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Evidence shows that the probability that a driver will be involved in a serious automobile accident during a given year is .01. A particular corporation employs 100 full-time traveling sales reps. Based on this evidence, use the Poisson approximation to the binomial distribution to find the probability that exactly two of the sales reps will be involved in a serious automobile accident during the coming year.

Short Answer

Expert verified
Answer: The probability that exactly two sales reps will have a serious automobile accident in the coming year is approximately 0.18394 or 18.39%.

Step by step solution

01

Write down the Poisson distribution formula

Recall the Poisson distribution formula: P(X = k) = (e^(-λ) * (λ^k)) / k! where λ is the mean number of accidents, k is the number of accidents we want to find the probability for, and e is the base of the natural logarithm.
02

Plug in the values

For this problem, λ = 1 (mean number of accidents), k = 2 (number of accidents we want the probability for), and e ≈ 2.71828. Plug the values into the formula: P(X = 2) = (e^(-1) * (1^2)) / 2!
03

Calculate the probability

Perform the calculations: P(X = 2) = (2.71828^(-1) * (1^2)) / 2 P(X = 2) ≈ (0.36788 * 1) / 2 P(X = 2) ≈ 0.18394 So, the probability that exactly two sales reps will be involved in a serious automobile accident during the coming year is approximately 0.18394 or 18.39%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Binomial Distribution
The binomial distribution is a common way to model situations where there are only two possible outcomes: success or failure. It's especially useful in scenarios where you're conducting an experiment several times, and each time the likelihood of success is constant.
In the original exercise, the scenario involves drivers who may or may not be involved in a car accident, and it can be seen as a binomial distribution. However, when dealing with a large number of trials (in this case, 100 sales reps) and a small probability of success (0.01, where success refers to having an accident), it becomes more efficient to use a different approach. This is where the Poisson distribution can approximate the binomial distribution very well.
  • This approximation is valid when the number of trials is large, and the probability of success is small.
  • The Poisson distribution helps simplify calculations that might otherwise be complex with the binomial distribution.
Understanding when and why to use these distributions is vital for solving real-world statistical problems efficiently.
Exploring Probability in the Context
Probability is the field of mathematics that deals with the likelihood or chance of different outcomes occurring. In the context of the Poisson approximation to the binomial distribution, it's all about estimating how often an event will occur in a given period.
For our exercise, the main task was to calculate the probability of exactly two sales reps being involved in a serious accident in one year, using the Poisson distribution.
  • This involves knowing two key parameters: the mean number of events (accidents, in this case) that occur, represented as \( \lambda \), and the set number of events we want to calculate the probability for.
  • Probability is a crucial component that enables accurate forecasting and decision-making in various fields.
By refining and understanding these probabilities, businesses and governments can make informed choices about resource allocation and risk management.
Mean Number of Events: Why It Matters
The term \( \lambda \) in the Poisson formula represents the mean number of events expected to occur in a fixed interval of time or space. It's essential because it simplifies how we calculate probabilities for rare events happening a given number of times.
In the example provided, the mean number of sales reps expected to be involved in serious car accidents is calculated by multiplying the total number of sales reps (100) by the probability of each being involved in an accident (0.01), thus \( \lambda = 100 \times 0.01 = 1.0 \).
  • This mean number forms the backbone of the Poisson calculation, allowing us to plug in values and compute probabilities with ease.
  • Understanding \( \lambda \) fully helps in anticipating the behavior of rare events across broader time frames and situations.
Effectively, it offers a lens through which statisticians and analysts can predict frequencies of occurrences efficiently, influencing how safety measures and preventive actions are considered.

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Most popular questions from this chapter

College campuses are graying! According to a recent article, one in four college students is aged 30 or older. Assume that the \(25 \%\) figure is accurate, that your college is representative of colleges at large, and that you sample \(n=200\) students, recording \(x\), the number of students age 30 or older. a. What are the mean and standard deviation of \(x ?\) b. If there are 35 students in your sample who are age 30 or older, would you be willing to assume that the \(25 \%\) figure is representative of your campus? Explain.

Let \(x\) be the number of successes observed in a sample of \(n=5\) items selected from \(N=10 .\) Suppose that, of the \(N=10\) items, 6 are considered "successes." a. Find the probability of observing no successes. b. Find the probability of observing at least two successes. c. Find the probability of observing exactly two successes

The 10 -year survival rate for bladder cancer is approximately \(50 \%\). If 20 people who have bladder cancer are properly treated for the disease, what is the probability that: a. At least 1 will survive for 10 years? b. At least 10 will survive for 10 years? c. At least 15 will survive for 10 years?

Defective Computer Chips A piece of electronic equipment contains six computer chips, two of which are defective. Three computer chips are randomly chosen for inspection, and the number of defective chips is recorded. Find the probability distribution for \(x\), the number of defective computer chips. Compare your results with the answers obtained in Exercise \(4.90 .\)

Suppose that one out of every 10 homeowners in the state of California has invested in earthquake insurance. If 15 homeowners are randomly chosen to be interviewed, a. What is the probability that at least one had earthquake insurance? b. What is the probability that four or more have earthquake insurance? c. Within what limits would you expect the number of homeowners insured against earthquakes to fall?

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