Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The demand for healthy foods that are low in fat and calories has resulted in a large number of "low-fat" or "fat-free" products. The table shows the number of calories and the amount of sodium (in milligrams) per slice for five different brands of fat-free American cheese. $$ \begin{array}{lcc} \text { Brand } & \text { Sodium (mg) } & \text { Calories } \\ \hline \text { Kraft Fat Free Singles } & 300 & 30 \\ \text { Ralphs Fat Free Singles } & 300 & 30 \\ \text { Borden }^{\text {( }} \text { Fat Free } & 320 & 30 \\ \text { Healthy Choice }^{@} \text { Fat Free } & 290 & 30 \\ \text { Smart Beat }^{@} \text { American } & 180 & 25 \end{array} $$ a. Should you use the methods of linear regression analysis or correlation analysis to analyze the data? Explain. b. Analyze the data to determine the nature of the relationship between sodium and calories in fat-free American cheese. Use any statistical tests that are appropriate.

Short Answer

Expert verified
Answer: The nature of the relationship between sodium content and calories within fat-free American cheese products across different brands is weakly positive, with a correlation coefficient of approximately 0.3034. This suggests that as sodium content increases, calories tend to increase slightly, but the strength of this relationship is weak, and there can be considerable variability among different brands.

Step by step solution

01

a. Appropriate Method to Analyze the Data

To determine the appropriate method for analyzing the data, let's see what linear regression analysis and correlation analysis provide us: 1. Linear Regression Analysis: this method allows us to predict the value of one variable based on the value of another variable. In this case, we would predict calories based on sodium content. 2. Correlation Analysis: this method determines the strength and direction of the relationship between two variables. In this case, we want to measure the relationship between sodium content and calories within fat-free American cheese. As we are interested in understanding the nature of the relationship between sodium and calories, we should use correlation analysis.
02

b. Analyzing the Data

Step 1: Calculate the mean of each variable To perform correlation analysis, we first need to determine the mean value for sodium and calories: Mean of Sodium: (300 + 300 + 320 + 290 + 180) / 5 = 1390 / 5 = 278 mg Mean of Calories: (30 + 30 + 30 + 30 + 25) / 5 = 145 / 5 = 29 kcal Step 2: Calculate the covariance Covariance measures the degree to which two variables move together. To calculate the covariance, we need to find each variable's deviation from the mean: $$ COV(X,Y) = \frac{\sum_{i=1}^{n}{(x_i-\bar{X})(y_i-\bar{Y})}}{n} $$ Using the table: $$ \begin{array}{lcccc} \text{Brand} & x_i (x_i-\bar{X}) & y_i (y_i-\bar{Y}) & (x_i-\bar{X})(y_i-\bar{Y})\\ \hline Kraft Fat Free Singles & 300 (22) & 30 (1) & 22\\ Ralphs Fat Free Singles & 300 (22) & 30 (1) & 22\\ Borden Fat Free & 320 (42) & 30 (1) & 42\\ Healthy Choice Fat Free & 290 (12) & 30 (1) & 12\\ Smart Beat American & 180 (-98) & 25 (-4) & 392 \\ \end{array} $$ Therefore, $$ COV(X,Y) = \frac{22 + 22 + 42 + 12 + 392}{5} = \frac{490}{5} = 98 $$ Step 3: Calculate the standard deviations of each variable The standard deviation is the measure of dispersion within a dataset. $$ \sigma_X = \sqrt{\frac{\sum_{i=1}^{n}{(x_i-\bar{X})^2}}{n}} $$ Therefore, $$ \sigma_X = \sqrt{\frac{22^2 + 22^2 + 42^2 + 12^2 + (-98)^2}{5}} $$ $$ \sigma_X = \sqrt{10,468} = 102.31 $$ $$ \sigma_Y = \sqrt{\frac{\sum_{i=1}^{n}{(y_i-\bar{Y})^2}}{n}} $$ Therefore, $$ \sigma_Y = \sqrt{\frac{1^2+1^2+1^2+1^2+(-4)^2}{5}} $$ $$ \sigma_Y =\sqrt{10} = 3.16 $$ Step 4: Calculate the correlation coefficient The correlation coefficient (r) measures the strength and direction of the relationship between two variables: $$ r = \frac{COV(X,Y)}{\sigma_X\sigma_Y} $$ Therefore, $$ r = \frac{98}{102.31 \times 3.16} = \frac{98}{322.68} = 0.3034 $$
03

Conclusion

We have computed the correlation coefficient (r) to be approximately 0.3034. This value indicates a weak positive relationship between sodium content and calories within these fat-free American cheese products. This suggests that, generally, as the sodium content increases, the calories tend to increase slightly as well; but the relationship is not very strong, and there can be considerable variability among different brands.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression Analysis
Linear regression analysis is a statistical method used to understand the relationship between two continuous variables. It helps in predicting the value of one variable based on the value of another. In a linear regression, the goal is to find a linear equation that best predicts the dependent variable from the independent variable. This equation is typically in the form of \( y = mx + c \), where \( m \) is the slope and \( c \) is the intercept.
Although linear regression is powerful, its main use is to predict one variable when the other is known. It can also help identify whether a relationship between two variables is significant, but it's not always the most suited for simply establishing the strength or direction of a relationship without prediction in mind. In the context of sodium and calories in cheese, we are more focused on understanding the association between these variables rather than making an exact prediction.
This is why, for the cheese study, correlation analysis is preferred — it focuses on the relationship itself rather than predicting values.
Covariance
Covariance is an important concept in statistics used to determine how two variables change together. If the two variables increase or decrease together, their covariance is positive. Conversely, if one increases when the other decreases, the covariance is negative. The formula for covariance between two variables \( X \) and \( Y \) is:
\[ COV(X,Y) = \frac{\sum_{i=1}^{n}{(x_i-\bar{X})(y_i-\bar{Y})}}{n} \]
In this equation, \( x_i \) and \( y_i \) are the individual data points for variables \( X \) and \( Y \), while \( \bar{X} \) and \( \bar{Y} \) are their respective means. Covariance can tell us about the direction of the linear relationship between variables, but not its strength or consistency. Thus, it lays foundational ground before computation of the correlation coefficient to better understand variable relationships.
For example, analyzing the sodium and calories in the cheese slices, we get a covariance of 98, indicating that there's a tendency for these variables to increase together. However, it doesn’t specify how strong the trend is, which is where correlation analysis steps in.
Standard Deviation
Standard deviation is a statistical measure that shows the amount of variation or dispersion in a set of data values. A low standard deviation indicates that the values tend to be very close to the mean, while a high standard deviation indicates that the values are spread out over a large range. For a variable \( X \), its standard deviation \( \sigma_X \) can be calculated as:
\[ \sigma_X = \sqrt{\frac{\sum_{i=1}^{n}{(x_i-\bar{X})^2}}{n}} \]
This formula involves calculating the square root of the average squared deviations from the mean \( \bar{X} \). This measure is particularly useful when used alongside other statistical metrics like covariance, as seen here with the cheese data, where standard deviations for sodium and calories were calculated.
By knowing these standard deviations, we can gain insight into the spread of sodium and calorie content across difference brands, which ultimately allows us to calculate the correlation coefficient and understand how consistent and reliable the observed relationships are.
Correlation Coefficient
The correlation coefficient, often represented as \( r \), is a statistical measure that describes the strength and direction of a linear relationship between two variables. Its value ranges from -1 to 1, where:
  • -1 indicates a perfect negative linear relationship,
  • 0 implies no linear relationship,
  • 1 indicates a perfect positive linear relationship.
The formula is:
\[ r = \frac{COV(X,Y)}{\sigma_X\sigma_Y} \]
This equation uses covariance and the product of the standard deviations of the two variables to yield \( r \). In practice, a value close to 1 indicates a strong positive correlation, whereas a value close to -1 suggests a strong negative correlation.
In the cheese example, \( r \) was calculated as approximately 0.3034. This positive but modest correlation suggests that higher sodium tends to come with slightly higher calories, although the relationship isn’t particularly strong. In essence, this metric allows us to both quantify and convey the potential linear association between sodium content and calorie levels in an understandable manner.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Six points have these coordinates: $$ \begin{array}{l|llllll} x & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline y & 5.6 & 4.6 & 4.5 & 3.7 & 3.2 & 2.7 \end{array} $$ a. Find the least-squares line for the data. b. Plot the six points and graph the line. Does the line appear to provide a good fit to the data points? c. Use the least-squares line to predict the value of \(y\) when \(x=3.5\) d. Fill in the missing entries in the MINITAB analysis of variance table. (Table)

The number of passes EX1242 completed and the total number of passing yards for Tom Brady, quarterback for the New England Patriots, were recorded for the 16 regular games in the 2006 football season. \({ }^{8}\) Week 6 was a bye and no data was reported. $$ \begin{array}{ccc} \text { Week } & \text { Completions } & \text { Total Yards } \\ \hline 1 & 11 & 163 \\ 2 & 15 & 220 \\ 3 & 31 & 320 \\ 4 & 15 & 188 \\ 5 & 16 & 140 \\ 6 & * & * \\ 7 & 18 & 195 \\ 8 & 29 & 372 \\ 9 & 20 & 201 \\ 10 & 24 & 253 \\ 11 & 20 & 244 \\ 12 & 22 & 267 \\ 13 & 27 & 305 \\ 14 & 12 & 78 \\ 15 & 16 & 109 \\ 16 & 28 & 249 \\ 17 & 15 & 225 \end{array} $$ a. What is the least-squares line relating the total passing yards to the number of pass completions for Tom Brady? b. What proportion of the total variation is explained by the regression of total passing yards \((y)\) on the number of pass completions \((x) ?\) c. If they are available, examine the diagnostic plots to check the validity of the regression assumptions.

You are given five points with these coordinates: $$ \begin{array}{c|rrrrrrr} x & -2 & -1 & 0 & 1 & 2 \\ \hline y & 1 & 1 & 3 & 5 & 5 \end{array} $$ a. Use the data entry method on your scientific or graphing calculator to enter the \(n=5\) observations. Find the sums of squares and cross-products, \(S_{x x} S_{x y},\) and \(S_{y y}\) b. Find the least-squares line for the data. c. Plot the five points and graph the line in part b. Does the line appear to provide a good fit to the data points? d. Construct the ANOVA table for the linear regression.

An agricultural experimenter, investigating the effect of the amount of nitrogen \(x\) applied in 100 pounds per acre on the yield of oats \(y\) measured in bushels per acre, collected the following data: $$ \begin{array}{l|llll} x & 1 & 2 & 3 & 4 \\ \hline y & 22 & 38 & 57 & 68 \\ & 19 & 41 & 54 & 65 \end{array} $$ a. Find the least-squares line for the data. b. Construct the ANOVA table. c. Is there sufficient evidence to indicate that the yield of oats is linearly related to the amount of nitrogen applied? Use \(\alpha=.05 .\) d. Predict the expected yield of oats with \(95 \%\) confidence if 250 pounds of nitrogen per acre are applied.e. Estimate the average increase in yield for an increase of 100 pounds of nitrogen per acre with \(99 \%\) confidence. f. Calculate \(r^{2}\) and explain its significance in terms of predicting \(y\), the yield of oats.

G. W. Marino investigated the variables related to a hockey player's ability to make a fast start from a stopped position. \({ }^{11}\) In the experiment, each skater started from a stopped position and attempted to move as rapidly as possible over a 6-meter distance. The correlation coefficient \(r\) between a skater's stride rate (number of strides per second) and the length of time to cover the 6 -meter distance for the sample of 69 skaters was -.37 . a. Do the data provide sufficient evidence to indicate a correlation between stride rate and time to cover the distance? Test using \(\alpha=.05 .\) b. Find the approximate \(p\) -value for the test. c. What are the practical implications of the test in part a?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free