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Consider two Bernoulli distributions with unknown parameters \(p_{1}\) and \(p_{2}\). If \(Y\) and \(Z\) equal the numbers of successes in two independent random samples, each of size \(n\), from the respective distributions, determine the mles of \(p_{1}\) and \(p_{2}\) if we know that \(0 \leq p_{1} \leq p_{2} \leq 1\)

Short Answer

Expert verified
The mles of \(p_{1}\) and \(p_{2}\) when \(0 \leq p_{1} \leq p_{2} \leq 1\) are \(\hat{p_{1}} = min(Y, Z)/n\), and \(\hat{p_{2}} = max(Y, Z)/n\).

Step by step solution

01

Understand the Maximum Likelihood Estimation (MLE)

The Maximum Likelihood Estimation (MLE) is a statistical method used to estimate the parameters of a model. It works by maximizing the likelihood function which is the probability of the observed data given the parameters.
02

Apply MLE to the Given Bernoulli Distributions

To apply MLE, consider each Bernoulli distribution separately at first. For each distribution, the likelihood function is given by \(L(p_{i}|Y) = {n \choose Y} p_{i}^Y (1-p_{i})^{n-Y}\), where \(i \in {1,2}\), n is the number of trials and Y is the observed number of successes. The mle of \(p_{i}\) is obtained by taking the derivative of the log likelihood function with respect to \(p_{i}\), setting it to zero and solving for \(p_{i}\). That is, \( \hat{p_{i}} = Y/n \). This is under the assumption that \(0 \leq p_{i} \leq 1\).
03

Integrate the Condition $0 \leq p_{1} \leq p_{2} \leq 1$ Into the Problem

With the condition $0 \leq p_{1} \leq p_{2} \leq 1$, solutions will be subjected to this inequality. If the maximum likelihood estimate of \(p_{1}\), \(\hat{p_{1}} = Y/n\), is greater than the maximum likelihood estimate of \(p_{2}\), \(\hat{p_{2}} = Z/n\), then this falls outside the restriction and one would have to adjust for this by setting \(p_{1}\) to equal \(p_{2}\), that is, the lower bound \(p_{2}\), hence becoming \(p_{2} \leq \hat{p_{2}} \leq 1\). Thus, the mle of \(p_{1}\) becomes \(\hat{p_{1}} = min(Y, Z)/n\), and the mle of \(p_{2}\) becomes \(\hat{p_{2}} = max(Y, Z)/n\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli Distributions
Bernoulli distributions are a fundamental concept in probability theory and statistics, representing processes that have exactly two possible outcomes, often termed as 'success' and 'failure'. Examples include flipping a coin (heads or tails) or checking if a light bulb works (on or off). For a Bernoulli distribution, there is a single parameter, denoted as \( p \), which is the probability of success on each trial.

The distribution is mathematically expressed as:
  • \( P(success) = p \)
  • \( P(failure) = 1 - p \)
This simple distribution forms the building block for more complex models and is instrumental in teaching fundamental concepts of variability and probability.
Statistical Method
Statistical methods are a collection of techniques used for collecting, analyzing, interpreting, and presenting empirical data. In the context of Bernoulli distributions or any other statistical model, these methods help identify patterns, test hypotheses, and make predictions based on sample data.

Maximum Likelihood Estimation (MLE) is one such statistical method prized for its utility in estimating unknown parameters of a probability distribution. By selecting the parameter values that make the observed data most probable, MLE provides a way to model the underlying distribution of data points, fitting our understanding of the phenomena being studied to the actual observed outcomes.
Parameter Estimation
Parameter estimation is the process of using sample data to estimate the parameters of the probability distribution that generated the data. In a Bernoulli distribution, the parameter \( p \) represents the probability of occurrence of the event of interest. To estimate this probability, techniques such as the Maximum Likelihood Estimation (MLE) are employed.

The premise is to find the value of \( p \) that would make the observed data most likely to occur. With Bernoulli trials, where each trial is independent, the likelihood of observing a specific set of outcomes has a direct mathematical expression. Through MLE, we obtain a 'point estimate', offering a single best guess for the parameter sought after. In the case of the Bernoulli trials in our exercise, the parameters \(p_1\) and \(p_2\) are estimated using the formula \( \hat{p_i} = Y/n \), where \(Y\) is the number of successes and \(n\) is the total number of trials.
Likelihood Function
The likelihood function is a key element in the process of parameter estimation through Maximum Likelihood Estimation. It represents the probability of the observed sample data given a set of parameters. For Bernoulli distributions, the likelihood of observing \(Y\) successes out of \(n\) trials when the probability of success is \(p\) is given by the binomial formula:

\( L(p|Y) = {n \choose Y} p^Y (1-p)^{n-Y} \).

MLE seeks the value of \(p\) that maximizes this function. In practice, we often work with the logarithm of the likelihood function, as it simplifies the calculations (turns products into sums) and reaches its maximum at the same parameter values as the original likelihood function. By taking the derivative of the log-likelihood with respect to \(p\), setting it to zero, and solving, we're able to find the estimate that makes the observed data most probable. This methodical approach reinforces the robustness of statistical methods in making informed inferences from sample data.

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Most popular questions from this chapter

Let \(X_{1}, \ldots, X_{n}\) and \(Y_{1}, \ldots, Y_{m}\) be independent random samples from the distributions \(N\left(\theta_{1}, \theta_{3}\right)\) and \(N\left(\theta_{2}, \theta_{4}\right)\), respectively. (a) Show that the likelihood ratio for testing \(H_{0}: \theta_{1}=\theta_{2}, \theta_{3}=\theta_{4}\) against all alternatives is given by $$ \begin{aligned} &\qquad\left[\sum_{1}^{n}\left(x_{i}-\bar{x}\right)^{2} / n\right]^{n / 2}\left[\sum_{1}^{m}\left(y_{i}-\bar{y}\right)^{2} / m\right]^{m / 2} \\ &\left\\{\left[\sum_{1}^{n}\left(x_{i}-u\right)^{2}+\sum_{1}^{m}\left(y_{i}-u\right)^{2}\right] /(m+n)\right\\}^{(n+m) / 2} \end{aligned} $$ (b) Show that the likelihood ratio test for testing \(H_{0}: \theta_{3}=\theta_{4}, \theta_{1}\) and \(\theta_{2}\) unspecified, against \(H_{1}: \theta_{3} \neq \theta_{4}, \theta_{1}\) and \(\theta_{2}\) unspecified, can be based on the random variable $$ F=\frac{\sum_{1}^{n}\left(X_{i}-\bar{X}\right)^{2} /(n-1)}{\sum_{1}^{m}\left(Y_{i}-\bar{Y}\right)^{2} /(m-1)} $$

Given \(f(x ; \theta)=1 / \theta, 00\), formally compute the reciprocal of $$ n E\left\\{\left[\frac{\partial \log f(X: \theta)}{\partial \theta}\right]^{2}\right\\} $$ Compare this with the variance of \((n+1) Y_{n} / n\), where \(Y_{n}\) is the largest observation of a random sample of size \(n\) from this distribution. Comment.

Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from a \(N(0, \theta)\) distribution. We want to estimate the standard deviation \(\sqrt{\theta}\). Find the constant \(c\) so that \(Y=\) \(c \sum_{i=1}^{n}\left|X_{i}\right|\) is an unbiased estimator of \(\sqrt{\theta}\) and determine its efficiency.

Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from a \(N\left(\theta, \sigma^{2}\right)\) distribution, where \(\sigma^{2}\) is fixed but \(-\infty<\theta<\infty\) (a) Show that the mle of \(\theta\) is \(\bar{X}\). (b) If \(\theta\) is restricted by \(0 \leq \theta<\infty\), show that the mle of \(\theta\) is \(\widehat{\theta}=\max \\{0, \bar{X}\\}\).

A machine shop that manufactures toggle levers has both a day and a night shift. A toggle lever is defective if a standard nut cannot be screwed onto the threads. Let \(p_{1}\) and \(p_{2}\) be the proportion of defective levers among those manufactured by the day and night shifts, respectively. We shall test the null hypothesis, \(H_{0}: p_{1}=p_{2}\), against a two-sided alternative hypothesis based on two random samples, each of 1000 levers taken from the production of the respective shifts. Use the test statistic \(Z^{*}\) given in Example \(6.5 .3 .\) (a) Sketch a standard normal pdf illustrating the critical region having \(\alpha=0.05\). (b) If \(y_{1}=37\) and \(y_{2}=53\) defectives were observed for the day and night shifts, respectively, calculate the value of the test statistic and the approximate \(p-\) value (note that this is a two-sided test). Locate the calculated test statistic on your figure in part (a) and state your conclusion. Obtain the approximate \(p\) -value of the test.

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