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Use Table 5 in Appendix I to bound the \(p\) -value for a chi-square test: a. \(X^{2}=4.29, d f=5\) b. \(X^{2}=20.62, d f=6\)

Short Answer

Expert verified
Answer: a) The p-value is bounded between 0.1 and 0.2. b) The p-value is bounded between 0.001 and 0.01.

Step by step solution

01

Locate the Appropriate Row in Appendix I Table 5

First, you need to find the row that corresponds to the degrees of freedom in the given problem. In this case, the degrees of freedom (df) are 5. Locate the row labeled "5" in the "df" column of Table 5 in Appendix I.
02

Find the Column(s) Where the Chi-Square Statistic Lies

Next, you need to identify the columns where the given \(X^{2}\) statistic (4.29) lies between. Look for the values in the row corresponding to the degrees of freedom that are closest to, but greater than and less than 4.29. In this case, you will find that the \(X^{2}\) statistic lies between the values in the columns labeled "0.20" (4.351) and "0.10" (6.626) of the table.
03

Identify the Bounds of the P-Value

Since the given \(X^{2}\) statistic lies between the values in the columns labeled "0.20" and "0.10," we can conclude that the p-value is bounded between 0.1 and 0.2. Case b: \(X^{2}=20.62, d f=6\)
04

Locate the Appropriate Row in Appendix I Table 5

First, you need to find the row that corresponds to the degrees of freedom in the given problem. In this case, the degrees of freedom (df) are 6. Locate the row labeled "6" in the "df" column of Table 5 in Appendix I.
05

Find the Column(s) Where the Chi-Square Statistic Lies

Next, you need to identify the columns where the given \(X^{2}\) statistic (20.62) lies between. Look for the values in the row corresponding to the degrees of freedom that are closest to, but greater than and less than 20.62. In this case, you will find that the \(X^{2}\) statistic lies between the values in the columns labeled "0.01" (16.812) and "0.001" (22.457) of the table.
06

Identify the Bounds of the P-Value

Since the given \(X^{2}\) statistic lies between the values in the columns labeled "0.01" and "0.001," we can conclude that the p-value is bounded between 0.001 and 0.01.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the P-Value in a Chi-Square Test
In a chi-square test, the p-value is a crucial component. It indicates the probability of observing a test statistic as extreme as, or more extreme than, the value calculated from the sample data. This is under the assumption that the null hypothesis is true. A smaller p-value suggests that there is stronger evidence against the null hypothesis.

In practical terms, calculating the p-value involves looking at a chi-square distribution table and identifying the bounds between which the observed chi-square statistic falls:
  • Locate the degrees of freedom row that corresponds to your data.
  • Identify the chi-square column nearest to your calculated statistic.
  • The p-value will be between the corresponding probability values.
For example, if the statistic is less than the chi-square value for the 0.05 column and more than the 0.01 column, the p-value is between 0.01 and 0.05. Thus, understanding and interpreting p-values accurately can determine the direction and confidence of your hypothesis testing.
Degrees of Freedom in Statistics
The concept of degrees of freedom (df) is central in statistics, particularly when conducting a chi-square test. It describes the number of values in a calculation that are free to vary.

Degrees of freedom are important because they are used to determine the appropriate chi-square distribution to reference when evaluating a test statistic. In essence, it adjusts the distribution to better fit the data size and complexity you're working with.
  • Degrees of freedom in a chi-square test is calculated as the number of categories minus one.
  • They help to shape the distribution curve used in calculating p-values.
  • The more the degrees of freedom, the closer the chi-square distribution will resemble a normal distribution.
Understanding degrees of freedom helps to ensure that the analysis reflects the true variability present in the data.
Chi-Square Statistic Explained
The chi-square statistic is the test statistic used in a chi-square test of independence or goodness of fit. It quantifies the difference between observed and expected frequencies in categorical data.

A higher chi-square statistic suggests a greater degree of deviation from what was expected in the null hypothesis. To compute it:
  • Calculate the expected frequencies for each category, which are often based on the proportions expected if the null hypothesis were true.
  • Use the formula: \[ X^{2} = \sum \frac{(O_i - E_i)^2}{E_i} \] where \(O_i\) is the observed frequency and \(E_i\) is the expected frequency.
  • Compare this statistic to the critical value from a chi-square distribution table.
Proper interpretation of the chi-square statistic within the context of the degrees of freedom is essential to making informed decisions regarding the null hypothesis.

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Most popular questions from this chapter

Researchers from Germany have concluded that the risk of a heart attack for a working person may be as much as \(50 \%\) greater on Monday than on any other day. \({ }^{1}\) The researchers kept track of heart attacks and coronary arrests over a period of 5 years among 330,000 people who lived near Augsburg, Germany. In an attempt to verify their claim, you survey 200 working people who had recently had heart attacks and recorded the day on which their heart attacks occurred: Do the data present sufficient evidence to indicate that there is a difference in the incidence of heart attacks depending on the day of the week? Test using \(\alpha=.05 .\)

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Each model year seems to introduce new colors and different hues for a wide array of vehicles, from luxury cars, to full-size or intermediate models, to compacts and sports cars, to light trucks. However, white and silver/gray continue to make the top five or six colors across all of these categories of vehicles. The top six colors and their percentage of the market share for compact/sports cars are shown in the following table. To verify the figures, a random sample consisting of 250 compact/sports cars was taken and the color of the vehicles recorded. The sample provided the following counts for the categories given above: \(52,43,48,41,\) \(32,19,\) respectively. a. Is any category missing in the classification? How many vehicles belong to that category? b. Is there sufficient evidence to indicate that our percentages of the colors for compact/sports cars differ from those given? Find the approximate \(p\) -value for the test.

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Previous enrollment records at a large university indicate that of the total number of persons who apply for admission, \(60 \%\) are admitted unconditionally, \(5 \%\) are admitted on a trial basis, and the remainder are refused admission. Of 500 applications to date for the coming year, 329 applicants have been admitted unconditionally, 43 have been admitted on a trial basis, and the remainder have been refused admission. Do these data indicate a departure from previous admission rates? Test using \(\alpha=.05 .\)

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