). The mean of the 1000 resulting observations was \(12.7\) hours. a. The sample standard deviation was not reported, but suppose that it was 5 hours. Carry out a hypothesis test with a significance level of \(.05\) to decide if there is convincing evidence that the mean time spent using the Internet by Canadians is greater than \(12.5\) hours. b. Now suppose that the sample standard deviation was 2 hours. Carry out a hypothesis test with a significance level of . 05 to decide if there is convincing evidence that the mean time spent using the Internet by Canadians is greater than \(12.5\) hours.

For which of the following \(P\) -values will the null hypothesis be rejected when performing a level \(.05\) test: a. 001 d. \(.047\) b. \(.021\) e. 148 c. \(.078\)

Use the definition of the \(P\) -value to explain the following: a. Why \(H_{0}\) would certainly be rejected if \(P\) -value \(=.0003\) b. Why \(H_{0}\) would definitely not be rejected if \(P\) -value \(=\) \(.350\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free