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Use the data given in Exercises 5-6 (Exercises 17-18, Section 12.1). Do the data provide sufficient evidence to indicate that \(y\) and \(x\) are linearly related? Test using the \(t\) statistic at the 1\% level of significance. Construct a \(99 \%\) confidence interval for the slope of the line. What does the phrase "99\% confident" mean? $$ \begin{array}{r|rrrrr} x & -2 & -1 & 0 & 1 & 2 \\ \hline y & 1 & 1 & 3 & 5 & 5 \end{array} $$

Short Answer

Expert verified
Answer: No, there is not enough evidence to indicate that x and y are linearly related at the 1% significance level since the p-value (0.95) is much greater than the significance level (0.01). The 99% confidence interval for the slope of the line is (-23.52, 24.12).

Step by step solution

01

Organize the Data

First, let's organize the data into two separate lists for x and y values: $$ x = [-2, -1, 0, 1, 2] $$ $$ y = [1, 1, 3, 5, 5] $$
02

Calculate the Sum of the Data

Now calculate the sum of x, sum of y, sum of x times y, sum of x squared, and sum of y squared: $$ \Sigma x = -2 - 1 + 0 + 1 + 2 = 0 $$ $$ \Sigma y = 1 + 1 + 3 + 5 + 5 = 15 $$ $$ \Sigma xy = (-2)(1) + (-1)(1) + (0)(3) + (1)(5) + (2)(5) = 3 $$ $$ \Sigma x^2 = (-2)^2 + (-1)^2 + (0)^2 + (1)^2 + (2)^2 = 10 $$ $$ \Sigma y^2 = (1)^2 + (1)^2 + (3)^2 + (5)^2 + (5)^2 = 51 $$
03

Perform Hypothesis Test with t Statistic

We are going to perform the hypothesis test as follows, where n is the number of data points: - Null Hypothesis (H0): The slope of the regression line is equal to zero (no linear relation between x and y). - Alternative Hypothesis (H1): The slope of the regression line is not equal to zero (there is a linear relation between x and y). First, find the mean of x and y: $$ \bar{x} = \frac{\Sigma x}{n} = \frac{0}{5} = 0 $$ $$ \bar{y} = \frac{\Sigma y}{n} = \frac{15}{5} = 3 $$ Calculate the slope, b: $$ b = \frac{n\Sigma(xy) - (\Sigma x)(\Sigma y)}{n\Sigma x^2 - (\Sigma x)^2} = \frac{5(3) - (0)(15)}{5(10) - (0)^2} = \frac{15}{50} = 0.3 $$ Calculate the intercept, a: $$ a = \bar{y} - b\bar{x} = 3 - 0.3(0) = 3 $$ The linear regression equation is: $$ y = 3 + 0.3x $$ Calculate the standard error: $$ \text{SE} = \sqrt{\frac{\Sigma y^2 - b\Sigma(xy)}{n - 2}} = \sqrt{\frac{51 - 0.3(3)}{5 - 2}} = \sqrt{\frac{50.1}{3}} = 4.08 $$ Calculate the t statistic: $$ t = \frac{b}{\text{SE}} = \frac{0.3}{4.08} = 0.07 $$
04

Calculate the p-value and Determine Significance

Check the p-value associated with the t statistic (df = 3) in a t-table or using software. In this case, the p-value is approximately 0.95. Since the p-value is much greater than the 1% significance level, we fail to reject the null hypothesis. This means that we cannot conclude that there is a linear relationship between x and y at the 1% significance level.
05

Calculate the 99% Confidence Interval for the Slope

Using software or a t-table, find the critical t-value for a 99% confidence interval with 3 degrees of freedom (df = n -2). The critical t-value is approximately 5.84. Calculate the margin of error: $$ \text{Margin of Error} = \text{Critical t-value} \cdot \text{SE} = 5.84 \cdot 4.08 = 23.82 $$ Calculate the 99% confidence interval for the slope: $$ \text{Lower Limit} = 0.3 - 23.82 = -23.52 $$ $$ \text{Upper Limit} = 0.3 + 23.82 = 24.12 $$ The 99% confidence interval for the slope is: (-23.52, 24.12)
06

Explain the Phrase "99% Confident"

The phrase "99% confident" means that if we were to repeat this process of constructing a 99% confidence interval on numerous samples, 99% of the time, the true slope would be contained within the confidence interval. In this case, the 99% confident interval for the slope is so wide (-23.52, 24.12) that it provides little information about the actual slope of the line.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

T-test for Linearity
The t-test for linearity is a statistical tool used to establish whether there's a linear relationship between two variables, generally denoted as x and y. In essence, when we perform a linear regression analysis, we want to know if the independent variable x has a significant effect on the dependent variable y.

The Null Hypothesis (H0) posits there is no linear relation, meaning that the slope (b) of the regression line is zero. The Alternative Hypothesis (H1) claims otherwise—that there is a linear relationship, and the slope is not zero.

During this test, we calculate the t-statistic for the slope of the regression line using the formula:
\[ t = \frac{b}{SE_b}\]
where b is the estimated slope, and SE_b is the standard error of the slope. This statistic is then compared against a critical value from the t-distribution based on our level of significance and the degrees of freedom which, for regression, is typically n - 2 (where n is the number of observations). If the absolute value of the t-statistic is greater than the critical value, we reject the null hypothesis and conclude that there is evidence of linearity.
99% Confidence Interval Calculation
Understanding the 99% confidence interval involves knowing what we mean by being '99% confident' in our statistical analysis. When we're calculating a confidence interval for the slope of our regression line, we're essentially creating a range of values within which we believe the actual slope of our population lies, with a certain degree of certainty.

To calculate a 99% confidence interval, we need a critical value that corresponds to our chosen level of confidence—99% in this case. This value is obtained from the t-distribution table or through statistical software, which considers the degrees of freedom (df = n - 2).

The formula for the confidence interval is:
\[\text{Confidence Interval} = b \pm \text{Critical t-value} \times \text{SE}_b\]
Here, b represents the sample slope and SE_b represents the standard error of b. The resulting confidence interval tells us that we can be 99% confident the interval captures the true population slope. In practice, wider intervals indicate less precision, while narrower intervals suggest our estimate is more precise.
Hypothesis Testing in Statistics
Hypothesis testing is a foundational concept in statistics used to make inferences about populations based on sample data. It is a method through which we can test claims or hypotheses about a parameter, like the mean or proportion, in a quantitative manner.

It starts with two competing hypotheses: the null hypothesis (H0), which represents the status quo or a statement to be tested, and the alternative hypothesis (H1), which represents what we're trying to provide evidence for. The hypothesis test uses sample data to determine whether to reject H0, thereby supporting H1, or to not reject H0 based on a pre-determined level of significance (typically 5%, 1%, or 0.1%).

The process involves calculating a p-value, which is the probability of observing test results as extreme as those recorded, assuming the null hypothesis is true. If the p-value is less than our significance level, we reject H0. Otherwise, we do not have enough evidence to support the alternative hypothesis. This method, applied across scientific research and data analysis, isn't about proving the null hypothesis true but rather about assessing the strength of evidence against it.

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Most popular questions from this chapter

Fill in the missing entries in the analysis of variance table for a simple linear regression analysis and test for a significant regression with \(\alpha=.05\) in Exercises \(3-4 .\) Calculate the coefficient of determination, \(r^{2},\) and interpret its significance. $$ \begin{array}{lclll} \hline \text { Source } & d f & \text { SS } & \text { MS } & F \\ \hline \text { Regression } & & 3 & & \\ \text { Error } & 14 & & 2 & \\ \hline \text { Total } & & & & \\ \hline \end{array} $$

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The number of passes completed and the total number of passing yards were recorded for the Los Angeles Chargers quarter-back, Philip Rivers for each of the 16 regular season games that he played in the fall of \(2017 .^{12}\) Week 9 was a "bye" week, and no data were recorded. $$ \begin{array}{ccc|ccc} \hline \text { Week } & \text { Completions } & \text { Yardage } & \text { Week } & \text { Completions Yardage } \\ \hline 1 & 28 & 387 & 10 & 17 & 212 \\ 2 & 22 & 290 & 11 & 15 & 183 \\ 3 & 20 & 227 & 12 & 25 & 268 \\ 4 & 18 & 319 & 13 & 21 & 258 \\ 5 & 31 & 344 & 14 & 22 & 347 \\ 6 & 27 & 434 & 15 & 20 & 237 \\ 7 & 20 & 251 & 16 & 31 & 331 \\ 8 & 21 & 235 & 17 & 22 & 192 \\ \hline \end{array} $$ a. What is the least-squares line relating the total passing yards to the number of pass completions for Philip Rivers? b. What proportion of the total variation is explained by the regression of total passing yards \((y)\) on the number of pass completions \((x) ?\) c. If they are available, examine the diagnostic plots to check the validity of the regression assumptions.

Basics Use the information given in Exercises \(1-2\) (Exercises 1 and 3 , Section 12.2 ) to construct an ANOVA table for a simple linear regression analysis. Use the ANOVA \(F\) -test to test \(H_{0}: \beta=0\) with \(\alpha=.05 .\) Then calculate \(b\) and its standard error: Use a t statistic to test \(H_{0}: \beta=0\) with \(\alpha=.05 .\) Verify that within rounding \(t^{2}=F\). $$ n=8 \text { pairs }(x, y), S_{x x}=4, S_{y y}=20, S_{x y}=8 $$

Give the equation and graph for a line with y-intercept and slope given in Exercises. $$y \text { -intercept }=2.5 ; \text { slope }=0$$

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