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Under what conditions would you use the hypergeometric probability distribution to calculate the probability of \(x\) successes in \(n\) trials?

Short Answer

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Answer: The hypergeometric probability distribution can be used when the following conditions are met: a) There is a finite population of size N. b) The population consists of two distinct categories: success and failure. c) Sampling is done without replacement. d) A fixed number (n) of trials are performed.

Step by step solution

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1. Definition of Hypergeometric Distribution

The hypergeometric distribution is a probability distribution that represents the probability of obtaining a certain number of successes in a fixed number of trials from a finite population without replacement. It is usually applied when sampling is done without replacement and the population size is small compared to the sample size.
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2. Conditions to use Hypergeometric Distribution

There are four main conditions that must be met in order to use the hypergeometric probability distribution: a) There is a finite population of size N. b) The population consists of two distinct categories: success and failure. c) Sampling is done without replacement. d) A fixed number (n) of trials are performed.
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3. Example of when to use the Hypergeometric Distribution

Suppose there are 20 students in a class, and 6 of them are left-handed. If we were to randomly select 5 students without replacement, and we wanted to know the probability that exactly 2 of those students are left-handed, we could use the hypergeometric distribution to calculate this probability. In this case, the conditions are satisfied: a) The finite population is 20 students. b) The two distinct categories are left-handed (success) and right-handed (failure). c) We sample without replacement since no student is selected twice. d) We perform 5 trials (selecting 5 students).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
When studying statistics or probability, you'll often encounter the term 'probability distribution'. This concept is fundamental in understanding how likely different outcomes are in a random experiment.

Let's imagine we have a bag of colorful marbles, and each color signifies a different outcome. A probability distribution would tell us how likely we are to pick a marble of each color if we were to reach into the bag without looking. But it's not just about guessing; it's about calculating the exact probability of drawing each color based on the proportion of marbles that color has in the bag.

In more technical terms, the distribution assigns a probability to each possible outcome. For example, if we know that 60% of the marbles are blue, 30% are red, and 10% are green, then our probability distribution would reflect these percentages for each draw.
Finite Population Sampling
Sometimes, the context of our random experiment is such that we have a limited number of items to consider. This scenario is known as 'finite population sampling'. This is a sampling method used when the group we're interested in (our population) isn't very large or when it’s not feasible to observe all its members.

For instance, if we are dealing with a specific year's high school graduation class rather than all high school graduates ever, we have a finite population. Understanding this scope is crucial because the size of the group can affect our probability calculations. It is like having a bag with only a set number of marbles—say 50. Once you've taken out so many marbles, there aren’t as many left to choose from for subsequent draws, which changes the likelihood of future picks. This aspect of the population size relative to the sample size is what differentiates finite population sampling from other types.
Sampling Without Replacement
Sampling without replacement is a technique widely used in statistics, particularly when dealing with a finite population. It's like drawing marbles from our earlier bag example, but once a marble is picked, it doesn't go back in. This affects subsequent selections because the makeup of the bag changes with each draw, making certain outcomes more or less likely.

This practice contrasts with 'sampling with replacement,' where each marble is returned to the bag after being picked, keeping the probability of each outcome constant. Without replacement, after each selection, the total number of options (and often the odds of picking a specific type) decreases.

Now, why is this relevant? When you are drawing without replacement from a small group, the chances of selecting a certain kind of item (like a left-handed student in a small class) are not independent from one draw to another. Hence, the probabilities of subsequent selections depend on the outcomes of previous picks. This dependency must be taken into account when calculating probabilities, which is where the hypergeometric distribution becomes the tool of choice.

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Most popular questions from this chapter

Draw three cards randomly from a standard deck of 52 cards and let \(x\) be the number of kings in the draw. Evaluate the probabilities and answer the questions in Exercises \(26-28\) Would the probability distribution in Exercise 27 change if \(x\) were defined to be the number of aces in the draw?

The board of directors of a major symphony orchestra has voted to create a committee to handle employee complaints. The committee will consist of the president and vice president of the symphony board and two orchestra representatives. The two orchestra representatives will be randomly selected from a list of six volunteers, consisting of four men and two women. a. Find the probability distribution for \(x,\) the number of women chosen to be orchestra representatives. b. What is the probability that both orchestra representatives will be women? c. Find the mean and variance for the random variable \(x\).

A key ring contains four office keys that are identical in appearance, but only one will open your office door. Suppose you randomly select one key and try it. If it does not fit, you randomly select one of the three remaining keys. If that key does not fit, you randomly select one of the last two. Each different sequence that could occur in selecting the keys represents a set of equally likely simple events. a. List the simple events in \(S\) and assign probabilities to the simple events. b. Let \(x\) equal the number of keys that you try before you find the one that opens the door \((x=1,2,3,4)\). Then assign the appropriate value of \(x\) to each simple event. c. Calculate the values of \(p(x)\) and display them in a table. d. Construct a probability histogram for \(p(x)\).

In a county containing a large number of rural homes, \(60 \%\) of the homes are insured against fire. Four rural homeowners are chosen at random from this county, and \(x\) are found to be insured against fire. Find the probability distribution for \(x\). What is the probability that at least three of the four will be insured?

A fire-detection device uses three temperature-sensitive cells acting independently of one another so that any one or more can activate the alarm. Each cell has a probability \(p=.8\) of activating the alarm when the temperature reaches \(57^{\circ} \mathrm{C}\) or higher. Let \(x\) equal the number of cells activating the alarm when the temperature reaches \(57^{\circ} \mathrm{C}\). a. Find the probability distribution of \(x\). b. Find the probability that the alarm will function when the temperature reaches \(57^{\circ} \mathrm{C}\). c. Find the expected value and the variance for the random variable \(x\).

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