Chapter 6: Problem 11
Let \(n\) independent trials of an experiment be such that \(x_{1}, x_{2}, \ldots, x_{k}\) are the respective numbers of times that the experiment ends in the mutually exclusive and exhaustive events \(C_{1}, C_{2}, \ldots, C_{k} .\) If \(p_{i}=P\left(C_{i}\right)\) is constant throughout the \(n\) trials, then the probability of that particular sequence of trials is \(L=p_{1}^{x_{1}} p_{2}^{x_{2}} \cdots p_{k}^{x_{k}}\). (a) Recalling that \(p_{1}+p_{2}+\cdots+p_{k}=1\), show that the likelihood ratio for testing \(H_{0}: p_{i}=p_{i 0}>0, i=1,2, \ldots, k\), against all alternatives is given by $$ \Lambda=\prod_{i=1}^{k}\left(\frac{\left(p_{i 0}\right)^{x_{i}}}{\left(x_{i} / n\right)^{x_{i}}}\right) $$ (b) Show that $$ -2 \log \Lambda=\sum_{i=1}^{k} \frac{x_{i}\left(x_{i}-n p_{i 0}\right)^{2}}{\left(n p_{i}^{\prime}\right)^{2}} $$ where \(p_{i}^{\prime}\) is between \(p_{i 0}\) and \(x_{i} / n\). Hint: Expand \(\log p_{i 0}\) in a Taylor's series with the remainder in the term involving \(\left(p_{i 0}-x_{i} / n\right)^{2}\). (c) For large \(n\), argue that \(x_{i} /\left(n p_{i}^{\prime}\right)^{2}\) is approximated by \(1 /\left(n p_{i 0}\right)\) and hence \(-2 \log \Lambda \approx \sum_{i=1}^{k} \frac{\left(x_{i}-n p_{i 0}\right)^{2}}{n p_{i 0}}\) when \(H_{0}\) is true. Theorem \(6.5 .1\) says that the right-hand member of this last equation defines a statistic that has an approximate chi-square distribution with \(k-1\) degrees of freedom. Note that dimension of \(\Omega-\) dimension of \(\omega=(k-1)-0=k-1\)
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