Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A researcher classified his subjects as innately right-handed or lefthanded by comparing thumbnail widths. He took a sample of 400 men and found that 80 men could be classified as left-handed according to his criterion. Estimate the proportion of all males in the population who would test to be left-handed using a \(95 \%\) confidence interval.

Short Answer

Expert verified
Question: Estimate the proportion of all males in the population who would test to be left-handed using a 95% confidence interval based on the given sample data: 80 out of 400 males are left-handed. Answer: Based on the researcher's criterion for classifying left-handed males, we can estimate with 95% confidence that the proportion of left-handed males in the population lies between 16.08% and 23.92%.

Step by step solution

01

Calculate the sample proportion of left-handed males

To calculate the sample proportion, we need to divide the number of left-handed males by the total number of males in the sample: Sample proportion, p = (Number of left-handed males) / (Total number of males) p = 80 / 400 = 0.2
02

Calculate the standard error of the proportion

To calculate the standard error of the proportion, we will use the following formula: Standard error(SE) = \(\sqrt{\frac{p \times (1-p)}{n}}\) Where, \(p\) = Sample proportion \(n\) = Total number of males in the sample SE = \(\sqrt{\frac{0.2 \times (1-0.2)}{400}} = \sqrt{\frac{0.16}{400}} = 0.02\)
03

Determine the z-score for a 95% confidence interval

A 95% confidence interval corresponds to z-scores of \(\pm 1.96\). This is because about 95% of the area under the standard normal distribution lies within \(\pm 1.96\) standard deviations of the mean.
04

Calculate the confidence interval

To calculate the 95% confidence interval, we will use the following formula: Confidence interval = Sample proportion \(\pm\) (z-score x Standard error) 95% Confidence interval = 0.2 \(\pm\) (1.96 x 0.02) Lower bound = 0.2 - (1.96 x 0.02) = 0.1608 Upper bound = 0.2 + (1.96 x 0.02) = 0.2392
05

Interpret the results

Based on the researcher's criterion for classifying left-handed males, we can estimate with 95% confidence that the proportion of left-handed males in the population lies between 16.08% and 23.92%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One of the major costs involved in planning a summer vacation is the cost of lodging. Even within a particular chain of hotels, costs can vary substantially depending on the type of room and the amenities offered. \(^{4}\) Suppose that we randomly select 50 billing statements from each of the computer databases of the Marriott, Radisson, and Wyndham hotel chains, and record the nightly room rates. $$\begin{array}{lccc} & \text { Marriott } & \text { Radisson } & \text { Wyndham } \\\\\hline \text { Sample average } & \$ 170 & \$ 145 & \$ 150 \\\\\text { Sample standard deviation } & 17.5 & 10 & 16.5\end{array}$$ a. Describe the sampled population(s). b. Find a point estimate for the average room rate for the Marriott hotel chain. Calculate the margin of error. c. Find a point estimate for the average room rate for the Radisson hotel chain. Calculate the margin of error. d. Find a point estimate for the average room rate for the Wyndham hotel chain. Calculate the margin of error. e. Display the results of parts \(\mathrm{b}, \mathrm{c},\) and d graphically, using the form shown in Figure \(8.5 .\) Use this display to compare the average room rates for the three hotel chains.

Find and interpret a \(95 \%\) confidence interval for a population mean \(\mu\) for these values: a. \(n=36, \bar{x}=13.1, s^{2}=3.42\) b. \(n=64, \bar{x}=2.73, s^{2}=.1047\)

Calculate the margin of error in estimating a binomial proportion for each of the following values of \(n\). Use \(p=.5\) to calculate the standard error of the estimator. a. \(n=30\) b. \(n=100\) c. \(n=400\) d. \(n=1000\)

Calculate the margin of error in estimating a binomial proportion \(p\) using samples of size \(n=100\) and the following values for \(p\) : a. \(p=.1\) b. \(p=.3\) c. \(p=.5\) d. \(p=.7\) e. \(p=.9\) f. Which of the values of \(p\) produces the largest margin of error?

Find a \(99 \%\) lower confidence bound for the binomial proportion \(p\) when a random sample of \(n=400\) trials produced \(x=196\) successes.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free