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A sample space contains seven simple events: \(E_{1}, E_{2}, \ldots, E_{7} .\) Use the following three eventsA, \(B\), and \(C\) - and list the simple events in Exercises \(7-12\). \(A=\left\\{E_{3}, E_{4}, E_{6}\right\\} \quad B=\left\\{E_{1}, E_{3}, E_{5}, E_{7}\right\\} \quad C=\left\\{E_{2}, E_{4}\right\\}\) $$\text { Both } A \text { and } B$$

Short Answer

Expert verified
Answer: The intersection of events A and B is given by {Eā‚ƒ}.

Step by step solution

01

Identify the elements in event A

First, let's list the elements in event \(A\). According to the problem, \(A=\left\\{E_{3}, E_{4}, E_{6}\right\\}\).
02

Identify the elements in event B

Next, let's list the elements in event \(B\). According to the problem, \(B=\left\\{E_{1}, E_{3}, E_{5},E_{7}\right\\}\).
03

Find the intersection of events A and B

Now, we want to find the simple events that are present in both events \(A\) and \(B\). This is called the intersection of events \(A\) and \(B\), denoted as \(A \cap B\). To find this intersection, we compare the elements in event \(A\) to the elements in event \(B\) and list the elements that are common to both events.
04

List the elements in the intersection of events A and B

Upon comparison, we can see that \(E_{3}\) is the only element common to both events \(A\) and \(B\). Therefore, the intersection of events \(A\) and \(B\) is given by: $$A \cap B = \left\\{E_{3}\right\\}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
A sample space is a fundamental concept in probability theory that represents the set of all possible outcomes of a random experiment. Think of it as a complete list of every potential result that can be attained.
For example, when you roll a six-sided die, the sample space is \[S = \{1, 2, 3, 4, 5, 6\}\]. Each result from rolling the die represents one possible outcome within this sample space.
In our exercise, the sample space contains seven elements: \(E_{1}, E_{2}, \ldots, E_{7}\), representing all the simple events that might occur. Recognizing the sample space is crucial because it allows us to consider all potential outcomes and make informed probabilistic predictions.
Intersection of Events
The intersection of events in probability refers to the scenario where two or more events occur at the same time. It's a way to determine which outcomes are common to all the events being considered.
Mathematically, the intersection is denoted by the symbol \(\cap\). For instance, if we have two events \(A\) and \(B\), the intersection \(A \cap B\) includes only the outcomes that are present in both \(A\) and \(B\).
In our exercise, we're asked to find the intersection of events \(A\) and \(B\) from our sample space. By identifying which simple events occur in both \(A\) and \(B\), we determine that \(A \cap B = \{E_3\}\). This indicates that \(E_3\) is the only outcome they share in common.
Simple Events
Simple events, in the context of probability, are the most basic possible results of a random experiment. Each simple event corresponds to a single outcome and cannot be further broken down into more simple components.
For example, when tossing a coin, the simple events are "heads" and "tails". These are the basic outcomes of the action.
In our sample space \(\{E_1, E_2, \ldots, E_7\}\), each \(E_i\) represents a simple event. These form the building blocks that combine to establish more complex events, like event \(A = \{E_3, E_4, E_6\}\), which is simply a collection of three simple events.
Events in Probability
Events in probability are sets of outcomes from a sample space, which can be one or several simple events. An event can be as basic as a single outcome or as complex as any combination of multiple outcomes.
Using our exercise, event \(A = \{E_3, E_4, E_6\}\) and event \(B = \{E_1, E_3, E_5, E_7\}\) are examples of events composed of simple events from the sample space.
Events are significant because they are the basic components of probability calculations. The probability of an event is found by considering the ratio of the number of outcomes in the event to the total number of outcomes in the sample space. These events can also interact in various ways, such as through intersections or unions, to help analyze different probabilistic scenarios.

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Most popular questions from this chapter

Suppose that \(P(A)=.3\) and \(P(B)=.4\) a. If \(P(A \cap B)=.12,\) are \(A\) and \(B\) independent? Justify your answer. b. If \(P(A \cup B)=.7,\) what is \(P(A \cap B)\) ? Justify your answer. c. If \(A\) and \(B\) are independent, what is \(P(A \mid B)\) ? d. If \(A\) and \(B\) are mutually exclusive, what is \(P(A \mid B) ?\)

A particular basketball player hits \(70 \%\) of her free throws. When she tosses a pair of free throws, the four possible simple events and three of their probabilities are as given in the table: $$ \begin{array}{llc} \hline & {\text { First Throw }} \\ { 2 - 3 } \text { Second Throw } & \text { Hit } & \text { Miss } \\ \hline \text { Hit } & .49 & .21 \\ \text { Miss } & ? & .09 \\ \hline \end{array} $$ a. Find the probability that the player will hit on the first throw and miss on the second. b. Find the probability that the player will hit on at least one of the two free throws.

Use the mn Rule to find the number. There are three groups of distinctly different items, 4 in the first group, 7 in the second, and 3 in the third. If you select one item from each group, how many different triplets can you form?

An experiment is conducted at a local supermarket, where shoppers are asked to taste two soft-drink samples \(-\) one Pepsi and one Coke- and state their preference. Suppose that four shoppers are chosen at random and asked to participate in the experiment, and that there is actually no difference in the taste of the two brands. a. What is the probability that all four shoppers choose Pepsi? b. What is the probability that exactly one of the four shoppers chooses Pepsi?

Suppose that \(P(A)=.3\) and \(P(B)=.5 .\) If events \(A\) and \(B\) are mutually exclusive, find these probabilities: a. \(P(A \cap B)\) b. \(P(A \cup B)\)

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