Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Independent and Dependent Variables Identify which of the two variables in Exercises \(10-14\) is the independent variable \(x\) and which is the dependent variable $y . Number of ice cream cones sold by Baskin Robbins and the temperature on a given day.

Short Answer

Expert verified
Answer: The independent variable (x) is the temperature on a given day, and the dependent variable (y) is the number of ice cream cones sold by Baskin Robbins.

Step by step solution

01

Understand the variables and their relationship

The given problem has two variables - the number of ice cream cones sold by Baskin Robbins and the temperature on a given day. To identify the independent and dependent variables, let's analyze the relationship between these variables. As the temperature increases or decreases, this likely has an effect on the number of ice cream cones sold. In this scenario, sales of ice cream cones depend on the temperature.
02

Identify the independent variable (x)

The independent variable is the variable that doesn't depend on any other variable. In this case, the temperature on a given day is the independent variable (x) because it affects the number of ice cream cones sold, rather than being affected by it.
03

Identify the dependent variable (y)

The dependent variable is the variable that depends on the independent variable. Since the number of ice cream cones sold by Baskin Robbins depends on the temperature, the number of ice cream cones sold is the dependent variable (y). In summary, the independent variable (x) is the temperature on a given day, and the dependent variable (y) is the number of ice cream cones sold by Baskin Robbins.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variable Relationships
Understanding the relationships between variables is a fundamental concept in various fields, from statistics to the natural sciences. When trying to analyze how two things are connected, we talk about independent and dependent variables. The independent variable, often denoted by x, is the one you suspect is the cause of a change. It stands alone and is not influenced by other variables you are trying to measure.
For example, in the exercise regarding ice cream sales and temperature, the temperature is the independent variable because it changes due to external factors like the climate or time of year and can influence other factors – in this case, ice cream sales.
The dependent variable, which we denote by y, is the outcome you're looking at to see if it changes in response to the independent variable. In the exercise, the number of ice cream cones sold is the dependent variable as it changes potentially due to variations in temperature. This relationship helps us see patterns and make predictions; for instance, predicting ice cream sales based on weather forecasts.
Data Analysis
Data analysis entails scrutinizing, cleaning, transforming, and modeling data to gain useful information, draw conclusions, and support decision-making. In our example, analyzing the data on ice cream sales and temperature involves looking at how the two variables correlate and possibly making predictive models.
In practice, this might mean plotting the data points on a graph with temperature on the x-axis and ice cream sales on the y-axis. If there's a trend, such as higher sales on hotter days, this could appear as an upward slope on the graph. Statisticians use various tools, including correlation coefficients and regression analysis, to quantify the strength and nature of the relationship between the two variables. For students, learning these analysis techniques is essential as they apply to virtually any field, from business to environmental science.
Statistics Education
Statistics education is about equipping students with the ability to collect, analyze, interpret, and present data. The goal is not only to develop technical skills but also critical thinking. It's one thing to calculate numbers and another to understand what those numbers imply in a real-world context.
For instance, in our example of ice cream sales and temperature, students learn to not only identify the independent and dependent variables but to understand causation versus correlation. Just because two variables are correlated does not imply that one causes the other. Robust statistical education involves learning about potential pitfalls, such as confounding variables – perhaps the ice cream sales are also affected by a local event that coincides with warmer weather.
Subsequently, through exercises like these, students learn the importance of considering various factors when analyzing data, which is a critical skill in today's data-driven world.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the data given in Exercises 6-7 (Exercises 17-18, Section 12.1). Construct the ANOVA table for a simple linear regression analysis, showing the sources, degrees of freedom, sums of squares, and mean sauares. $$\begin{array}{l|rrrrrrr}x & -2 & -1 & 0 & 1 & 2 \\\\\hline y & 1 & 1 & 3 & 5 & 5\end{array}$$

Is there any relationship between these two variables? To find out, we randomly selected 12 people from a data set constructed by Allen Shoemaker (Journal of Statistics Education) and recorded their body temperature and heart rate. \({ }^{19}\) $$\begin{array}{lllllll}\hline \text { Person } & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline \text { Temperature } & 96.3 & 97.4 & 98.9 & 99.0 & 99.0 & 96.8 \\ \text { (degrees) } & & & & & & \\\\\text { Heart Rate } & 70 & 68 & 80 & 75 & 79 & 75 \\\\\text { (beats per } & & & & & & \\\\\text { minute) } & & & & & & \\\ \hline\end{array}$$ $$\begin{array}{lllllll}\hline \text { Person } & 7 & 8 & 9 & 10 & 11 & 12 \\\\\hline \text { Temperature } & 98.4 & 98.4 & 98.8 & 98.8 & 99.2 & 99.3 \\\\\multicolumn{2}{l} {\text { (degrees) }} & & & & & & \\\\\text { Heart Rate } & 74 & 84 & 73 & 84 & 66 & 68 \\\\\text { (beats per } & & & & & & \\\\\text { minute) } & & & & & & & \\\& & & & \\\\\hline\end{array}$$ a. Find the correlation coefficient \(r\), relating body temperature to heart rate. b. Is there sufficient evidence to indicate that there is a correlation between these two variables? Test at the 5\% level of significance.

Find the least-squares line for the data. Plot the points and graph the line on the same graph. Does the line appear to provide a good fit to the data points? $$\begin{array}{c|cccccc}x & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline y & 5.6 & 4.6 & 4.5 & 3.7 & 3.2 & 2.7\end{array}$$

10\. Recidivism Recidivism refers to the return to prison of a prisoner who has been released or paroled. The data that follow reports the group median age at which a prisoner was released from a federal prison and the percentage of those arrested for another crime. \({ }^{7}\) Use the MS Excel printout to answer the questions that follow. $$ \begin{array}{l|lllllll} \text { Group Median Age }(x) & 22 & 27 & 32 & 37 & 42 & 47 & 52 \\ \hline \text { \% Arrested }(y) & 64.7 & 59.3 & 52.9 & 48.6 & 44.5 & 37.7 & 23.5 \end{array} $$ $$ \begin{aligned} &\text { SUMMARY OUTPUT }\\\ &\begin{array}{ll} \hline \text { Regression Statistics } & \\ \hline \text { Multiple R } & 0.9779 \\ \text { R Square } & 0.9564 \\ \text { Adjusted R Square } & 0.9477 \\ \text { Standard Error } & 3.1622 \\ \text { Observations } & 7.0000 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { ANOVA }\\\ &\begin{array}{llrrr} \hline & & & & {\text { Significance }} \\ & \text { df } & \text { SS } & \text { MS } & \text { F } & \text { F } \\ & & & & & \\ \hline \text { Regression } & 1 & 1096.251 & 1096.251 & 109.631 & 0.000 \\ \text { Residual } & 5 & 49.997 & 9.999 & & \\ \text { Total } & 6 & 1146.249 & & & \\ \hline \end{array} \end{aligned} $$ $$ \begin{array}{lrrrrrr} \hline& {\text { Coeffi- Standard }} \\ & \text { cients } & \text { Error } & \text { tStat } & \text { P-value } & \text { Lower } 95 \% & \text { Upper } 95 \% \\ \hline \text { Intercept } & 93.617 & 4.581 & 20.436 & 0.000 & 81.842 & 105.393 \\ \mathrm{x} & -1.251 & 0.120 & -10.471 & 0.000 & -1.559 & \- \\ \hline \end{array} $$ a. Find the least-squares line relating the percentage arrested to the group median age. b. Do the data provide sufficient evidence to indicate that \(x\) and \(y\) are linearly related? Test using the \(t\) statistic at the \(5 \%\) level of significance. c. Construct a \(95 \%\) confidence interval for the slope of the line. d. Find the coefficient of determination and interpret its significance.

Give the equation and graph for a line with y-intercept and slope given in Exercises. $$y \text { -intercept }=2.5 ; \text { slope }=0$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free