Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In how many ways can you select two people from a group of 20 if the order of selection is not important?

Short Answer

Expert verified
Answer: There are 190 ways to select two people from a group of 20 when the order of selection does not matter.

Step by step solution

01

Understanding Combinations

Combinations refer to selecting items from a larger set such that the order of selection does not matter. In other words, it's a selection where the elements have no order. In this exercise, we need to select two people from a group of 20 people. Since the order of selection is not important, we can use the combinations formula to solve this problem. The notation we use for a combination is 'C(n, r)', where 'n' is the number of items to choose from, and 'r' is the number of items we want to choose.
02

Formula for Combinations

The formula for combinations is given by C(n, r) = \frac{n!}{r!(n-r)!}, where '!' denotes factorial ('n!' means you multiply all positive integers from 1 up to 'n', i.e., 5! = 5 × 4 × 3 × 2 × 1 = 120).
03

Applying the Combinations Formula

Now, let's apply the combinations formula to find the number of ways to select two people from a group of 20. We have 'n' = 20 (the total number of people) and 'r' = 2 (the number of people we want to select). So, we can plug these values into the combinations formula: C(20,2) = \frac{20!}{2!(20-2)!}.
04

Calculate the Factorials

Next, we need to calculate the factorials in the formula: 1. 20! = 20 × 19 × 18 × ... × 3 × 2 × 1 2. 2! = 2 × 1 3. (20-2)! = 18! = 18 × 17 × 16 × ... × 3 × 2 × 1
05

Simplify and Solve

Now, let's simplify and solve the expression: C(20,2) = \frac{20!}{2!(20-2)!} = \frac{20!}{2!18!} We can cancel out some terms in the expression to simplify it: C(20,2) = \frac{20 × 19 × 18 × ... × 3 × 2 × 1}{(2 × 1)(18 × 17 × 16 × ... × 3 × 2 × 1)} Since 18 and remaining terms are in both the numerator and denominator, we can cancel them out: C(20,2) = \frac{20 × 19}{2 × 1} = \frac{380}{2} = 190 So, there are 190 different ways to select two people from a group of 20 when the order of selection is not important.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorials
Factorials are a fundamental concept in mathematics, especially when dealing with permutations and combinations. A factorial of a number, denoted by an exclamation mark (!), is the product of all positive integers up to that number. For example, the factorial of 5 is written as 5! and calculated as 5 × 4 × 3 × 2 × 1 = 120.
Factorials are crucial in combinations because they help calculate the total number of ways to order a set of items, and in the context of combinations, they help determine the different ways to select items without regard to order.
For a given number \( n \), the factorial \( n! \) can be calculated as follows:
  • Start with the number \( n \).
  • Multiply it by each consecutive integer less than itself, down to 1.
Factorials grow quickly as \( n \) increases, and converting these into calculations using formulas is essential in combinatorics.
Combinatorics
Combinatorics is the branch of mathematics that deals with counting, arranging, and analyzing possibilities and structures. It is often focused on finite sets or countable discrete structures. Among its many applications, combinatorics is crucial for solving problems where the task is to determine how many different ways an event can happen.
An important tool in combinatorics is the combination formula, which tells us how many ways we can choose a subset of items from a larger set when the order is not important. This particular form of combinatorial calculation is known as 'combinations', where we use the combination formula given by:\[C(n, r) = \frac{n!}{r!(n-r)!}\]Here:
  • \( n \) is the total number of items to choose from.
  • \( r \) is the number of items we want to select.
  • Factorials are vital to compute combinations efficiently.
In the exercise, when you are selecting 2 people from a group of 20, you are employing combinatorics to determine all possible pairs without regard to order.
Selection Without Order
Selection without order refers to choosing items from a set where the order in which the items are selected does not matter. In real-world scenarios, this is applicable in situations like forming teams or groups where the identity of members matters but the position does not.
For example, if you have a group of 20 people and you need to select 2 for a project, it doesn't matter if you choose person A first and person B second or vice versa. What matters is the pair of people you have chosen, not the sequence in which you picked them.
Combinations are used to solve problems of selection without order. This ensures that each possible selection is considered equivalent, regardless of the order in which it appears. By applying the formula for combinations, you can confidently determine how many unique groups or subsets can be formed, as seen in our example exercise which resulted in 190 distinct selections of 2 people from 20.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The board of directors of a major symphony orchestra has voted to create a committee for the purpose of handling employee complaints. The committee will consist of the president and vice president of the symphony board and two orchestra representatives. The two orchestra representatives will be randomly selected from a list of six volunteers, consisting of four men and two women. a. Find the probability distribution for \(x\), the number of women chosen to be orchestra representatives. b. What is the probability that both orchestra representatives will be women? able \(x\).

Most coffee drinkers take a little time each day for their favorite beverage, and many take more than one coffee break every day. The table below, adapted from a Snapshot in \(U S A\) Today, shows the probability distribution for \(x\), the number of daily coffee breaks taken per day by coffee drinkers. \({ }^{8}\) $$\begin{array}{l|lllllll}x & 0 & 1 & 2 & 3 & 4 & 5 \\\\\hline p(x) & .28 & .37 & .17 & .12 & .05 & .01\end{array}$$ a. What is the probability that a randomly selected coffee drinker would take no coffee breaks during the day? b. What is the probability that a randomly selected coffee drinker would take more than two coffee breaks during the day? c. Calculate the mean and standard deviation for the random variable \(x\). d. Find the probability that \(x\) falls into the interval \(\mu \pm 2 \sigma\).

A random variable \(x\) has this probability distribution: $$\begin{array}{l|llllll}x & 0 & 1 & 2 & 3 & 4 & 5 \\\\\hline p(x) & .1 & .3 & .4 & .1 & ? & .05\end{array}$$ a. Find \(p(4)\). b. Construct a probability histogram to describe \(p(x)\). c. Find \(\mu, \sigma^{2},\) and \(\sigma\). d. Locate the interval \(\mu \pm 2 \sigma\) on the \(x\) -axis of the histogram. What is the probability that \(x\) will fall into this interval? e. If you were to select a very large number of values of \(x\) from the population, would most fall into the interval \(\mu \pm 2 \sigma\) ? Explain.

A research physician compared the effectiveness of two blood pressure drugs \(A\) and \(B\) by administering the two drugs to each of four pairs of identical twins. Drug \(A\) was given to one member of a pair; drug \(B\) to the other. If, in fact, there is no difference in the effects of the drugs, what is the probability that the drop in the blood pressure reading for drug \(A\) exceeds the corresponding drop in the reading for drug \(B\) for all four pairs of twins? Suppose drug \(B\) created a greater drop in blood pressure than drug \(A\) for each of the four pairs of twins. Do you think this provides sufficient evidence to indicate that drug \(B\) is more effective in lowering blood pressure than drug \(A\) ?

Suppose a group of research proposals was evaluated by a panel of experts to decide whether or not they were worthy of funding. When these same proposals were submitted to a second independent panel of experts, the decision to fund was reversed in \(30 \%\) of the cases. If the probability that a proposal is judged worthy of funding by the first panel is \(.2,\) what are the probabilities of these events? a. A worthy proposal is approved by both panels. b. A worthy proposal is disapproved by both panels. c. A worthy proposal is approved by one panel.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free