Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Find the critical value(s) of \(t\) that specify the rejection region in these situations: a. A two-tailed test with \(\alpha=.01\) and \(12 d f\) b. A right-tailed test with \(\alpha=.05\) and \(16 d f\) c. A two-tailed test with \(\alpha=.05\) and \(25 d f\) d. A left-tailed test with \(\alpha=.01\) and \(7 d f\)

Short Answer

Expert verified
#Short Answer# a. The critical values for a two-tailed test with α = 0.01 and 12 d.f. are approximately ±3.106. b. The critical value for a right-tailed test with α = 0.05 and 16 d.f. is approximately 1.746. c. The critical values for a two-tailed test with α = 0.05 and 25 d.f. are approximately ±2.060. d. The critical value for a left-tailed test with α = 0.01 and 7 d.f. is approximately -2.998.

Step by step solution

01

Test Type

This is a two-tailed test. We will use α/2 = 0.005 to find the critical values on each tail. ##Step 2: Identify the degrees of freedom##
02

Degrees of Freedom

In this case, degrees of freedom (d.f.) = 12. ##Step 3: Find the critical value##
03

Critical Value

Using a t-distribution table or calculator, we find the critical values for α/2 = 0.005 and 12 d.f. The critical values are approximately ±3.106. ##Step 4: Conclusion##
04

Conclusion

The critical values for a two-tailed test with α = 0.01 and 12 d.f. are approximately ±3.106. #b. A right-tailed test with α = .05 and 16 df# ##Step 1: Determine the test type##
05

Test Type

This is a right-tailed test. We will use α = 0.05. ##Step 2: Identify the degrees of freedom##
06

Degrees of Freedom

In this case, degrees of freedom (d.f.) = 16. ##Step 3: Find the critical value##
07

Critical Value

Using a t-distribution table or calculator, we find the critical value for α = 0.05 and 16 d.f. The critical value is approximately 1.746. ##Step 4: Conclusion##
08

Conclusion

The critical value for a right-tailed test with α = 0.05 and 16 d.f. is approximately 1.746. #c. A two-tailed test with α = .05 and 25 df# ##Step 1: Determine the test type and α/2##
09

Test Type

This is a two-tailed test. We will use α/2 = 0.025. ##Step 2: Identify the degrees of freedom##
10

Degrees of Freedom

In this case, degrees of freedom (d.f.) = 25. ##Step 3: Find the critical value##
11

Critical Value

Using a t-distribution table or calculator, we find the critical values for α/2 = 0.025 and 25 d.f. The critical values are approximately ±2.060. ##Step 4: Conclusion##
12

Conclusion

The critical values for a two-tailed test with α = 0.05 and 25 d.f. are approximately ±2.060. #d. A left-tailed test with α = .01 and 7 df# ##Step 1: Determine the test type##
13

Test Type

This is a left-tailed test. We will use α = 0.01. ##Step 2: Identify the degrees of freedom##
14

Degrees of Freedom

In this case, degrees of freedom (d.f.) = 7. ##Step 3: Find the critical value##
15

Critical Value

Using a t-distribution table or calculator, we find the critical value for α = 0.01 and 7 d.f. The critical value is approximately -2.998. ##Step 4: Conclusion##
16

Conclusion

The critical value for a left-tailed test with α = 0.01 and 7 d.f. is approximately -2.998.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Value
The critical value in a t-distribution is an essential component in statistical hypothesis testing. It helps to determine whether the null hypothesis should be rejected. The critical value marks the boundaries of the rejection region, which is the area in the tails of the distribution that lies beyond a certain chance of error, known as the level of significance (\( \alpha \)).
  • For a two-tailed test, you need to divide the level of significance by two since the rejection area is split between both tails of the distribution.
  • For one-tailed tests, the entire significance level is in one tail.
  • Finding a critical value requires using a t-distribution table, or a calculator, based on degrees of freedom and the chosen significance level.
These critical values help decide whether the test statistic falls within the critical region, leading to the rejection of the null hypothesis.
Degrees of Freedom
Degrees of freedom (\( \text{d.f.} \)) are a crucial aspect of t-distributions and greatly impact the shape of the distribution. It essentially refers to the number of independent observations in a sample minus the number of parameters estimated. The calculation of degrees of freedom in most t-tests is straightforward:
  • For a single sample, the degrees of freedom are equal to the sample size minus one (\( n - 1 \)).
  • More complex designs, such as paired samples or multiple groups, may involve more intricate calculations.
Degrees of freedom affect the spread and the tail areas of the t-distribution. Lower degrees of freedom result in fatter tails, indicating more variability. As the degrees of freedom increase, the t-distribution approaches a normal distribution.
Two-Tailed Test
A two-tailed test is a statistical test where the area of rejection is on both ends of the sampling distribution. This type of test is used when we are interested in determining whether there is a difference regardless of direction.
  • In hypothesis testing, it looks for deviations in either direction from the hypothesized parameter.
  • For example, if testing whether a sample mean is different from a known population mean, you would check for values significantly higher or lower.
The significance level for a two-tailed test is divided between the two tails. So if \( \alpha = 0.05 \), then each tail would have a 0.025 level of significance. This approach is more conservative, as it requires stronger evidence to reject the null hypothesis since it checks both directions.
Right-Tailed Test
In a right-tailed test, the rejection region is in the right tail of the distribution. This type of test is specifically used when predicting an increase or greater values in the parameter of interest.
  • For example, if testing whether a new drug increases response times, a right-tailed test could be appropriate.
  • The critical value separates the non-rejection area from the rejection region in the right tail.
The entire chosen significance level (\( \alpha \)) is in the right side tail. Thus, for \( \alpha = 0.05 \), 5% of the distribution area falls under the rejection region. Right-tailed tests are pivotal in hypotheses where you only care about deviations in one direction, specifically to the right.
Left-Tailed Test
A left-tailed test, meanwhile, sets its sights on the left end of the distribution. It's most applicable when a decrease or lesser value in the parameter in question is the point of interest.
  • For example, if assessing whether a new teaching technique lowers anxiety levels, a left-tailed test could be used.
  • The critical value defines the boundary beyond which the null hypothesis will be rejected.
Here, the entire significance level (\( \alpha \)) resides in the left tail. For instance, with a significance level of 0.01, 1% of the area on the left tail makes up the rejection region. The left-tailed test is perfect for scenarios where changes suspected are directionally specific to the left.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The EPA limit on the allowable discharge of suspended solids into rivers and streams is 60 milligrams per liter ( \(\mathrm{mg} /\) l) per day. A study of water samples selected from the discharge at a phosphate mine shows that over a long period, the mean daily discharge of suspended solids is \(48 \mathrm{mg} /\), but day-to-day discharge readings are variable. State inspectors measured the discharge rates of suspended solids for \(n=20\) days and found \(s^{2}=39(\mathrm{mg} / \mathrm{I})^{2}\). Find a \(90 \%\) confidence interval for \(\sigma^{2}\). Interpret your results.

An experimenter was interested in determining the mean thickness of the cortex of the sea urchin egg. The thickness was measured for \(n=10\) sea urchin eggs. These measurements were obtained: $$ \begin{array}{lllll} 4.5 & 6.1 & 3.2 & 3.9 & 4.7 \\ 5.2 & 2.6 & 3.7 & 4.6 & 4.1 \end{array} $$ Estimate the mean thickness of the cortex using a \(95 \%\) confidence interval.

Jan Lindhe conducted a study on the effect of an oral antiplaque rinse on plaque buildup on teeth. \(^{6}\) Fourteen people whose teeth were thoroughly cleaned and polished were randomly assigned to two groups of seven subjects each. Both groups were assigned to use oral rinses (no brushing) for a 2 -week period. Group 1 used a rinse that contained an antiplaque agent. Group \(2,\) the control group, received a similar rinse except that, unknown to the subjects, the rinse contained no antiplaque agent. A plaque index \(x\), a measure of plaque buildup, was recorded at 14 days with means and standard deviations for the two groups shown in the table. $$ \begin{array}{lll} & \text { Control Group } & \text { Antiplaque Group } \\ \hline \text { Sample Size } & 7 & 7 \\ \text { Mean } & 1.26 & .78 \\ \text { Standard Deviation } & 32 & 32 \end{array} $$ a. State the null and alternative hypotheses that should be used to test the effectiveness of the antiplaque oral rinse b. Do the data provide sufficient evidence to indicate that the oral antiplaque rinse is effective? Test using \(\alpha=.05 .\) c. Find the approximate \(p\) -value for the test.

The earth's temperature can be measured using either ground-based sensors or infrared-sensing devices mounted in aircraft or space satellites. Ground-based sensoring is very accurate but tedious, while infrared-sensoring appears to introduce a bias into the temperature readings- that is, the average temperature reading may not be equal to the average obtained by ground-based sensoring. To determine the bias, readings were obtained at five different locations using both ground- and air-based temperature sensors. The readings (in degrees Celsius) are listed here: $$ \begin{array}{ccc} \text { Location } & \text { Ground } & \text { Air } \\ \hline 1 & 46.9 & 47.3 \\ 2 & 45.4 & 48.1 \\ 3 & 36.3 & 37.9 \\ 4 & 31.0 & 32.7 \\ 5 & 24.7 & 26.2 \end{array} $$ a. Do the data present sufficient evidence to indicate a bias in the air-based temperature readings? Explain. b. Estimate the difference in mean temperatures between ground- and air-based sensors using a \(95 \%\) confidence interval. c. How many paired observations are required to estimate the difference between mean temperatures for ground- versus air-based sensors correct to within \(.2^{\circ} \mathrm{C}\), with probability approximately equal to \(.95 ?\)

A manufacturer of hard safety hats for construction workers is concerned about the mean and the variation of the forces helmets transmit to wearers when subjected to a standard external force. The manufacturer desires the mean force transmitted by helmets to be 800 pounds (or less), well under the legal 1000 -pound limit, and \(\sigma\) to be less than \(40 .\) A random sample of \(n=40\) helmets was tested, and the sample mean and variance were found to be equal to 825 pounds and 2350 pounds \(^{2}\), respectively. a. If \(\mu=800\) and \(\sigma=40,\) is it likely that any helmet, subjected to the standard external force, will transmit a force to a wearer in excess of 1000 pounds? Explain. b. Do the data provide sufficient evidence to indicate that when the helmets are subjected to the standard external force, the mean force transmitted by the helmets exceeds 800 pounds?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free