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The mean length of long-distance telephone calls placed with a particular phone company was known to be \(7.3\) min under an old rate structure. In an attempt to be more competitive with other long-distance carriers, the phone company lowered long-distance rates, thinking that its customers would be encouraged to make longer calls and thus that there would not be a big loss in revenue. Let \(\mu\) denote the true mean length of long-distance calls after the rate reduction. What hypotheses should the phone company test to determine whether the mean length of long-distance calls increased with the lower rates?

Short Answer

Expert verified
The phone company should test the null hypothesis \(H_0: \mu = 7.3\) and the alternative hypothesis \(H_1: \mu > 7.3\).

Step by step solution

01

Defining Null hypothesis

The null hypothesis would state that the mean length of calls (\(\mu\)) under the new rate structure is the same as under the old rate structure i.e., at \(7.3\) minutes. This can be mathematically expressed as \(H_0: \mu = 7.3\) minutes.
02

Formulating Alternative hypothesis

The alternative hypothesis is what the company wants to test, i.e., whether the mean length of calls has increased due to the reduced rate. So, it can be mathematically represented as \(H_1: \mu > 7.3\) minutes.
03

Explanation of Hypotheses

So, in this context, the null hypothesis \(H_0: \mu = 7.3\) states that the rate decrease has not affected the mean length of the calls, whereas the alternative hypothesis \(H_1: \mu > 7.3\) suggests that the mean length of calls increased with the lower rates.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
Understanding the null hypothesis is a fundamental aspect of hypothesis testing in statistics. It is the default assumption that there is no effect or no difference between two measured phenomena. For instance, if a telephone company is analyzing the impact of a change in their rate structure on the duration of calls, the null hypothesis would assert that this change has not altered the average call length.

In formal terms, the null hypothesis is declared as a specific value that the parameter of interest (such as the mean length of long-distance telephone calls, denoted as \(\mu\)) is equal to. If the known average call length under the old rate structure was 7.3 minutes, the null hypothesis (\(H_0\)) would be: \[H_0: \mu = 7.3 \text{ minutes}.\] The essence of the null hypothesis lies in its neutrality and the assumption of 'no change' or 'no effect,' which serves as a baseline for statistical testing.
Alternative Hypothesis
Contrasts against the null hypothesis, the alternative hypothesis (\(H_1\)) represents a researcher's conjecture that there is indeed an effect, or a difference that exists. In regards to the mean length of telephone calls after a rate reduction, the alternative hypothesis would state that the mean duration of calls has increased—that is, it is greater than the mean under the old rate structure.

Mathematically, this hypothesis could be formulated as \[H_1: \mu > 7.3 \text{ minutes}.\] The creation of an alternative hypothesis is a critical step as it embodies the idea you're testing and is often the hypothesis that the researcher wants to prove. In a scenario where a phone company has reduced rates with the expectation that call durations will extend, demonstrating an increase in the average length of calls will support their marketing strategy.
Mean Length of Calls
The mean length of calls, denoted mathematically by the symbol \(\mu\), is a measure of central tendency that calculates the average duration of telephone calls made within a certain period. This statistic is highly valuable to telephone companies in understanding customer behavior and optimizing rate plans.

When a company changes its rate structure, investigating the mean length of calls before and after the change is central to determining the impact of their business decision. In the case of a decrease in rates, the company hypothesizes that this will lead to customers engaging in longer calls, potentially compensating for the reduced rate by an increase in usage. The mean length of calls serves as a critical metric in conducting a hypothesis test to validate or refute this assumption.
Rate Structure Analysis
Rate structure analysis involves examining how changes in billing for services affect customer usage patterns. In the context of a telephone company, this could imply altering per-minute charges, implementing flat fees, or introducing discounted rates during off-peak hours. The analysis aims to determine if such changes are economically beneficial or detrimental to the company.

By conducting a rate structure analysis, a company assesses the business impact of changing its pricing model. For our particular case, the company aims to find out if lowering long-distance rates leads to a significant change in the mean length of calls. This type of analysis integrates statistical hypothesis testing to evaluate if the observed differences in call lengths are likely due to chance or if they are statistically significant and, hence, possibly attributed to the rate reduction.

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Most popular questions from this chapter

According to a survey of 1000 adult Americans conducted by Opinion Research Corporation, 210 of those surveyed said playing the lottery would be the most practical way for them to accumulate \(\$ 200,000\) in net wealth in their lifetime ("One in Five Believe Path to Riches Is the Lottery," San Luis Obispo Tribune, January 11,2006 ). Although the article does not describe how the sample was selected, for purposes of this exercise, assume that the sample can be regarded as a random sample of adult Americans. Is there convincing evidence that more than \(20 \%\) of adult Americans believe that playing the lottery is the best strategy for accumulating \(\$ 200,000\) in net wealth?

A number of initiatives on the topic of legalized gambling have appeared on state ballots. Suppose that a political candidate has decided to support legalization of casino gambling if he is convinced that more than twothirds of U.S. adults approve of casino gambling. USA Today (June 17,1999 ) reported the results of a Gallup poll in which 1523 adults (selected at random from households with telephones) were asked whether they approved of casino gambling. The number in the sample who approved was 1035 . Does the sample provide convincing evidence that more than two-thirds approve?

Suppose that you are an inspector for the Fish and Game Department and that you are given the task of determining whether to prohibit fishing along part of the Oregon coast. You will close an area to fishing if it is determined that fish in that region have an unacceptably high mercury content. a. Assuming that a mercury concentration of \(5 \mathrm{ppm}\) is considered the maximum safe concentration, which of the following pairs of hypotheses would you test: $$ H_{0}: \mu=5 \text { versus } H_{a}: \mu>5 $$ or $$ H_{0}: \mu=5 \text { versus } H_{a}: \mu<5 $$ Give the reasons for your choice. b. Would you prefer a significance level of \(.1\) or \(.01\) for your test? Explain.

Occasionally, warning flares of the type contained in most automobile emergency kits fail to ignite. A consumer advocacy group wants to investigate a claim against a manufacturer of flares brought by a person who claims that the proportion of defective flares is much higher than the value of \(.1\) claimed by the manufacturer. A large number of flares will be tested, and the results will be used to decide between \(H_{0}=\pi=.1\) and \(H_{a}: \bar{\pi}>.1\), where \(\pi\) represents the true proportion of defective flares made by this manufacturer. If \(H_{0}\) is rejected, charges of false advertising will be filed against the manufacturer. a. Explain why the alternative hypothesis was chosen to be \(H_{a}: \pi>.1\). b. In this context, describe Type I and Type II errors, and discuss the consequences of each.

For which of the following \(P\) -values will the null hypothesis be rejected when performing a level \(.05\) test: a. 001 d. \(.047\) b. \(.021\) e. 148 c. \(.078\)

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