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Is it appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) in the following circumstances? a. \(n=50, p=.05\) b. \(n=75, p=.1\) c. \(n=250, p=.99\)

Short Answer

Expert verified
a. \(n=50, p=.05\) b. \(n=75, p=.1\) c. \(n=250, p=.99\) Answer: It is not appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) in any of the given circumstances.

Step by step solution

01

a. \(n=50, p=.05\)

First, we need to check if the sample size is large enough. Calculate \(np\) and \(n(1-p)\): \(np = 50 \times 0.05 = 2.5\) \(n(1-p) = 50 \times (1-0.05) = 47.5\) Since \(np\) is less than 10, it is not appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) in this case.
02

b. \(n=75, p=.1\)

First, we need to check if the sample size is large enough. Calculate \(np\) and \(n(1-p)\): \(np = 75 \times 0.1 = 7.5\) \(n(1-p) = 75 \times (1-0.1) = 67.5\) Since \(np\) is less than 10, it is not appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) in this case.
03

c. \(n=250, p=.99\)

First, we need to check if the sample size is large enough. Calculate \(np\) and \(n(1-p)\): \(np = 250 \times 0.99 = 247.5\) \(n(1-p) = 250 \times (1-0.99) = 2.5\) Since \(n(1-p)\) is less than 10, it is not appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) in this case. In conclusion, it is not appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) in any of the given circumstances.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Distribution
The concept of sampling distribution is key in statistics. It refers to the probability distribution of a statistic obtained through a large number of samples drawn from a specific population. Each sample consists of a certain number of observations, and its statistics, like the sample mean or sample proportion, can differ from sample to sample. When you repeat the sampling process many times, you'll have a distribution of those statistics which we call the sampling distribution.
This distribution can help us understand how the sample statistic is likely to vary and whether it accurately reflects the population parameter. A common task in statistics is to determine the shape of this distribution. Under specific conditions, it might resemble a normal distribution, which eases further analysis and calculations.
It's important to assess whether a normal distribution can approximate a sampling distribution based on criteria like sample size and proportion values.
Sample Size
Sample size plays a crucial role in determining the appropriateness of using a normal distribution for approximation. Large samples generally lead to more reliable and stable estimates of the population parameter. In statistics, a rule of thumb is to ensure that both the product of the sample size () and the sample proportion (p), and its complement (1-p), should be at least 10.
This condition: \(np \geq 10\) and \(n(1-p) \geq 10\) is used to justify the use of the normal distribution as an approximation of the sampling distribution. A larger sample size also reduces the margin of error, leading to more precise estimates. If p or (1-p) is small, the sample would need to be much larger for the approximation to be valid.
Approximation
The process of approximation involves using a known distribution to estimate a sampling distribution when it's complicated or inconvenient to determine its exact form. The normal distribution is frequently used for this purpose due to its well-defined properties. Approximating a sampling distribution with a normal distribution allows statisticians to use z-scores and standard deviation to calculate probabilities quickly and easily.
However, the approximation is valid only under certain conditions, such as having a sufficiently large sample size and certain distribution properties. You should always check the conditions (e.g., \(np \geq 10\) and \(n(1-p) \geq 10\)) to ensure the approximation gives meaningful results.
Otherwise, relying on the normal distribution might lead to inaccurate conclusions about the probability and characteristics of the sample statistics.
Probability
Probability underlies the entire process of inferring from a sample to a population. It's the mathematical framework that allows us to estimate and predict how likely certain outcomes are, given certain conditions. In the context of sampling distributions, probability helps determine whether using a normal distribution approximation is logical.
If conditions are met, the normal distribution can reliably reflect the probability behavior of sample statistics. This is based on the Central Limit Theorem, which states that, for sufficiently large samples, the distribution of the sample mean will be approximately normal regardless of the shape of the population distribution.
  • When analyzing sample proportions, calculating the probability that these proportions align closely with population proportions is often of interest.
  • Proper probability models allow statisticians to understand the likelihood of various outcomes when drawing samples from a population.
In conclusion, probability allows us to leverage the normal distribution's properties to make predictions based on samples with confidence, only if the conditions for approximation are valid.

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Most popular questions from this chapter

Recycling trash, reducing waste, and reusing materials are eco-actions that will help the environment. According to a USA Today snapshot (Exercise 6.45), \(78 \%\) of respondents list recycling as the leading way to help our environment. \({ }^{11}\) Suppose that a random sample of \(n=100\) adults is selected and that the \(78 \%\) figure is correct. a. Does the distribution of \(\hat{p},\) the sample proportion of adults who list recycling as the leading way to help the environment have an approximate normal distribution? If so, what is its mean and standard deviation? b. What is the probability that the sample proportion \(\hat{p}\) is less than \(75 \% ?\) c. What is the probability that \(\hat{p}\) lies in the interval .7 to .75? d. What might you conclude about \(p\) if the sample proportion were less than \(.65 ?\)

A bottler of soft drinks packages cans in six-packs. Suppose that the fill per can has an approximate normal distribution with a mean of 12 fluid ounces and a standard deviation of 0.2 fluid ounces. a. What is the distribution of the total fill for a case of 24 cans? b. What is the probability that the total fill for a case is less than 286 fluid ounces? c. If a six-pack of soda can be considered a random sample of size \(n=6\) from the population, what is the probability that the average fill per can for a six-pack of soda is less than 11.8 fluid ounces?

The normal daily human potassium requirement is in the range of 2000 to 6000 milligrams (mg), with larger amounts required during hot summer weather. The amount of potassium in food varies, but bananas are often associated with high potassium, with approximately \(422 \mathrm{mg}\) in a medium sized banana \(^{8}\). Suppose the distribution of potassium in a banana is normally distributed, with mean equal to \(422 \mathrm{mg}\) and standard deviation equal to \(13 \mathrm{mg}\) per banana. You eat \(n=3\) bananas per day, and \(T\) is the total number of milligrams of potassium you receive from them. a. Find the mean and standard deviation of \(T\). b. Find the probability that your total daily intake of potassium from the three bananas will exceed \(1300 \mathrm{mg} .\) (HINT: Note that \(T\) is the sum of three random variables, \(x_{1}, x_{2},\) and \(x_{3},\) where \(x_{1}\) is the amount of potassium in banana number \(1,\) etc. \()\)

The sample means were calculated for 40 samples of size \(n=5\) for a process that was judged to be in control. The means of the 40 values and the standard deviation of the combined 200 measurements were \(\overline{\bar{x}}=155.9\) and \(s=4.3,\) respectively. a. Use the data to determine the upper and lower control limits for an \(\bar{x}\) chart. b. Construct an \(\bar{x}\) chart for the process and explain how it can be used.

A population consists of \(N=5\) numbers: \(1,3,5,6,\) and 7 . It can be shown that the mean and standard deviation for this population are \(\mu=4.4\) and \(\sigma=2.15,\) respectively. a. Construct a probability histogram for this population. b. Use the random number table, Table 10 in Appendix I, to select a random sample of size \(n=10\) with replacement from the population. Calculate the sample mean, \(\bar{x}\). Repeat this procedure, calculating the sample mean \(\bar{x}\) for your second sample. To simulate the sampling distribution of \(\bar{x}\), we have selected 50 more samples of size \(n=10\) with replacement, and have calculated the corresponding sample means. Construct a relative frequency histogram for these 50 values of \(\bar{x}\). What is the shape of this distribution?

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