Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The number of passes completed by Brett Favre, quarterback for the Green Bay Packers, was recorded for each of the 16 regular season games in the fall of 2006 (www.espn.com). \(^{9}\) $$ \begin{array}{rrrrrr} 15 & 31 & 25 & 22 & 22 & 19 \\ 17 & 28 & 24 & 5 & 22 & 24 \\ 22 & 20 & 26 & 21 & & \end{array} $$ a. Draw a stem and leaf plot to describe the data. b. Calculate the mean and standard deviation for Brett Favre's per game pass completions. c. What proportion of the measurements lie within two standard deviations of the mean?

Short Answer

Expert verified
Answer: The proportion of measurements within two standard deviations of the mean is approximately 0.9375 or 93.75%.

Step by step solution

01

Organize the data

First, let's organize the data from the lowest to the highest value: 5, 15, 17, 19, 20, 21, 22, 22, 22, 22, 24, 24, 25, 26, 28, 31
02

Draw a stem and leaf plot

Now, create a stem and leaf plot from the organized data: Stem | Leaf 0 | 5 1 | 579 2 | 0112223445568 3 | 1
03

Calculate the mean

To find the mean of Brett Favre's completed passes per game, sum the values and divide by the total number of games (16). Mean = (5+15+17+19+20+21+22+22+22+22+24+24+25+26+28+31)/16 = 343/16 Mean = 21.44 completed passes per game
04

Calculate the standard deviation

To calculate standard deviation, follow these steps: 1. Find the mean (already calculated): 21.44 2. Subtract the mean from each value and square the result 3. Calculate the average of squared differences (variance) 4. Take the square root of the variance Variance = [(5-21.44)^2 + (15-21.44)^2 + ... + (31-21.44)^2]/16 Variance ≈ 47.90 Standard Deviation = √47.90 ≈ 6.92 passes
05

Determine the proportion of measurements within two standard deviations

By calculating mean ± 2 standard deviations, we will find the range: Lower Range = Mean - 2*(Standard Deviation) = 21.44 - 2*6.92 ≈ 7.60 Upper Range = Mean + 2*(Standard Deviation) = 21.44 + 2*6.92 ≈ 35.28 Now, we count the total number of measurements within this range: There are 15 out of 16 measurements within two standard deviations of the mean. The proportion of measurements within two standard deviations of the mean is: Proportion = 15/16 ≈ 0.9375 or 93.75%

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stem and Leaf Plot
A stem and leaf plot is a visual method of displaying quantitative data that helps in understanding the distribution and frequency of a data set. It resembles a histogram turned sideways; with stems on one side representing the leading digit(s) and leaves on the other side representing the trailing digit(s). Imagine this like a more detailed bar chart where each bar is split into individual numbers. To create a stem and leaf plot from a dataset, follow these steps:

  • Separate each value into a stem (the number's leading digit(s)) and a leaf (the number's trailing digit).
  • List the stems in ascending order on the left and attach the corresponding leaves for each stem, also in ascending order.
  • It's often helpful to indicate the number of instances a leaf occurs if the data repeats.

For the dataset given in the exercise, with each game's number of passes organized in ascending order, they formed stems from 0 through 3 with the leaves representing the last digits of the number of passes. Stem '2' for example, had several leaves showing how often the twenties range of passes occurred.
Mean Calculation
The mean, often referred to as the average, is a measure of central tendency in a data set that represents the typical value. Calculating the mean involves summing all the values and then dividing by the number of values. The formula for the mean (\bar{x}) is expressed as:

\[\begin{equation}\bar{x} = \dfrac{\sum{x_i}}{n}\end{equation}\]

where represents each value in the dataset and is the total number of values. Applying this to Brett Favre's completed passes, we first summed the number of passes per game and divided by the total number of games, which is 16. This calculation provided the average number of completed passes per game for that season.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values are close to the mean of the data set, while a high standard deviation indicates a wide range of values. To calculate the standard deviation:\

  • Compute the mean (average) of the data set.
  • Subtract the mean from each data point and square the result (the squared difference).
  • Find the average of these squared differences (this is the variance).
  • Take the square root of the variance to get the standard deviation.

The formula for standard deviation (\sigma) is:\[\begin{equation}\sigma = \sqrt{\dfrac{\sum{(x_i - \bar{x})^2}}{n}}\end{equation}\]
For Brett Favre's data, after finding the mean, each game's passes were subtracted from this mean, squared, and then the average of these squares was taken to find the variance. The square root of this variance gave us the standard deviation, showing us the spread of the number of passes around the average.
Variance
Variance is a statistical measurement of the spread between numbers in a data set. More precisely, it measures how far each number in the set is from the mean and thus from every other number in the set. The formula to calculate variance (\sigma^2) is similar to that of the standard deviation, but without taking the square root at the end. Variance is calculated as follows:\

\[\begin{equation}\sigma^2 = \dfrac{\sum{(x_i - \bar{x})^2}}{n}\end{equation}\]
The variance provides a squared value which can be difficult to apply directly to the initial data as they are not in the same units. That's why the square root is taken to return to the original unit of measurement, transforming variance back into standard deviation. Brett Favre's pass completions had a variance of approximately 47.90, indicating the degree to which individual games deviated from the mean performance.
Probability and Statistics
Probability and statistics deal with the study of randomness and uncertainty. These mathematical fields provide tools for analyzing, interpreting, and making predictions based on data. Probability is about modeling and measuring uncertainty: it uses models and theories to determine the likelihood of certain events occurring. Statistics, on the other hand, pertains to the collection, analysis, interpretation, and presentation of masses of numerical data. It involves using probability to make inferences about a population from a sample.

In the context of the exercise, probability theory is employed to ascertain the likelihood of Brett Favre's game performances falling within a certain range of values. Specifically, when we say 93.75% of the games fall within two standard deviations of the mean, we're using statistical knowledge to draw conclusions about his consistency over the season. These kinds of insights help coaches, players, and fans understand performance levels and can inform future strategies and expectations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An article in Consumer EX0208 Reports gives the price-an estimated average for a 6-ounce can or a 7.06 -ounce pouch \(-\) for 14 different brands of water- packed light tuna, based on prices paid nationally in supermarkets: $$ \begin{array}{rrrrrrr} .99 & 1.92 & 1.23 & .85 & .65 & .53 & 1.41 \\ 1.12 & .63 & .67 & .69 & .60 & .60 & .66 \end{array} $$ a. Find the average price for the 14 different brands of tuna. b. Find the median price for the 14 different brands of tuna. c. Based on your findings in parts a and b, do you think that the distribution of prices is skewed? Explain.

The DVD player is a common fixture in most American households. In fact, most American households have DVDs, and many have more than one. A sample of 25 households produced the following measurements on \(x\), the number of DVDs in the household: $$ \begin{array}{lllll} 1 & 0 & 2 & 1 & 1 \\ 1 & 0 & 2 & 1 & 0 \\ 0 & 1 & 2 & 3 & 2 \\ 1 & 1 & 1 & 0 & 1 \\ 3 & 1 & 0 & 1 & 1 \end{array} $$ a. Is the distribution of \(x\), the number of DVDs in a household, symmetric or skewed? Explain. b. Guess the value of the mode, the value of \(x\) that occurs most frequently. c. Calculate the mean, median, and mode for these measurements. d. Draw a relative frequency histogram for the data set. Locate the mean, median, and mode along the horizontal axis. Are your answers to parts a and b correct?

Here are the ages of 50 pennies from Exercise 1.45 and data set EX0145. The data have been sorted from smallest to largest. $$ \begin{array}{rrrrrrrrrr} 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 1 & 1 & 1 & 1 & 1 & 2 & 2 \\ 2 & 3 & 3 & 3 & 4 & 4 & 5 & 5 & 5 & 5 \\ 6 & 8 & 9 & 9 & 10 & 16 & 17 & 17 & 19 & 19 \\ 19 & 20 & 20 & 21 & 22 & 23 & 25 & 25 & 28 & 36 \end{array} $$ a. What is the average age of the pennies? b. What is the median age of the pennies? c. Based on the results of parts a and b, how would you describe the age distribution of these 50 pennies? d. Construct a box plot for the data set. Are there any outliers? Does the box plot confirm your description of the distribution's shape?

To estimate the amount of lumber in a tract of timber, an owner decided to count the number of trees with diameters exceeding 12 inches in randomly selected 50 -by-50foot squares. Seventy 50 -by-50-foot squares were chosen, and the selected trees were counted in each tract. The data are listed here: $$ \begin{array}{rrrrrrrrrr} 7 & 8 & 7 & 10 & 4 & 8 & 6 & 8 & 9 & 10 \\ 9 & 6 & 4 & 9 & 10 & 9 & 8 & 8 & 7 & 9 \\ 3 & 9 & 5 & 9 & 9 & 8 & 7 & 5 & 8 & 8 \\ 10 & 2 & 7 & 4 & 8 & 5 & 10 & 7 & 7 & 7 \\ 9 & 6 & 8 & 8 & 8 & 7 & 8 & 9 & 6 & 8 \\ 6 & 11 & 9 & 11 & 7 & 7 & 11 & 7 & 9 & 13 \\ 10 & 8 & 8 & 5 & 9 & 9 & 8 & 5 & 9 & 8 \end{array} $$ a. Construct a relative frequency histogram to describe the data. b. Calculate the sample mean \(\bar{x}\) as an estimate of \(\mu,\) the mean number of timber trees for all 50 -by-50-foot squares in the tract. c. Calculate \(s\) for the data. Construct the intervals \(\bar{x} \pm\) \(s, \bar{x} \pm 2 s\), and \(\bar{x} \pm 3 s\). Calculate the percentage of squares falling into each of the three intervals, and compare with the corresponding percentages given by the Empirical Rule and Tchebysheff's Theorem.

A random sample of 100 foxes was examined by a team of veterinarians to determine the prevalence of a particular type of parasite. Counting the number of parasites per fox, the veterinarians found that 69 foxes had no parasites, 17 had one parasite, and so on. A frequency tabulation of the data is given here: $$ \begin{array}{l|rrrrrrrrr} \text { Number of Parasites, } x & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline \text { Number of Foxes, } f & 69 & 17 & 6 & 3 & 1 & 2 & 1 & 0 & 1 \end{array} $$ a. Construct a relative frequency histogram for \(x\), the number of parasites per fox. b. Calculate \(\bar{x}\) and \(s\) for the sample. c. What fraction of the parasite counts fall within two standard deviations of the mean? Within three standard deviations? Do these results agree with Tchebysheff's Theorem? With the Empirical Rule?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free