Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Two men each toss a coin. They obtain a "match" if either both coins are heads or both are tails. Suppose the tossing is repeated three times. a. What is the probability of three matches? b. What is the probability that all six tosses (three for each man) result in tails? c. Coin tossing provides a model for many practical experiments. Suppose that the coin tosses represent the answers given by two students for three specific true-false questions on an examination. If the two students gave three matches for answers, would the low probability found in part a suggest collusion?

Short Answer

Expert verified
Answer: The probability of getting three matches in three consecutive coin tosses is 1/8 (12.5%). The probability of all six tosses being tails is 1/64 (1.56%). Although the probability of getting three matches is low, it does not necessarily suggest collusion between two students. Other factors, such as similarity in wrong answers and the relationship between the students, should be considered before drawing any conclusions.

Step by step solution

01

Calculate the probability of a match in a single toss

In a single toss, there are 4 possible outcomes: HH, HT, TH, and TT. Two of these outcomes are matches (HH and TT). So, the probability of a match in a single toss is: P(match) = Number of matches outcomes / Total number of outcomes P(match) = 2 / 4 = 1 / 2
02

Calculate the probability of three matches

Since the coin tosses are independent events, we can find the probability of three matches by multiplying the probabilities of matches in each toss. So the probability of three matches is: P(3 matches) = P(match) * P(match) * P(match) = (1/2) * (1/2) * (1/2) = 1 / 8
03

Calculate the probability of getting tails in a single toss

In a single coin toss, there are two possible outcomes: heads (H) and tails (T). The probability of getting tails is: P(Tails) = Number of tails outcomes / Total number of outcomes P(Tails) = 1 / 2
04

Calculate the probability of all six tosses being tails

Again, since the tosses are independent, we can find the probability of all six tosses being tails by multiplying the probabilities in each toss. P(All 6 tails) = P(Tails) * P(Tails) * P(Tails) * P(Tails) * P(Tails) * P(Tails) = (1/2)^6 = 1 / 64
05

Analyze if low probability suggests collusion

From part a, we found that the probability of getting three matches is 1/8, which means there is a 12.5% chance of two independent coin tosses having three matches. The low probability might seem suspicious at first, but it is important to consider other factors before concluding collusion between the two students. It is not rare for independent events to produce matching outcomes occasionally, and a 12.5% probability is not exceptionally low. So, it would not be correct to suggest collusion solely based on the probability found in part a. Other factors, like the similarity in the wrong answers and the relationship between the students, should be taken into account before making any conclusions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coin Toss
A coin toss is a simple yet fascinating probability exercise. When you toss a coin, there are two possible outcomes: heads (H) or tails (T). For each toss, the chance of the coin landing on heads or tails is equal, which makes it a perfect example of a 50-50 chance. Coin tossing is considered a model for random events, meaning each toss is independent of the previous one. The outcome of one toss does not affect the result of the next. Understanding the nature of a coin toss is crucial when analyzing multiple tosses in sequence, like the exercise where two men toss coins to achieve matching results.
Independent Events
Independent events are those where the outcome of one event does not influence the outcome of another. Each coin toss in the exercise is independent, as the result of one coin has no bearing on the next. This concept is essential in calculating probabilities because it allows you to multiply the probabilities of individual events to find the total probability of a sequence of independent events occurring.For example, when calculating the probability of three consecutive matches in the coin toss exercise, each toss remains independent, so you multiply the probability of a single match \( \left( \frac{1}{2} \right) \) three times: \( \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right) = \frac{1}{8} \). This demonstrates how understanding independence helps in solving complex probability problems.
Match Probability
Match probability refers to the chance that two independent events will produce the same outcome, like both coins landing heads or tails in the same toss. In the given problem, a match occurs when both men have the same result, either both heads (HH) or both tails (TT). Since there are four possible outcomes per toss (HH, HT, TH, TT), and two are considered matches, the probability of a match per toss is \( \frac{2}{4} = \frac{1}{2} \).Understanding match probability is essential when calculating more complex sequences of events. For instance, to find the probability of achieving three matches in a row, you simply multiply the probability of each match, considering the independence of tosses. This leads to a probability of \( \frac{1}{8} \), highlighting how probabilities compound over multiple independent events.
Collusion Analysis
Collusion analysis involves looking at whether a pattern of results, like the matching answers in exams, suggests cooperation between participants. In the example exercise, we see a slight concern about collusion because two students provide matching answers more often than expected. However, while the probability of getting three matches in a row is relatively low at 12.5%, it is not so low as to be highly suspicious by itself. To assess the possibility of collusion, other factors should be considered. These might include:
  • Similarity in incorrect answers, not just matches.
  • Any known relationship or previous cooperation between the individuals.
  • Additional statistical patterns over multiple tests or conditions.
A simple probability calculation can raise questions but is just one piece of the puzzle when investigating potential collusion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A certain virus afflicted the families in three adjacent houses in a row of 12 houses. If houses were randomly chosen from a row of 12 houses, what is the probability that the three houses would be adjacent? Is there reason to believe that this virus is contagious?

Exercise 4.10 described the game of roulette. Suppose you bet \(\$ 5\) on a single number-say, the number \(18 .\) The payoff on this type of bet is usually 35 to \(1 .\) What is your expected gain?

A man takes either a bus or the subway to work with probabilities .3 and \(.7,\) respectively. When he takes the bus, he is late \(30 \%\) of the days. When he takes the subway, he is late \(20 \%\) of the days. If the man is late for work on a particular day, what is the probability that he took the bus?

A college student frequents one of two coffee houses on campus, choosing Starbucks \(70 \%\) of the time and Peet's \(30 \%\) of the time. Regardless of where she goes, she buys a cafe mocha on \(60 \%\) of her visits. a. The next time she goes into a coffee house on campus, what is the probability that she goes to Starbucks and orders a cafe mocha? b. Are the two events in part a independent? Explain. c. If she goes into a coffee house and orders a cafe mocha, what is the probability that she is at Peet's? d. What is the probability that she goes to Starbucks or orders a cafe mocha or both?

A smoke-detector system uses two devices, \(A\) and \(B\). If smoke is present, the probability that it will be detected by device \(A\) is .95 by device \(B, .98 ;\) and by both devices, .94 a. If smoke is present, find the probability that the smoke will be detected by device \(A\) or device \(B\) or both devices. b. Find the probability that the smoke will not be detected.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free