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Use the information given in Exercises \(4-7\) to calculate Spearman's rank correlation coefficient, where \(x_{i}\) and \(y_{i}\) are the ranks of the ith pair of observations and \(d_{i}=x_{i}-y_{i} .\) Assume that there are no ties in the ranks. \(S_{x x}=S_{y y}=10 ; S_{x y}=6 ; n=5\)

Short Answer

Expert verified
Answer: The Spearman's rank correlation coefficient is 0.6.

Step by step solution

01

Identify the given values

We are given the following values: - \(S_{xx} = 10\) - \(S_{yy} = 10\) - \(S_{xy} = 6\) - \(n = 5\)
02

Set up the formula for Spearman's rank correlation coefficient

The formula for Spearman's rank correlation coefficient is given by: $$r_s = \frac{S_{xy}}{\sqrt{S_{xx} S_{yy}}}$$
03

Substitute the given values and calculate the coefficient

Now, we substitute the given values into the formula: $$r_s = \frac{6}{\sqrt{10 \times 10}}$$
04

Solve the equation

Simplify the expression: $$r_s = \frac{6}{\sqrt{100}} = \frac{6}{10} = 0.6$$
05

Interpret the result

The Spearman's rank correlation coefficient, \(r_s\), is 0.6. This indicates a moderate positive relationship between the paired observations. When one variable increases, the other variable tends to increase as well, but the relationship is not very strong.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rank Correlation
In statistics, rank correlation is a method of calculating the relationship or association between two ordinal variables. It is nonparametric, meaning it does not assume a specific statistical distribution. The Spearman's rank correlation coefficient, often denoted by \( r_s \), is a popular measure to assess how well the relationship between two variables can be described using a monotonic function.

Essentially, Spearman's rank correlation examines the ranks assigned to data values rather than their raw numbers. If the ranks of corresponding paired observations resemble each other closely, the Spearman's rank correlation coefficient will be closer to \( +1 \) for positively related ranks, or \( -1 \) for negatively related ranks. A value near zero suggests little or no rank correlation. It's particularly useful because it lessens the influence of outliers and can handle non-linear relationships.
Nonparametric Statistics
Nonparametric statistics refers to statistical methods that do not require population parameters to follow a specific distribution, often making fewer assumptions about the data. This flexibility allows for analysis when parametric assumptions cannot be met, which can be vital for accurately understanding a variety of data types.

They are used when data doesn't lend itself well to standard parametric tests, such as when handling skewed distributions, ordinal data, or populations that are not normally distributed. Spearman's rank correlation coefficient is an example of a nonparametric statistic because it does not rely on any assumptions about the frequency distribution of the variables and is based only on the ranks, therefore being especially robust to data anomalies.
Data Analysis
Data analysis encompasses a broad range of methods to process, visualise, and draw conclusions from data. In the context of Spearman's rank correlation, data analysis involves ranking the variables, assessing their association, and determining the strength and direction of the relationship between them.

The conclusion drawn from a Spearman's rank correlation can influence decision-making in various sectors, including business, healthcare, and social sciences. Data analysis is iterative and exploratory at its core, often benefiting from visualization tools that can help illustrate the strength of a correlation or the pattern of a relationship. An effective data analysis strategy enables researchers to navigate through complex data sets, simplifying the inference of trends and relationships.

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Most popular questions from this chapter

Dissolved oxygen content is a measure of the ability of a river, lake, or stream to support aquatic life, with high levels being better. A pollution- control inspector who suspected that a river community was releasing semitreated sewage into a river, randomly selected five specimens of river water at a location above the town and another five below. These are the dissolved oxygen readings (in parts per million): $$ \begin{array}{l|lllll} \text { Above Town } & 4.8 & 5.2 & 5.0 & 4.9 & 5.1 \\ \hline \text { Below Town } & 5.0 & 4.7 & 4.9 & 4.8 & 4.9 \end{array} $$ a. Use a one-tailed Wilcoxon rank sum test with \(\alpha=.05\) to confirm or refute the theory. b. Use a Student's \(t\) -test (with \(\alpha=.05\) ) to analyze the data. Compare the conclusion reached in part a.

The time required for kindergarten children to assemble a specific Lego creation was measured for children who had been instructed for four different lengths of time. Five children were randomly assigned to each instructional group. The length of time (in minutes) to assemble the Lego creation was recorded for each child in the experiment. $$ \begin{array}{rlll} \hline & {\text { Training Period (hours) }} \\ \hline .5 & 1.0 & 1.5 & 2.0 \\ \hline 8 & 9 & 4 & 4 \\ 14 & 7 & 6 & 7 \\ 9 & 5 & 7 & 5 \\ 12 & 8 & 8 & 5 \\ 10 & 9 & 6 & 4 \\ \hline \end{array} $$ Use the Kruskal-Wallis \(H\) -Test to determine whether there is a difference in the distribution of times for the four different lengths of instructional time. Use \(\alpha=01\).

The data were collected using a randomized block design. For each data set, use the Friedman \(F\) -test to test for differences in location among the treatment distributions using \(\alpha=.05 .\) Bound the \(p\) -value for the test using Table 5 of Appendix \(I\) and state your conclusions. $$ \begin{array}{lccc} \hline & {\text { Treatment }} \\ \text { Block } & 1 & 2 & 3 \\ \hline 1 & 3.2 & 3.1 & 2.4 \\ 2 & 2.8 & 3.0 & 1.7 \\ 3 & 4.5 & 5.0 & 3.9 \\ 4 & 2.5 & 2.7 & 2.6 \\ 5 & 3.7 & 4.1 & 3.5 \\ 6 & 2.4 & 2.4 & 2.0 \\ \hline \end{array} $$

A drug called ampakine CX- 516 that accelerates signals between brain cells and appears to significantly sharpen memory was expected to provide relief for patients with Alzheimer's disease. \({ }^{2}\) In a preliminary study involving no medication, 10 students in their early 20 s and 10 men aged \(65-70\) were asked to listen to a list of nonsense syllables. The numbers of nonsense syllables recalled after 5 minutes are recorded in the table. Use the Wilcoxon rank sum test to determine whether the distributions for the number of nonsense syllables recalled are the same for these two groups. $$ \begin{array}{l|llllllllll} 20 \mathrm{~s} & 3 & 6 & 4 & 8 & 7 & 1 & 1 & 2 & 7 & 8 \\ \hline 65-70 \mathrm{~s} & 1 & 0 & 4 & 1 & 2 & 5 & 0 & 2 & 2 & 3 \end{array} $$

Use the Wilcoxon rank sum test to determine whether population 1 lies to the left of population 2 by (1) stating the null and alternative hypotheses to be tested, (2) calculating the values of \(T_{1}\) and \(T_{l}^{*},(3)\) finding the rejection region for \(\alpha=.05,\) and (4) stating your conclusions. $$ \begin{array}{l|ccccc} \text { Sample } 1 & 6 & 7 & 3 & 1 & \\ \hline \text { Sample } 2 & 4 & 4 & 9 & 2 & 7 \end{array} $$

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