Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A sample is selected from one of two populations, \(S_{1}\) and \(S_{2},\) with \(P\left(S_{1}\right)=.7\) and \(P\left(S_{2}\right)=.3 .\) The probabilities that an event A occurs, given that event \(S_{1}\) or \(S\), has occurred are $$ P\left(A \mid S_{1}\right)=.2 \text { and } P\left(A \mid S_{2}\right)=.3 $$ Use this information to answer the questions in Exercises \(1-3 .\) Use Bayes' Rule to find \(P\left(S_{2} \mid A\right)\).

Short Answer

Expert verified
Answer: The probability is approximately 0.3913 or 39.13%.

Step by step solution

01

Understand Bayes' Rule

Bayes' Rule is a method to update the probability of a hypothesis based on new evidence. In this context, it helps us to find the probability of \(S_2\) occurring given that event A has occurred. Mathematically, Bayes' Rule is defined as: $$ P(S_2 | A) = \frac{P(A | S_2) * P(S_2)}{P(A)} $$ Here, we are given the \(P(A | S_1)\), \(P(A | S_2)\) and \(P(S_1)\), and \(P(S_2)\) values, but we need to find the value of \(P(A)\) before we can apply Bayes' Rule.
02

Calculate P(A) using the Law of Total Probability

The Law of Total Probability states that if we have a partition of the sample space (in this case, the partition is \(S_1\) and \(S_2\)), then P(A) can be calculated using the following formula: $$ P(A) = P(A | S_1)*P(S_1) + P(A | S_2)*P(S_2) $$ We can plug in the given values to find P(A): $$ P(A) = 0.2*0.7 + 0.3*0.3 $$ $$ P(A) = 0.14 + 0.09 = 0.23 $$
03

Apply Bayes' Rule

Now, we have all the necessary values to apply Bayes' Rule: $$ P(S_2 | A) = \frac{P(A | S_2) * P(S_2)}{P(A)} $$ Plug in the values and calculate the result: $$ P(S_2 | A) = \frac{0.3*0.3}{0.23} = \frac{0.09}{0.23} $$ $$ P(S_2 | A) \approx 0.3913 $$
04

Interpret the Result

The probability of selecting a sample from population \(S_2\), given that event A has occurred, is approximately 0.3913 or 39.13%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Rules
Probability rules are the foundational principles of probability that help us calculate and understand various probabilistic events. These rules are essential for solving problems in probability, and they are frequently used in conjunction with other concepts like Bayes' Theorem.

Some key probability rules include:
  • Addition Rule: Useful when determining the probability of either of two mutually exclusive events occurring. If events A and B cannot happen at the same time, then the probability of A or B is simply the sum of their probabilities: \( P(A \cup B) = P(A) + P(B) \).
  • Multiplication Rule: When the events are independent, the probability of both events A and B occurring is the product of their respective probabilities: \( P(A \cap B) = P(A) \cdot P(B) \).
  • Complement Rule: The probability of an event not occurring is equal to one minus the probability of the event occurring: \( P(A') = 1 - P(A) \).
Understanding and using these basic rules correctly is crucial for solving more complex problems involving events and probabilities.
Law of Total Probability
The Law of Total Probability is a vital tool in probability theory, particularly when dealing with conditional probabilities. It allows us to calculate the overall probability of an event based on conditional probabilities given different initial conditions or events.

Imagine you have a sample space divided into different parts or "events," such as the populations \( S_1 \) and \( S_2 \) in our example. The Law of Total Probability can be expressed as:
  • \( P(A) = P(A | S_1) \cdot P(S_1) + P(A | S_2) \cdot P(S_2) \)
To apply this law, follow these steps:
  • Identify and list all possible partitions of the sample space that the event can occur.
  • Calculate the probability of the event for each partition, multiplying by the probability of the partition itself.
  • Add up these partial probabilities to arrive at the total probability of the event.
In our case, we found the probability of the event \( A \) occurring, which provides us the groundwork to apply Bayes' Theorem effectively.
Conditional Probability
Conditional probability refers to the probability of an event occurring given that another event has already occurred. It forms the basis for concepts like Bayes' Theorem and is denoted as \( P(A | B) \), which reads as "the probability of A given B."

Conditional probability is crucial for assessing the likelihood of an event when the outcome is influenced by prior events. The formula for conditional probability is generally given by:
  • \( P(A | B) = \frac{P(A \cap B)}{P(B)} \)
In the context of our exercise, we are working to determine probabilities like \( P(S_2 | A) \), meaning "given that event \( A \) has already occurred, what is the probability of \( S_2 \)?"

Here’s how you can approach conditional probability problems:
  • Understand the dependencies between events.
  • Use the given data to calculate probabilities of intersection and the known event.
  • Apply the formula to determine the conditional probability.
In practice, conditional probability helps in making informed decisions where part of the outcome is already known, refining predictions in a variety of fields.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Experiment III A sample space consists of five simple events with \(P\left(E_{1}\right)=P\left(E_{2}\right)=.15, P\left(E_{3}\right)=.4,\) and \(P\left(E_{4}\right)=2 P\left(E_{5}\right) .\) Find the probabilities for simple events \(E_{4}\) and \(E_{5}\).

Refer to Exercise 33. Suppose you are interested in following two independent traits in snap peas-seed texture \((\mathrm{S}=\) smooth \(, \mathrm{s}=\) wrinkled \()\) and seed color \((\mathrm{Y}=\) yellow, \(\mathrm{y}=\) green \()-\) in a secondgeneration cross of heterozygous parents. Remember that the capital letter represents the dominant trait. Complete the table with the gene pairs for both traits. All possible pairings are equally likely. a. What proportion of the offspring from this cross will have smooth yellow peas? b. What proportion of the offspring will have smooth green peas? c. What proportion of the offspring will have wrinkled yellow peas? d. What proportion of the offspring will have wrinkled green peas? e. Given that an offspring has smooth yellow peas, what is the probability that this offspring carries one s allele? One s allele and one y allele?

Evaluate the permutations. $$ P_{1}^{20} $$

Two cold tablets are unintentionally put in a box containing two aspirin tablets, that appear to be identical. One tablet is selected at random from the box and swallowed by the first patient. The second patient selects another tablet at random and swallows it. a. List the simple events in the sample space \(S\). b. Find the probability of event \(A\), that the first patient swallowed a cold tablet. c. Find the probability of event \(B\), that exactly one of the two patients swallowed a cold tablet. d. Find the probability of event \(C,\) that neither patient swallowed a cold tablet.

In \(1865,\) Gregor Mendel suggested a theory of inheritance based on the science of genetics. He identified heterozygous individuals for flower color that had two alleles \((\mathrm{r}=\) recessive white color allele and \(\mathrm{R}=\) dominant red color allele ). When these individuals were mated, \(3 / 4\) of the offspring were observed to have red flowers and \(1 / 4\) had white flowers. The table summarizes this mating; each parent gives one of its alleles to form the gene of the offspring. We assume that each parent is equally likely to give either of the two alleles and that, if either one or two of the alleles in a pair is dominant (R), the offspring will have red flowers. a. What is the probability that an offspring in this mating has at least one dominant allele? b. What is the probability that an offspring has at least one recessive allele? c. What is the probability that an offspring has one recessive allele, given that the offspring has red flowers?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free