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A sample is selected from one of two populations, \(S_{1}\) and \(S_{2},\) with \(P\left(S_{1}\right)=.7\) and \(P\left(S_{2}\right)=.3 .\) The probabilities that an event A occurs, given that event \(S_{1}\) or \(S\), has occurred are $$ P\left(A \mid S_{1}\right)=.2 \text { and } P\left(A \mid S_{2}\right)=.3 $$ Use this information to answer the questions in Exercises \(1-3 .\) Use the Law of Total Probability to find \(P(A)\).

Short Answer

Expert verified
Answer: The probability of event A occurring is \(0.23\).

Step by step solution

01

Identify the given probabilities

We are given that: - \(P(S_1) = 0.7\) - \(P(S_2) = 0.3\) - \(P(A \mid S_1) = 0.2\) - \(P(A \mid S_2) = 0.3\)
02

Use the Law of Total Probability

We can now apply the Law of Total Probability formula: $$P(A) = P(A \mid S_1)P(S_1) + P(A \mid S_2)P(S_2)$$
03

Plug in the values

Substitute the given values into the formula: $$P(A) = (0.2)(0.7) + (0.3)(0.3)$$
04

Calculate P(A)

Perform the calculations: $$P(A) = 0.14 + 0.09$$ $$P(A) = 0.23$$ So the probability that event A occurs, \(P(A)\), is \(0.23\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
When studying probability, a fundamental concept is known as conditional probability. It refers to the probability of an event occurring, given that another event has already occurred. This is notated as P(A | B), which reads as 'the probability of A given B'.

For example, if we have two populations, S1 and S2, and we're interested in the occurrence of an event A, we need to consider the chances of A happening within each separate population. Conditional probability allows us to update our predictions about A according to whether we know the sample came from S1 or S2. In our exercise, we have the conditional probabilities as P(A | S1) and P(A | S2), suggesting different likelihoods of A depending on the source population.

The concept is particularly useful when dealing with complex scenarios where the probability of an outcome can be influenced by various factors, here embodied by the different source populations. Understanding conditional probability is essential for accurately calculating the chances of an event under certain conditions, a skill not just for textbook exercises but in real-world statistical analysis as well.
Probability of an Event
The probability of an event is a measure of the likelihood that the event will occur. It is a value between 0 and 1, where 0 indicates impossibility and 1 indicates certainty. The probability of an event A is notated as P(A).

In our exercise, determining P(A) involves combining the probabilities of event A occurring in two separate populations. By applying the Law of Total Probability, we effectively weigh each conditional probability by the probability of its conditioning event, thus acknowledging each population's contribution to the overall event probability.

Diagramming the Probability

Think of your overall probability as a pie made up of slices that represent different contributing factors. In our case, the slices for event A are based on which population the sample comes from – with S1 or S2. Calculating P(A) with the Law of Total Probability is akin to piecing together the complete pie to understand the full picture of how likely event A is to occur.
Statistical Populations
A statistical population is a set of entities about which statistical inferences are to be made, often based on a sample from the population. In probability and statistics, a population doesn't necessarily refer to people; it could be a collection of objects, events, processes, measurements, or even the results of a model.

In our exercise, we deal with two different populations, S1 and S2. Each population may behave differently and thus has distinct probabilities associated with event A, P(A | S1) and P(A | S2) respectively. By identifying and working with these populations separately, we respect the different mechanisms at play within each group.

Importance in Analysis

Recognizing the diversity among populations is crucial for accurate data analysis. When calculating overall probabilities, failing to account for the unique characteristics of separate populations would lead to misleading conclusions. Our exercise showcases how to consider these differences systematically to arrive at a true understanding of the likelihood of event A.

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Most popular questions from this chapter

A sample is selected from one of two populations, \(S_{1}\) and \(S_{2},\) with \(P\left(S_{1}\right)=.7\) and \(P\left(S_{2}\right)=.3 .\) The probabilities that an event A occurs, given that event \(S_{1}\) or \(S\), has occurred are $$ P\left(A \mid S_{1}\right)=.2 \text { and } P\left(A \mid S_{2}\right)=.3 $$ Use this information to answer the questions in Exercises \(1-3 .\) Use Bayes' Rule to find \(P\left(S_{2} \mid A\right)\).

A study of drug offenders who have been treated for drug abuse suggests that the chance of conviction within a 2 -year period after treatment may depend on the offender's education. The proportions of the total number of cases that fall into four education/conviction categories are shown in the following table. Suppose a single offender is selected from the treatment program. Here are the events of interest: \(A:\) The offender has 10 or more years of education B: The offender is convicted within 2 years after completion of treatment Find the appropriate probabilities for these events: a. \(A\) b. \(B\) c. \(A \cap B\) d. \(A \cup B\) e. \(A^{c}\) f. \(A\) given that \(B\) has occurred g. \(B\) given that \(A\) has occurred

For the experiments, list the simple events in the sample space, assign probabilities to the simple events, and find the required probabilities. A single card is randomly drawn from a deck of 52 cards. Find the probability that it is an ace.

In \(1865,\) Gregor Mendel suggested a theory of inheritance based on the science of genetics. He identified heterozygous individuals for flower color that had two alleles \((\mathrm{r}=\) recessive white color allele and \(\mathrm{R}=\) dominant red color allele ). When these individuals were mated, \(3 / 4\) of the offspring were observed to have red flowers and \(1 / 4\) had white flowers. The table summarizes this mating; each parent gives one of its alleles to form the gene of the offspring. We assume that each parent is equally likely to give either of the two alleles and that, if either one or two of the alleles in a pair is dominant (R), the offspring will have red flowers. a. What is the probability that an offspring in this mating has at least one dominant allele? b. What is the probability that an offspring has at least one recessive allele? c. What is the probability that an offspring has one recessive allele, given that the offspring has red flowers?

Suppose \(5 \%\) of all people filing the long income tax form seek deductions that they know are illegal, and an additional \(2 \%\) incorrectly list deductions because they are unfamiliar with income tax regulations. Of the \(5 \%\) who are guilty of cheating, \(80 \%\) will deny knowledge of the error if confronted by an investigator. If the filer of the long form is confronted with an unwarranted deduction and he or she denies the knowledge of the error, what is the probability that he or she is guilty?

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