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Do you own an iPod Nano or a Sony Walkman Bean? These and other brands of MP3 players are becoming more and more popular among younger Americans. An iPod survey reported that \(54 \%\) of 12 - to 17 -year-olds, \(30 \%\) of 18 - to 34 -year-olds, and \(13 \%\) of 35 - to 54 -year-olds own MP3 players. \({ }^{6}\) Suppose that these three estimates are based on random samples of size \(400,350,\) and \(362,\) respectively. a. Construct a \(95 \%\) confidence interval estimate for the proportion of 12 - to 17 -year-olds who own an MP3 player. b. Construct a \(95 \%\) confidence interval estimate for the proportion of 18 - to 34 -year-olds who own an MP3 player.

Short Answer

Expert verified
Question: Determine the 95% confidence intervals for the proportion of 12-to-17-year-olds and 18-to-34-year-olds who own an MP3 player. Answer: The 95% confidence interval estimate for the proportion of 12-to-17-year-olds who own an MP3 player is (0.48994, 0.59006), and the 95% confidence interval estimate for the proportion of 18-to-34-year-olds who own an MP3 player is (0.25153, 0.34847).

Step by step solution

01

Calculate the sample proportions for each age group

Given the survey results, we can calculate the sample proportions of MP3 player ownership for each age group: 12-to-17-year-olds: \(\hat{p}_1 = 0.54\) 18-to-34-year-olds: \(\hat{p}_2 = 0.30\)
02

Determine the critical value corresponding to 95% confidence

For a 95% confidence interval, the critical value \(Z_{\frac{\alpha}{2}}\) can be found in a Z-table or using a calculator. The critical value is: \(Z_{\frac{\alpha}{2}} = 1.96\)
03

Calculate the confidence interval for 12-to-17-year-olds

Using the formula for the confidence interval, we can calculate the 95% confidence interval for the proportion of 12-to-17-year-olds who own an MP3 player: \(CI_1 = \hat{p}_1 \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}}\) \(CI_1 = 0.54 \pm 1.96 \times \sqrt{\frac{0.54(1-0.54)}{400}}\) \(CI_1 = 0.54 \pm 1.96 \times \sqrt{0.0006475}\) \(CI_1 = 0.54 \pm 0.05006\) Therefore, the 95% confidence interval estimate for the proportion of 12-to-17-year-olds who own an MP3 player is (0.48994, 0.59006).
04

Calculate the confidence interval for 18-to-34-year-olds

Now, we can calculate the 95% confidence interval for the proportion of 18-to-34-year-olds who own an MP3 player: \(CI_2 = \hat{p}_2 \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\) \(CI_2 = 0.30 \pm 1.96 \times \sqrt{\frac{0.30(1-0.30)}{350}}\) \(CI_2 = 0.30 \pm 1.96 \times \sqrt{0.00061286}\) \(CI_2 = 0.30 \pm 0.04847\) Therefore, the 95% confidence interval estimate for the proportion of 18-to-34-year-olds who own an MP3 player is (0.25153, 0.34847).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
In statistics, the sample proportion is the percentage of individuals in a sample that have a particular characteristic. For example, in a survey, it measures the fraction of people who own an MP3 player in different age groups. Calculating sample proportion, denoted as \( \hat{p} \), is straightforward. You divide the number of favorable responses by the total number of sample responses.
  • For the 12-to-17-year-olds, if 54 out of 100 surveyed own an MP3 player, the sample proportion \( \hat{p}_1 \) is 0.54.
  • For the 18-to-34-year-olds, with a proportion of 30%, \( \hat{p}_2 \) is 0.30.
Sample proportions help gauge the prevalence of characteristics in a population. They provide a groundwork for estimating and creating confidence intervals. With a bigger sample size, the sample proportion's estimate is more likely to reflect the true proportion in the whole population.
Critical Value
The critical value is an important factor in hypothesis testing and constructing confidence intervals. It represents the cutoff point that determines the extent of uncertainty in a sample statistic based on a desired level of confidence. This value is derived from the Z-distribution or standard normal distribution when dealing with proportions.
For a 95% confidence interval, which is common for social sciences, the critical value \( Z_{\frac{\alpha}{2}} \) is 1.96.
  • This means that if you want to be 95% certain your confidence interval contains the true population proportion, you include 1.96 standard deviations (to the left and right) of your sample proportion.
The critical value comes into play when calculating the margin of error in a confidence interval: the larger the critical value, the wider the interval, reflecting the inherent uncertainty.
Z-score
A Z-score measures exactly how many standard deviations a data point is from the mean. In calculating the confidence interval for a sample proportion, the Z-score is used to assess the probability that a sample mean will fall within a certain range of the population mean.
The Z-score is crucial when it comes to proportions, as the sample mean of the proportion under the null hypothesis is normally distributed, allowing use of the normal Z-distribution.
  • This standardization helps in determining the position of data points in relation to the overall distribution.
Using the Z-score helps in creating confidence intervals by specifying the range of proportion values that are statistically not different from the population proportion.
MP3 Player Ownership Statistics
Understanding MP3 player ownership statistics shines a light on consumer habits across various demographics. It helps us gauge the penetration and popularity of such technology over different age groups. Take iPods or Sony Walkman Beans, for example. Ownership statistics reveal how mainstream these gadgets have become.
  • Among 12-to-17-year-olds, 54% own an MP3 player, indicating strong popularity in this group.
  • The 18-to-34-year-olds have a 30% ownership rate, showing steady, though less intense, engagement.
  • Only 13% of 35-to-54-year-olds own one, illustrating slower adoption in older age groups.
By analyzing these statistics, marketers and manufacturers can target age-specific needs, support product development strategies, and predict market trends. Combining this data with confidence intervals allows a more precise understanding of the needs and size of these market segments.

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Most popular questions from this chapter

Born between 1980 and \(1990,\) Generation Next have lived in a post-Cold War world and a time of relative economic prosperity in America, but they have also experienced September 11 th and the fear of another attack, two Gulf Wars, the tragedy at Columbine High School, Hurricane Katrina, and the increasing polarization of public discourse. More than any who came before, Generation Next is engaged with technology, and the vast majority is dependent upon it. \({ }^{15}\) Suppose that a survey of 500 female and 500 male students in Generation Next, 345 of the females and 365 of the males reported that they decided to attend college in order to make more money. a. Construct a \(98 \%\) confidence interval for the difference in the proportions of female and male students who decided to attend college in order to make more money. b. What does it mean to say that you are "98\% confident"? c. Based on the confidence interval in part a, can you conclude that there is a difference in the proportions of female and male students who decided to attend college in order to make more money?

In a study to compare the effects of two pain relievers it was found that of \(n_{1}=200\) randomly selectd individuals instructed to use the first pain reliever, \(93 \%\) indicated that it relieved their pain. Of \(n_{2}=450\) randomly selected individuals instructed to use the second pain reliever, \(96 \%\) indicated that it relieved their pain. a. Find a \(99 \%\) confidence interval for the difference in the proportions experiencing relief from pain for these two pain relievers. b. Based on the confidence interval in part a, is there sufficient evidence to indicate a difference in the proportions experiencing relief for the two pain relievers? Explain.

Refer to the Interpreting Confidence Intervals applet. a. Suppose that you have a random sample of size \(n=50\) from a population with unknown mean \(\mu\) and known standard deviation \(\sigma=35 .\) Calculate the half width of a \(95 \%\) confidence interval for \(\mu\). What would the width of this interval be? b. Use the button to create a single confidence interval for \(\mu\). What is the width of this interval? Compare your results to the calculation you did in part a.

In an article in the Annals of Botany, a researcher reported the basal stem diameters of two groups of dicot sunflowers: those that were left to sway freely in the wind and those that were artificially supported. \({ }^{18}\) A similar experiment was conducted for monocot maize plants. Although the authors measured other variables in a more complicated experimental design, assume that each group consisted of 64 plants (a total of 128 sunflower and 128 maize plants). The values shown in the table are the sample means plus or minus the standard error. $$\begin{array}{l|c|c} & \text { Sunflower } & \text { Maize } \\\\\hline \text { Free-Standing } & 35.3 \pm .72 & 16.2 \pm .41 \\\\\text {Supported } & 32.1 \pm .72 & 14.6 \pm .40\end{array}$$ Use your knowledge of statistical estimation to compare the free-standing and supported basal diameters for the two plants. Write a paragraph describing your conclusions, making sure to include a measure of the accuracy of your inference.

A researcher classified his subjects as innately right-handed or lefthanded by comparing thumbnail widths. He took a sample of 400 men and found that 80 men could be classified as left-handed according to his criterion. Estimate the proportion of all males in the population who would test to be left-handed using a \(95 \%\) confidence interval.

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