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Suppose that \(P(A)=.3\) and \(P(B)=.5 .\) If events \(A\) and \(B\) are mutually exclusive, find these probabilities: a. \(P(A \cap B)\) b. \(P(A \cup B)\)

Short Answer

Expert verified
Answer: For mutually exclusive events A and B, a. The probability of their intersection, P(A ∩ B), is 0. b. The probability of their union, P(A ∪ B), is 0.8.

Step by step solution

01

Understand the properties of mutually exclusive events

When two events are mutually exclusive, it means that they cannot occur at the same time. In other words, if one of them occurs, the other cannot. Mathematically, it means that the intersection of the two events is the empty set, i.e., \(P(A \cap B) = 0\).
02

Find the probability of A intersection B

Since A and B are mutually exclusive, the probability of their intersection is 0. Therefore, \(P(A \cap B) = 0\).
03

Find the probability of A union B

To find the probability of the union of A and B, we can use the formula for the probability of the union of two events: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\). Since we already know that \(P(A \cap B) = 0\), we can simplify this formula as \(P(A \cup B) = P(A) + P(B)\). Plug the given values into the formula: \(P(A \cup B) = P(A) + P(B) = 0.3 + 0.5 = 0.8\). The probabilities for these events are: a. \(P(A \cap B) = 0\) b. \(P(A \cup B) = 0.8\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutually Exclusive Events
Mutually exclusive events are events that cannot occur simultaneously. Think of these events like two separate doors; choosing one automatically excludes the other. In probability terms, if two events are mutually exclusive, the probability of them both occurring at the same time is zero. This is mathematically represented as \( P(A \cap B) = 0 \).

An example to visualize this is flipping a coin—obtaining a "heads" and a "tails" in one flip is impossible, hence mutually exclusive. Understanding this principle is important because it helps us in calculating probabilities related to these events correctly.
Probability of Intersection
The probability of intersection between two events refers to the likelihood that both events will happen at the same time. In mathematical terms, this is defined by \( P(A \cap B) \).

For mutually exclusive events, as mentioned earlier, this probability is zero because they cannot occur together. However, if events were not mutually exclusive, an example might include drawing a red card and a king from a deck of cards—the king can also be red. In scenarios where events aren't mutually exclusive, intersections are calculated considering common elements between events.

Knowing how to calculate intersections allows us to dive deeper into more complex probability scenarios.
Probability of Union
The probability of the union of two events refers to the probability that at least one of the events will occur. It’s symbolized by \( P(A \cup B) \). The formula is \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \).

In simpler terms, this formula helps to calculate the chances of either event A happening, event B happening, or both, ensuring not to double-count the overlap if they intersect. For mutually exclusive events, since their intersection is zero, the formula simplifies to \( P(A \cup B) = P(A) + P(B) \).

This union concept extends to broader applications, such as calculating the probability of at least one success in multiple independent trials, forming the foundation for more advanced statistical methods.

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Most popular questions from this chapter

Choosing a Mate Men and women often disagree on how they think about selecting a mate. Suppose that a poll of 1000 individuals in their twenties gave the following responses to the question of whether it is more important for their future mate to be able to communicate their feelings ( \(F\) ) than it is for that person to make a good living \((G)\). $$\begin{array}{lccc} & \text { Feelings }(F) & \text { Good Living }(G) & \text { Totals } \\\\\hline \text { Men }(M) & .35 & .20 & .55 \\\\\text { Women }(W) & .36 & .09 & .45 \\\\\hline \text { Totals } & 71 & 29 & 1.00\end{array}$$ If an individual is selected at random from this group of 1000 individuals, calculate the following probabilities: a. \(P(F)\) b. \(P(G)\) c. \(P(F \mid M)\) d. \(P(F \mid W)\) e. \(P(M \mid F)\) f. \(P(W \mid G)\)

Suppose a group of research proposals was evaluated by a panel of experts to decide whether or not they were worthy of funding. When these same proposals were submitted to a second independent panel of experts, the decision to fund was reversed in \(30 \%\) of the cases. If the probability that a proposal is judged worthy of funding by the first panel is \(.2,\) what are the probabilities of these events? a. A worthy proposal is approved by both panels. b. A worthy proposal is disapproved by both panels. c. A worthy proposal is approved by one panel.

A salesperson figures that the probability of her making a sale during the first contact with a client is .4 but improves to .55 on the second contact if the client did not buy during the first contact. Suppose this salesperson makes one and only one callback to any client. If she contacts a client, calculate the probabilities for these events: a. The client will buy. b. The client will not buy.

Let \(x\) equal the number observed on the throw of a single balanced die. a. Find and graph the probability distribution for \(x\). b. What is the average or expected value of \(x ?\) c. What is the standard deviation of \(x ?\) d. Locate the interval \(\mu \pm 2 \sigma\) on the \(x\) -axis of the graph in part a. What proportion of all the measurements would fall into this range?

You can insure a \(\$ 50,000\) diamond for its total value by paying a premium of \(D\) dollars. If the probability of loss in a given year is estimated to be .01 , what premium should the insurance company charge if it wants the expected gain to equal \$1000?

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