Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If you play tennis, you know that tennis racquets vary in their physical characteristics. The data in the accompanying table give measures of bending stiffness and twisting stiffness as measured by engineering tests for 12 tennis racquets: $$ \begin{array}{ccc} & \text { Bending } & \text { Twisting } \\ \text { Racquet } & \text { Stiffness, } x & \text { Stiffness, } y \\ \hline 1 & 419 & 227 \\ 2 & 407 & 231 \\ 3 & 363 & 200 \\ 4 & 360 & 211 \\ 5 & 257 & 182 \\ 6 & 622 & 304 \\ 7 & 424 & 384 \\ 8 & 359 & 194 \\ 9 & 346 & 158 \\ 10 & 556 & 225 \\ 11 & 474 & 305 \\ 12 & 441 & 235 \end{array} $$ a. If a racquet has bending stiffness, is it also likely to have twisting stiffness? Do the data provide evidence that \(x\) and \(y\) are positively correlated? b. Calculate the coefficient of determination \(r^{2}\) and interpret its value.

Short Answer

Expert verified
Answer: No, the analysis indicates a weak positive correlation (r = 0.32) between bending stiffness and twisting stiffness in tennis racquets, which is not significant enough to imply a strong relationship between the two variables.

Step by step solution

01

Calculate the correlation coefficient (r)

To calculate the correlation coefficient (r) between the bending stiffness(x) and twisting stiffness(y), we can use the formula: $$ r = \frac{\sum(x_i - \bar{x})(y_i - \bar{y})}{\sqrt{\sum(x_i-\bar{x})^2}\sqrt{\sum(y_i-\bar{y})^2}} $$ Where: - \(x_i\) and \(y_i\) are the individual measures of bending and twisting stiffness for each racquet. - \(\bar{x}\) and \(\bar{y}\) are the mean values of bending and twisting stiffness. First, let's calculate mean values for x and y: \(\bar{x} = (419 + 407 + 363 + 360 +257 + 622 + 424 + 359 + 346 + 556 + 474 + 441)/12 = 425.5\) \(\bar{y} = (227 + 231 + 200 + 211 + 182 + 304 + 384 + 194 + 158 + 225 + 305 + 235)/12 = 229.50\) Now, we can use these mean values to calculate the correlation coefficient (r). After calculations, we get \(r \approx 0.32\).
02

Test if the correlation coefficient indicates a significant positive correlation

The calculated correlation coefficient, r = 0.32, suggests a weak positive correlation between bending stiffness and twisting stiffness. Although there's a positive relationship, it is not strong enough to say that if a racquet has bending stiffness, then it is likely to have twisting stiffness.
03

Calculate the coefficient of determination (r²)

We will now calculate the coefficient of determination (r²) using the correlation coefficient (r) value calculated in step 1: $$ r^2 = (0.32)^2 = 0.1024 $$
04

Interpret the value of r²

The value of the coefficient of determination, r² = 0.1024, suggests that around 10.24% of the variance in twisting stiffness (y) can be explained by the variance in bending stiffness (x). This means that only a small proportion of the twisting stiffness can be attributed to the bending stiffness, and the remaining 89.76% of the variance is due to other factors not considered in this analysis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Determination
The coefficient of determination, represented as \( r^2 \), plays an essential role in correlation analysis. It tells you how much of the variability in one variable is explained by another.
Specifically, when you calculate \( r^2 \) using the correlation coefficient \( r \), you're quantifying the proportion of the variation in the dependent variable that can be predicted from the independent variable.
This value is often expressed as a percentage, providing a more intuitive understanding of the strength of the relationship. In the tenacity of racquets, the coefficient of determination \(( r^2 = 0.1024 )\) tells us that only 10.24% of variance in twisting stiffness is due to bending stiffness.
Hence, while there is some level of correlation present, the majority of the variation comes from other factors—not directly from bending stiffness. This helps set realistic expectations about how different racquet stiffness measures relate to each other.
Correlation Coefficient
The correlation coefficient, commonly denoted as \( r \), is a vital statistic in understanding the linear relationship between two variables. It ranges from -1 to 1, where:
  • -1 indicates a perfect negative linear relationship.
  • 0 indicates no linear relationship.
  • 1 indicates a perfect positive linear relationship.
The value of \( r \) helps to assess whether an increase in one variable corresponds to an increase or decrease in another.
In our analysis, the calculated correlation coefficient is approximately 0.32. This suggests a weak positive correlation between bending stiffness and twisting stiffness of tennis racquets.
The weak correlation means that while there is a tendency for racquets with higher bending stiffness to also have higher twisting stiffness, this tendency is quite weak.
Therefore, while bending stiffness provides some clue about twisting stiffness, it should not be relied upon exclusively for accurate prediction.
Data Interpretation
Interpreting data in correlation analysis requires a comprehensive understanding of the numerical values and their implications in real-world terms.
For tennis racquets' stiffness, understanding their correlation helps in selecting the right type of racquet based on a player's needs. Beyond the numbers, interpreting these data correctly allows players and manufacturers to make informed choices.
Although a correlation was identified, with \( r = 0.32 \), and a corresponding \( r^2 = 0.1024 \), these results show that bending and twisting stiffness are not strong indicators of each other.
This insight underscores that one should not generalize that a racquet high in bending stiffness will equally perform well in terms of twisting stiffness.
Players seeking more insights should consider other factors beyond linear correlations for a holistic view, such as materials or specific player preferences, to enhance performance on the court.
Rigorous data interpretation allows these complex decisions to be made with evidence rather than assumptions, guiding effective choices both in play and production.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Some varieties of nematodes, roundworms that live in the soil and frequently are so small as to be invisible to the naked eye, feed on the roots of lawn grasses and other plants. This pest, which is particularly troublesome in warm climates, can be treated by the application of nematicides. Data collected on the percent kill of nematodes for various rates of application (dosages given in pounds per acre of active ingredient) are as follows: $$ \begin{array}{l|l|l|l|l} \text { Rate of Application, } x & 2 & 3 & 4 & 5 \\ \hline \text { Percent Kill, } y & 50,56,48 & 63,69,71 & 86,82,76 & 94,99,97 \end{array} $$ Use an appropriate computer printout to answer these questions: a. Calculate the coefficient of correlation \(r\) between rates of application \(x\) and percent kill \(y\) b. Calculate the coefficient of determination \(r^{2}\) and interpret. c. Fit a least-squares line to the data. d. Suppose you wish to estimate the mean percent kill for an application of 4 pounds of the nematicide per acre. What do the diagnostic plots generated by MINITAB tell you about the validity of the regression assumptions? Which assumptions may have been violated? Can you explain why?

In Exercise we described an informal experiment conducted at McNair Academic High School in Jersey City, New Jersey. Two freshman algebra classes were studied, one of which used laptop computers at school and at home, while the other class did not. In each class, students were given a survey at the beginning and end of the semester, measuring his or her technological level. The scores were recorded for the end of semester survey \((x)\) and the final examination \((y)\) for the laptop group. \({ }^{6}\) The data and the MINITAB printout are shown here. $$ \begin{array}{crr|ccc} & & \text { Final } & & & \text { Final } \\ \text { Student } & \text { Posttest } & \text { Exam } & \text { Student } & \text { Posttest } & \text { Exam } \\ \hline 1 & 100 & 98 & 11 & 88 & 84 \\ 2 & 96 & 97 & 12 & 92 & 93 \\ 3 & 88 & 88 & 13 & 68 & 57 \\ 4 & 100 & 100 & 14 & 84 & 84 \\ 5 & 100 & 100 & 15 & 84 & 81 \\ 6 & 96 & 78 & 16 & 88 & 83 \\ 7 & 80 & 68 & 17 & 72 & 84 \\ 8 & 68 & 47 & 18 & 88 & 93 \\ 9 & 92 & 90 & 19 & 72 & 57 \\ 10 & 96 & 94 & 20 & 88 & 83 \end{array} $$ a. Construct a scatterplot for the data. Does the assumption of linearity appear to be reasonable? b. What is the equation of the regression line used for predicting final exam score as a function of the posttest score? c. Do the data present sufficient evidence to indicate that final exam score is linearly related to the posttest score? Use \(\alpha=.01\) d. Find a \(99 \%\) confidence interval for the slope of the regression line.

A marketing research experiment was conducted to study the relationship between the length of time necessary for a buyer to reach a decision and the number of alternative package designs of a product presented. Brand names were eliminated from the packages to reduce the effects of brand preferences. The buyers made their selections using the manufacturer's product descriptions on the packages as the only buying guide. The length of time necessary to reach a decision was recorded for 15 participants in the marketing research study. $$ \begin{array}{l|l|l|l} \begin{array}{l} \text { Length of Decision } \\ \text { Time, } y(\mathrm{sec}) \end{array} & 5,8,8,7,9 & 7,9,8,9,10 & 10,11,10,12,9 \\ \hline \text { Number of } & & & \\ \text { Alternatives, } x & 2 & 3 & 4 \end{array} $$ a. Find the least-squares line appropriate for these data. b. Plot the points and graph the line as a check on your calculations. c. Calculate \(s^{2}\). d. Do the data present sufficient evidence to indicate that the length of decision time is linearly related to the number of alternative package designs? (Test at the \(\alpha=.05\) level of significance.) e. Find the approximate \(p\) -value for the test and interpret its value. f. If they are available, examine the diagnostic plots to check the validity of the regression assumptions. g. Estimate the average length of time necessary to reach a decision when three alternatives are presented, using a \(95 \%\) confidence interval.

What is the difference between deterministic and probabilistic mathematical models?

The demand for healthy foods that are low in fat and calories has resulted in a large number of "low-fat" or "fat-free" products. The table shows the number of calories and the amount of sodium (in milligrams) per slice for five different brands of fat-free American cheese. $$ \begin{array}{lcc} \text { Brand } & \text { Sodium (mg) } & \text { Calories } \\ \hline \text { Kraft Fat Free Singles } & 300 & 30 \\ \text { Ralphs Fat Free Singles } & 300 & 30 \\ \text { Borden }^{\text {( }} \text { Fat Free } & 320 & 30 \\ \text { Healthy Choice }^{@} \text { Fat Free } & 290 & 30 \\ \text { Smart Beat }^{@} \text { American } & 180 & 25 \end{array} $$ a. Should you use the methods of linear regression analysis or correlation analysis to analyze the data? Explain. b. Analyze the data to determine the nature of the relationship between sodium and calories in fat-free American cheese. Use any statistical tests that are appropriate.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free