Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Human heights are one of many biological random variables that can be modeled by the normal distribution. Assume the heights of men have a mean of 69 inches with a standard deviation of 3.5 inches. a. What proportion of all men will be taller than \(6^{\prime} 0^{\prime \prime}\) ? (HINT: Convert the measurements to inches.) b. What is the probability that a randomly selected man will be between \(5^{\prime} 8^{\prime \prime}\) and \(6^{\prime} 1^{\prime \prime}\) tall? c. President George \(\mathrm{W}\). Bush is \(5^{\prime} 11^{\prime \prime}\) tall. Is this an unusual height? d. Of the 42 presidents elected from 1789 through 2006,18 were \(6^{\prime} 0^{\prime \prime}\) or taller. \(^{1}\) Would you consider this to be unusual, given the proportion found in part a?

Short Answer

Expert verified
2. What is the probability of a randomly selected man being between 5 feet 8 inches (68 inches) and 6 feet 1 inch (73 inches) tall? 3. Is George W. Bush's height of 5 feet 11 inches (71 inches) unusual? 4. Is the number of presidents 6 feet or taller unusual based on the proportion found in part 1?

Step by step solution

01

Calculate z-scores for the given heights

First, we need to calculate the z-scores for the heights mentioned in the questions (72 inches, 68 inches, and 73 inches). The formula for the z-score is: \(z = \frac{x - \mu}{\sigma}\), where x is the individual value, \(\mu\) is the mean, and \(\sigma\) is the standard deviation. 1. Z-score for 72 inches: \(z_{72} = \frac{72 - 69}{3.5}\) 2. Z-score for 68 inches: \(z_{68} = \frac{68 - 69}{3.5}\) 3. Z-score for 73 inches: \(z_{73} = \frac{73 - 69}{3.5}\) Now we can calculate these values: 1. \(z_{72} = \frac{3}{3.5} = 0.857\) 2. \(z_{68} = \frac{-1}{3.5} = -0.286\) 3. \(z_{73} = \frac{4}{3.5} = 1.143\)
02

Calculate the proportions using the z-scores

Next, we'll use z-scores to calculate the proportions asked in the exercise. a. First, we need to find the proportion of men taller than 72 inches (z-score \(0.857\)). We will look up the value for \(0.857\) in the z-table (standard normal table) and subtract this value from 1. The resulting proportion is the desired answer. \(Proportion = 1 - P(Z \leq 0.857) \approx 1 - 0.8049 = 0.1951\) b. To find the probability of a randomly selected man being between 68 inches and 73 inches tall, we'll use the z-scores \(-0.286\) and \(1.143\). We'll subtract the value of \(P(Z \leq -0.286)\) from \(P(Z \leq 1.143)\). \(Probability = P( -0.286 \leq Z \leq 1.143) \approx 0.8672 - 0.3873 = 0.4799\)
03

Determine if George W. Bush's height is unusual

George W. Bush's height is 71 inches, so we can calculate the z-score for this height using the formula mentioned earlier: \(z_{71} = \frac{71 - 69}{3.5} = \frac{2}{3.5} = 0.571\) Now, we can check the value of \(P(Z \leq 0.571)\) in the z-table. \(P(Z \leq 0.571) \approx 0.7163\) Since this value is not in the tails of the distribution (let's say, outside of the 5% on either side), it can be considered not unusual.
04

Analyze whether the number of presidents 6 feet or taller is unusual

We found in Step 2a that the proportion of men taller than 6 feet is 0.1951. Now let's find the expected number of presidents, out of 42, who would be 6 feet or taller based on this proportion. \(Expected\_Number = 0.1951 * 42 \approx 8.2\) There were actually 18 presidents 6 feet or taller, while the expected number is 8.2. This difference seems substantial, so it could be considered unusual.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score
Understanding the z-score is essential for interpreting data on a standard normal distribution. It is a statistical measure that describes a value's relationship to the mean of a group of values. Put simply, a z-score tells you how many standard deviations an element is from the mean.

When you calculate the z-score of an individual measurement, you're comprehending its position relative to the average. In the context of human heights, if the average height of men is 69 inches, a z-score will indicate how tall or short someone is compared to the average man.

For instance, a positive z-score implies that the measurement is above the mean, while a negative z-score means it's below the mean. A z-score of 0 signifies that the measurement is exactly at the mean. Understanding this concept allows for better interpretation of where a particular measurement stands in a normally distributed population.
Probability
In statistics, probability is a measure of the likelihood of an event occurring. It ranges from 0 to 1, where 0 indicates impossibility, and 1 indicates certainty. In the problem, figuring out the probability that a randomly selected man falls within a certain height range requires knowledge of the normal distribution and the ability to use z-scores.

Probabilities in a normal distribution can be found with z-tables, which showcase the percentage of data within certain z-score values. For example, if we wanted to determine how likely it is to find a man between 68 and 73 inches tall, we would look at the cumulative probability associated with the z-scores of those heights and calculate the difference. This application of probability in normal distribution is crucial for making predictions and understanding data variability.
Statistical Significance
The concept of statistical significance is a cornerstone for determining whether a result from a data set is likely due to a specific factor or merely by chance. In statistical terms, a result is considered statistically significant if the likelihood of the result occurring by chance is low, often below an arbitrary threshold of 5% (the p-value).

For example, assessing whether the number of tall presidents is statistically significant involves comparing the expected proportion based on general height distributions to the observed proportion in presidents. If a significant difference exists, like the unexpectedly high number of tall presidents, we might infer that height plays a role in presidential elections or that stature was regarded differently in certain historical periods. However, statistical significance doesn't always equate to practical significance, something to keep in mind when interpreting these results.
Standard Deviation
The standard deviation is a measure of variation or dispersion within a set of values. In a normal distribution, it quantifies how spread out numbers are from the mean value. A high standard deviation indicates a wide range of values, while a low standard deviation signifies that the values tend to be closer to the mean.

In the context of human heights, the standard deviation dictates the typical amount of height variation we can expect from the average. The problem presented involves a standard deviation of 3.5 inches for men's heights, which guides us in understanding the range within which most men's heights fall. Through the lens of a normal distribution, approximately 68% of data falls within one standard deviation of the mean, providing a clear and useful picture of variability within the population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A used-car dealership has found that the length of time before a major repair is required on the cars it sells is normally distributed with a mean equal to 10 months and a standard deviation of 3 months. If the dealer wants only \(5 \%\) of the cars to fail before the end of the guarantee period, for how many months should the cars be guaranteed?

The number of times \(x\) an adult human breathes per minute when at rest depends on the age of the human and varies greatly from person to person. Suppose the probability distribution for \(x\) is approximately normal, with the mean equal to 16 and the standard deviation equal to \(4 .\) If a person is selected at random and the number \(x\) of breaths per minute while at rest is recorded, what is the probability that \(x\) will exceed \(22 ?\)

For a car traveling 30 miles per hour (mph), the distance required to brake to a stop is normally distributed with a mean of 50 feet and a standard deviation of 8 feet. Suppose you are traveling \(30 \mathrm{mph}\) in a residential area and a car moves abruptly into your path at a distance of 60 feet. a. If you apply your brakes, what is the probability that you will brake to a stop within 40 feet or less? Within 50 feet or less? b. If the only way to avoid a collision is to brake to a stop, what is the probability that you will avoid the collision?

Suppose that you must establish regulations concerning the maximum number of people who can occupy an elevator. A study of elevator occupancies indicates that if eight people occupy the elevator, the probability distribution of the total weight of the eight people has a mean equal to 1200 pounds and a standard deviation of 99 pounds. What is the probability that the total weight of eight people exceeds 1300 pounds? 1500 pounds? (Assume that the probability distribution is approximately normal.)

Two of the biggest soft drink rivals, Pepsi and Coke, are very concerned about their market shares. The pie chart that follows claims that PepsiCo's share of the beverage market is \(25 \% .^{6}\) Assume that this proportion will be close to the probability that a person selected at random indicates a preference for a Pepsi product when choosing a soft drink. A group of \(n=500\) consumers is selected and the number preferring a Pepsi product is recorded. Use the normal curve to approximate the following binomial probabilities. a. Exactly 150 consumers prefer a Pepsi product. b. Between 120 and 150 consumers (inclusive) prefer a Pepsi product. c. Fewer than 150 consumers prefer a Pepsi product. d. Would it be unusual to find that 232 of the 500 consumers preferred a Pepsi product? If this were to occur, what conclusions would you draw?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free